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Probability Notes Math 309
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Some Definitions Experiment - means of making an observation
Sample Space (S) - set of all outcomes of an experiment listed in a mutually exclusive and exhaustive manner Event - subset of a sample space Simple Event - an event which can only happen in one way; (or can be thought of as a sample point - a one element subset of S)
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Since events are sets, we need to understand the basic set operations
Intersection everything in A and B Union everything in A or B or both Complement everything not in A
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You should be able to sketch Venn diagrams to describe the intersections, unions, & complements of sets. Note that these set operations obey the commutative, associative, and distributive laws
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DeMorgan’s Laws Convince yourself that these are reasonable with Venn diagrams!
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Another definition - A and B are mutually exclusive iff A B =
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Axioms of Probability (these are FACT, no proof needed!)
Let E represent an event, S the sample space, For pairwise mutually exclusive events, the probability of their union is the sum of their respective probabilities, i.e.
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Theorems (You should be able to prove these using the axioms and definitions.)
Thm The probability of the empty set is zero. Thm 1.2 – Let {A1, A2, ,An} be a mutually exclusive set of events. Then P(A1A2 An) = P(A1) + P(A2) P(An)
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Propositions (You should be able to prove these using the axioms and definitions.)
Let E and F be any two events. P(E) 1 If E is a subset of F, then P(E) P(F). For mutually exclusive events, P(E F) = P(E) + P(F)
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Theorems (You should be able to prove these using the axioms and definitions.)
Let E and F be any two events. Thm P( ) = 1 - P(E) Thm P(E F) = P(E) + P(F) - P(E F)
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Unions get complicated if events are not mutually exclusive!
P(A B C) = P(A) + P(B) + P(C) - P(A B) - P(A C) - P(B C) + P(A B C) B
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Let A and B be any two events.
More Theorems Let A and B be any two events. Thm 1.5- If A B, then P(B-A) = P(B AC) = P(B) – P(A) Corollary: If A is a subset of B, then P(A) <= P(B). Thm P(A) = P(A B) + P(A BC) (generalize)
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Sample Spaces with Equally Likely Outcomes
In an experiment where all simple events (sample points) are equally likely, one can find the probability of an event by counting two sets.
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Combinatorial Methods
Math 309
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Combinatorics Basic Principle of Counting Permutations Combinations
(a.k.a. Multiplication Principle) Permutations Permutations with indistinguishable objects Combinations
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Basic Counting Principle
If experiment 1 has m outcomes and experiment 2 has n outcomes, then there are m*n outcomes for both experiments. The principle can be generalized for r experiments. The number of outcomes of r experiments is the product of the number of outcomes of each experiment.
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We define experiment as a means of making an observation (e. g
We define experiment as a means of making an observation (e.g. flip a coin, choose a color). Each experiment could be making a choice from a different set.
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Permutations # of arrangements of one set, order matters
application of the basic counting principle where we return to the same set for the next selection P(n,r) = n!/(n-r)!
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Permutations with Indistinguishable Objects
Order the objects as if they were distinguishable Then “divide out” those arrangements that look identical.
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Combinations the number of selections, order doesn’t matter
C(n,r) = n!/[(n-r)!r!] the number of arrangements can be counted by selecting the objects and then ordering them i.e. P(n,r) = C(n,r)*r!
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Observations about Combinations
C(n, r) = C(n, n-r) C(n, n) = C(n, 0) = 1 C(n, 1) = n = C(n, n-1) C(n, 2) = n(n-1)/2
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Combining Counting Techniques
If we are careful with language, when we say “AND”, we multiply “AND” multiplication intersection when we say “OR”, we add “OR” addition union
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Conditional Probability and Independence
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Conditional Probability P(A|B)
P(A|B) is read, “the probability of A given B” B is known to occur.
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The multiplication rule and intersectionmultiply
P(A B) = P(A)*P(B|A) = P(B)*P(A|B) Intersections get more complicated when there are more events, e.g. P(ABCD) = P(A)* P(B|A)*P(C|AB)*P(D|A BC)
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Independent Events A and B are independent if any of the following are true: P(AB) = P(A)*P(B) P(A|B) = P(A) P(B|A) = P(B) You need to check probabilities to determine if events are independent. If A, B, C, & D are pairwise independent, P (AB C D) = P(A)*P(B)*P(C)*P(D)
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Conditional Probability P(A|B) Formula
P(A|B) = P(A B) / P(B), if P(B) > 0 (Note that this is an algebraic manipulation of the formula for the probability of the intersection of 2 events.) i.e. the conditional probability is the probability that both occur divided by what is given occurs
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