1. The Distributive Property
Standard: Use the distributive property to express a sum of two whole numbers 1–100 with a common factor as a multiple of a sum of two whole numbers with no common factor.
I Can Goal: I can apply the Distributive Property to rewrite addition problems by factoring out the Greatest Common Factor.

2. Distributive Property
A paperboy delivers or distributes newspapers to everyone who signs up to receive them. + OR
( )

3. Distributive Property
We can use the same idea with numbers
Steps to Solve:
Find the factors of each number.
Factors of 20: 1, 2, 4, 5, 10, 20
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

4. Distributive Property
We can use the same idea with numbers
Steps to Solve:
2. Find the GCF.
Factors of 20: 1, 2, 4, 5, 10, 20
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

5. Distributive Property
We can use the same idea with numbers = 4(5 +6)
Steps to Solve:
3. Pull out the GCF.
Factors of 20: 1, 2, 4, 5, 10, 20
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

6. Distributive Property
BUT, do they give the same answer?
OR 4(5 +6) =
=44
YES!

7. Distributive Property
We can also model the expression.
4(5 +6) 5 6 4 + 11

8. Distributive Property
Let’s Practice
Factors of 12: 1, 2, 3, 4, 6, 12
Factors of 20: 1, 2, 4, 5, 10, 20
GCF (12,20) = 4
= ___(__) + ___ (__)
= ___ (____ + ____)

9. 3 5 1. 4