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Table of Contents Chapter 15: Solutions.

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Presentation on theme: "Table of Contents Chapter 15: Solutions."— Presentation transcript:

1 Table of Contents Chapter 15: Solutions

2 Some Helpful Definitions
Solutions: Basic Concepts Some Helpful Definitions solute –dissolved substance, may change phase, lesser amount solvent – dissolving, no phase change, greater amount soluble – the ability of a solute to dissolve. insoluble – a solute unable to dissolve. predicting solubility: “like dissolves like.”

3 Concentrated Versus Dilute
Solutions: Basic Concepts Concentrated Versus Dilute Chemists never apply the terms strong and weak to solution concentrations. These terms are used to describe the chemical behavior of acids and bases. Instead, use the terms concentrated and dilute.

4 Percent by mass or volume Percent by volume
Solutions: Basic Concepts Concentration Concentration units: Percent by mass or volume Percent by volume Molality Molarity

5 Percent by mass = mass of solute x 100 mass of solution
Solutions: Additional Concepts Concentration Percent by mass = mass of solute x 100 mass of solution Calculate the percent by mass of 2.56 g NaCl dissolved in 74 g water. Mass solute: g Mass solution: g NaCl + 74 g H2O = g Percent by mass = g x 100 = 3.34 % 76.56 g

6 Percent by mass = mass of solute x 100 mass of solution
TRY IT OUT! Concentration Percent by mass = mass of solute x 100 mass of solution Calculate the percent by mass of 4.95 g NaCl dissolved in 53 g water. Mass solute: g Mass solution: g NaCl + 53 g H2O = g Percent by mass = g x 100 = 8.54 % 57.95 g

7 Percent by volume = volume of solute x 100 volume of solution
Solutions: Additional Concepts Concentration Percent by volume = volume of solute x 100 volume of solution Calculate the percent by volume of 26 mL methanol dissolved in 71 mL water. Volume solute: 26 mL Volume solution: 26 mL methanol + 71 ml H2O = 97 mL Percent by mass = mL x 100 = 26.8 % 97 mL

8 Molality (m) = moles of solute kg solvent
Solutions: Additional Concepts Concentration Molality (m) = moles of solute kg solvent What is the molality of 17.1 g NaCl in g H2O? Moles solute: g NaCl 1 mol NaCl = .2926 mol NaCl 58.44 g NaCl Kilograms solvent: g H2O = kg H2O Molality = .2926 mol = 2.89 m .1014 kg

9 Molality (m) = moles of solute kg solvent
TRY IT OUT! Concentration Molality (m) = moles of solute kg solvent What is the molality of 21.3 g NaCl in 94.1 g H2O? Moles solute: g NaCl 1 mol NaCl = .3645 mol NaCl 58.44 g NaCl Kilograms solvent: g H2O = kg H2O Molality = .3645 mol = 3.87 m .0941 kg

10 Molarity (M) = moles of solute liters of solution
Solutions: Additional Concepts Concentration Molarity (M) = moles of solute liters of solution What is the molarity of 1.1 mol KCl in 1.8 L solution? Moles solute: 1.1 mol Liters solution: 1.8 L Molarity = 1.1 mol = .61 M = .61 mol/L 1.8 L

11 Molarity (M) = moles of solute liters of solution
TRY IT OUT! Concentration Molarity (M) = moles of solute liters of solution What is the molarity of 2.4 mol KCl in .9 L solution? Moles solute: 2.4 mol Liters solution: .9 L Molarity = 2.4 mol = 2.67 M = 2.67 mol/L .9 L

12 Molarity (M) as a conversion factor
Solutions: Additional Concepts Concentration Molarity (M) as a conversion factor How many grams of solute are in 68.0 mL M KOH? 68.0 mL KOH 1 L mol KOH 56.11 g KOH 1000 mL 1 L 1 mol KOH = .1278 g KOH Use molarity as a conversion factor

13 Molarity (M) as a conversion factor
TRY IT OUT! Concentration Molarity (M) as a conversion factor How many grams of solute are in 52.0 mL 0.12 M KOH? 52.0 mL KOH 1 L .12 mol KOH 56.11 g KOH 1000 mL 1 L 1 mol KOH = .350 g KOH Use molarity as a conversion factor

14 Dilutions M1V1 = M2V2 (3.65 M NaOH) (V1) = (.95 M NaOH) (125 mL NaOH)
Solutions: Additional Concepts Dilutions M1V1 = M2V2 How many millimeters of 3.65 M NOH is needed to make 125 mL of 0.95 M NaOH solution? (3.65 M NaOH) (V1) = (.95 M NaOH) (125 mL NaOH) (V1) = 36.1 mL NaOH

15 Dilutions M1V1 = M2V2 (2.75 M HCl) (V1) = (.65 M HCl) (80 mL HCl) (V1)
TRY IT OUT! Dilutions M1V1 = M2V2 How many millimeters of 2.75 M HCl is needed to make 80 mL of 0.65 M HCl solution? (2.75 M HCl) (V1) = (.65 M HCl) (80 mL HCl) (V1) = 18.9 mL HCl

16 Your time! Worksheet: Do not do #4, #7, #10
Answers are posted at the front – CHECK IT! Do as much as you can - due tomorrow at the beginning of class


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