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Electric Current Pages 448-451
Chapter 23 Electric Current Pages
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Circuits Any path along which electrons can flow is a circuit
Any gaps will prevent flow and stop the circuit Switch Break 2 types of circuits Series Parallel Fuse: prevent overloading in circuits. The fuse will only allow a certain amount of current to pass through. If too much passes, it will burn the fuse and break the circuit
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Series Circuit Current has a single pathway
Total resistance is equal to the sum of the individual resistances π
π = π
1 + π
2 + π
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Series Circuit πΌ=π£/ π
π Voltage divides among the electrical devices
Ohmβs law applies separately to each device
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Series Circuit Main disadvantage: If one device fails, they all fail
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Series Circuit π
1 =3β¦ ; π
2 =2Ξ©; π
3 =1Ξ©;π=6π£
π
1 =3β¦ ; π
2 =2Ξ©; π
3 =1Ξ©;π=6π£ What is the total resistance? 3+2+1=6Ξ© What is the current in the circuit? πΌ= π π
= 6V 6Ξ© =1π΄ How much voltage is dropped across each resistor? voltage divides 2 V
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Parallel circuit Each device operates independently of the other devices Voltage is the same across all devices Total current divides among the branches. Ohmβs law applies separately to each branch πΌ π‘ππ‘ππ = πΌ πππππβ 1 + πΌ πππππβ 2 + πΌ πππππβ 3 = πΌ π£πππ‘πππ π ππ’πππ As the number of branches increases, the overall resistance of the circuit is decreased. The overall resistance of the circuit is less than the resistance of any one of the braches.
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Parallel circuit 2β¦ 2β¦ 2β¦ 6 v Voltage across each resistor? 6 V
Current in each branch? I=v/r I= 6/2= 3 A Current through the battery? I= sum of all branches= 6 A Equivalent resistance? for a pair of resistors, product / sum⦠2⦠2⦠6 v
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Assignment Click on the link to complete the homework
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