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Lecture 1-2 Time and Space of DTM
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Model Multitape TM with write-only output.
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Time of DTM
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Time Bound M is said to have a time bound t(n) if for every x with |x| < n, TimeM(x) < max {n+1, t(n)}
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Theorem For any multitape DTM M, there exists a one-tape DTM M’ to simulate M within time TimeM’(x) < c + (TimeM(x)) c is a constant. 2
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Complexity Class A language L has a (deterministic) time-complexity t(n) if there is a multitape DTM M accepting L, with time bound t(n). DTIME(t(n)) = {L | L has a time bound t(n)}
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Linear Speed Up
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1--m Bee dance 3m q
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1--m a b c d e f initial 3m q
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1--m a b c d e f 1st bee dance 3m c d q
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1--m a b c d e f 1st bee dance 3m c d e f q
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1--m a b c d e f 1st bee dance 3m c d e f q
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1--m a b c d e f 1st bee dance 3m a b c d e f q
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1--m a b c d e f 3m a’ b’ c’ d’ e’ f’ p
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1--m a b c’ d’ e f 2nd bee dance 3m a’ b’ e’ f’ p
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1--m a b c’ d’ e’ f’ 2nd bee dance 3m a’ b’ p
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1--m a b c’ d’ e’ f’ 2nd bee dance 3m a’ b’ p
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1--m a’ b’ c’ d’ e’ f’ 2nd bee dance 3m p
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1--m a’ b’ c’ d’ e’ f’ initial 3m p
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Model Independent Classes
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Space SpaceM(x) = total # of cells that M visits on all working (storage) tapes during the computation on input x. If M is a multitape DTM, then the working tapes do not include the input tape and the write-only output tape.
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Multi-tape DTM Input tape (read only) working tapes Output tape
(possibly, write only)
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Space Bound A DTM with k work tapes is said to have a space bound s(n) if for any input x with |x| < n, SpaceM(x) < max{k, s(n)}.
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Time and Space For any DTM with k work tapes,
SpaceM(x) < k (TimeM(x) + 1)
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Complexity Classes A language L has a space complexity s(n) if it is accepted by a multitape with write-only output tape DTM with space bound s(n). DSPACE(s(n)) = {L | L has space complexity s(n)}
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Tape Compression Theorem
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1--m 3m
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Model Independent Classes
P = U c>0 DTIME(n ) EXP = U c > 0 DTIME(2 ) EXPOLY = U c > 0 DTIME(2 ) PSPACE = U c > 0 DSPACE(n ) c cn c n c
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Extended Church-Turing Thesis
A function computable in polynomial time in any reasonable computational model using a reasonable time complexity measure is computable by a DTM in polynomial time.
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P PSPACE SpaceM(x) < k (TimeM(x) + 1)
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PSPACE EXPOLY
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Input tape (read only) working tapes Output tape (possibly, write only)
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“Sufficiently large”
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A, B P imply A U B P
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A, B P imply AB P
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L P implies L* P
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All regular sets belong to P
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Space Hierarchy Theorem
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Space-constructible function
s(n) is fully space-constructible if there exists a DTM M such that for sufficiently large n and any input x with |x|=n, SpaceM(x) = s(n).
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Space Hierarchy If s2(n) is a fully space-constructible function,
s1(n)/s2(n) → 0 as n → infinity, s1(n) > log n, then DSPACE(s2(n)) DSPACE(s1(n)) ≠ Φ
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Time Hierarchy
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Time-constructible function
t(n) is fully time-constructible if there exists a DTM such that for sufficiently large n and any input x with |x|=n, TimeM(x) = t(n).
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Time Hierarchy If t1(n) > n+1, t2(n) is fully time-constructible,
t1(n) log t1(n) /t2(n) → 0 as n → infinity, then DTIME(t2(n)) DTIME(t1(n)) ≠ Φ
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P EXP Could you prove
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PSPACE≠EXP
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