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Presentation on theme: "Check animations and delete slides not needed for your class."β€” Presentation transcript:

1 Check animations and delete slides not needed for your class.
Linear Equations – Variable on One Side – Mixed – Non-Calculator – Demonstration This resource provides animated demonstrations of the mathematical method. Check animations and delete slides not needed for your class.

2 π‘₯+6=10 βˆ’ 6 βˆ’ 6 π‘₯ = 4 Solving Linear Equations : Balancing Method
How can we check our answer?

3 15 = 3π‘₯ Γ·3 Γ·3 5 = π‘₯ Solving Linear Equations : Balancing Method
How can we check our answer?

4 π‘₯ 3 =4 Γ—3 Γ—3 π‘₯ = 12 Solving Linear Equations : Balancing Method
How can we check our answer?

5 Solving Linear Equations : Balancing Method
16 = 3π‘₯+4 βˆ’ 4 βˆ’ 4 12 = 3π‘₯ Γ·3 Γ·3 4 = π‘₯ How can we check our answer?

6 Solving Linear Equations : Balancing Method
4π‘₯βˆ’6 =18 + 6 + 6 4π‘₯ = 24 Γ·4 Γ·4 π‘₯ = 6 How can we check our answer?

7 Solving Linear Equations : Balancing Method
π‘₯ 5 +7 =9 βˆ’ 7 βˆ’ 7 π‘₯ 5 = 2 Γ—5 Γ—5 π‘₯ = 10 How can we check our answer?

8 Solving Linear Equations : Balancing Method
2π‘₯ 3 +4 =8 βˆ’ 4 βˆ’ 4 2 3 π‘₯ = 4 Γ—3 Γ—3 2π‘₯ = 12 Γ·2 Γ·2 π‘₯ = 6 How can we check our answer?

9 Solving Linear Equations : Balancing Method
9= π‘₯ βˆ’ 6 βˆ’ 6 π‘₯+2 3 3 = Γ—3 Γ—3 9 = π‘₯+2 βˆ’ 2 βˆ’ 2 7 = π‘₯ How can we check our answer?

10 Solving Linear Equations : Balancing Method
8.5= 4π‘₯+5 2 Γ—2 Γ—2 4π‘₯+5 17 = βˆ’ 5 βˆ’ 5 12 = 4π‘₯ Γ·4 Γ·4 3 = π‘₯ How can we check our answer?

11 Lay out your working neatly!
Solve each equation. (Find the value of π‘₯) Lay out your working neatly! a) π‘₯+2=6 a) 2π‘₯+5=13 a) π‘₯ =7 b) 5π‘₯=15 b) π‘₯ 3 βˆ’4 =1 b) 5π‘₯ βˆ’ 4 4 =4 c) 4π‘₯ βˆ’ =βˆ’10 c) π‘₯ 3 =2 c) 3π‘₯βˆ’5=βˆ’11 d) 6π‘₯ βˆ’4 =7 d) π‘₯ 5 +3 =4 d) 4π‘₯ =9

12 Lay out your working neatly!
Solve each equation. (Find the value of π‘₯) Lay out your working neatly! a) π‘₯+2=6 π‘₯ =4 b) 5π‘₯=15 π‘₯ =3 c) π‘₯ 3 =2 π‘₯ =6 d) π‘₯ 5 +3 =4 π‘₯ =5 a) 2π‘₯+5=13 π‘₯ =4 b) π‘₯ 3 βˆ’4 =1 π‘₯ =15 d) 4π‘₯ =9 π‘₯ =5 c) 3π‘₯βˆ’5=βˆ’11 π‘₯ =βˆ’2 a) π‘₯ =7 π‘₯ =6 b) 5π‘₯ βˆ’ 4 4 =4 π‘₯ =4 c) 4π‘₯ βˆ’ =βˆ’10 π‘₯ =βˆ’5 d) 6π‘₯ βˆ’4 =7 π‘₯ =2.5

13 tom@goteachmaths.co.uk Questions? Comments? Suggestions?
…or have you found a mistake!? Any feedback would be appreciated . Please feel free to


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