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Finding Maximums & Minimums of Polynomial Functions fguilbert.

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Presentation on theme: "Finding Maximums & Minimums of Polynomial Functions fguilbert."— Presentation transcript:

1 Finding Maximums & Minimums of Polynomial Functions fguilbert

2 Objective - find the maximum and minimum value for a function.
fguilbert

3 value of a quadratic is at the vertex.
The maximum or minimum value of a quadratic is at the vertex. x = - b 2a fguilbert

4 A rectangular dog pen is
Ex 1 A rectangular dog pen is constructed with 60 m of fence. One side of the pen is a barn. What dimensions will give the greatest area. fguilbert

5 barn pen fence 60 m of fence. One side of the pen is a barn.
Find greatest area. barn pen fence fguilbert

6 Total of 3 sides is 60. barn pen X X 60 - 2X fguilbert

7 Area = x ( x) = - 2x2 + 60x barn pen X X 60 - 2X fguilbert

8 Area = x ( x) = - 2x2 + 60x vertex (15, 450) fguilbert

9 Area = x ( 60 - 2x) = - 2x2 + 60x (15, 450) barn pen 15 15 30
fguilbert

10 A box is made. Find x 10 6 6 x 10 sheet of metal.
ex 2 Squares with side x are cut from corners. A box is made. Find x to maximize volume. 10 6 x fguilbert

11 A cubic function has a local max and local min.
fguilbert

12 10 6 x x x x x x x x fguilbert

13 Visualize cutting corners & folding the box.
10 6 x x x x x x x x Visualize cutting corners & folding the box. fguilbert

14 10 - 2x x x x x 6-2x x x x x Sides of the box are
shorter than 10 by 6. fguilbert

15 bottom 6-2x 10 - 2x fguilbert

16 x bottom 6-2x 10 - 2x What is the height ? fguilbert

17 Volume = l w h x 6-2x 10 - 2x V = (10 - 2x )( 6 - 2x ) x bottom
fguilbert

18 V = (10 - 2x )( 6 - 2x ) x max when x = 1.21 V = 32.8 fguilbert

19 Ex A ball is thrown up. Height is a function of time
Given : ho = 15m vo= 20 m/sec g = 9.8m/s2 h = height fguilbert

20 h0 = 15 Vo =20 g =9.8 h = - 1/2 g t2 + vot + ho
h = - 1/2 (9.8) t t + 15 h = t t fguilbert

21 b. Find ball height when t = 3
h = t t + 15 h = -4.9( 3)2 + 20(3) + 15 h = 30.9 meters fguilbert

22 When is the ball 25 m off ground?
Ball is up 25M so let h = 25 h = t t + 15 25 = t t solve for t fguilbert

23 25 = - 4. 9 t2 + 20 t + 15 Put in standard form Get 0 on left. 0 = - 4
25 = t t Put in standard form Get 0 on left. 0 = t t Solve with quadratic formula. fguilbert

24 t = √ 204 - 9.8 t = .6 or t = 3.5 fguilbert

25 When will ball hit ground? Looking for t? Or h??
when the ball hits ground 0 = t t fguilbert

26 0 = - 4.9 t2 + 20 t + 15 Use quadratic formula t = 4.68 or
t = -.6 (is this ok?) no fguilbert

27 When will the ball be at the highest point? Find the maximum height.
h = t t + 15 fguilbert

28 I know how to get maximum height. Just graph the equation. Find the
y value of the max. fguilbert

29 Find the Max ( t, h) (2.04, 35.41) h = t t +15 fguilbert

30 Effort - It is a solo performance that only you can control."
fguilbert


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