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King Fahd University of Petroleum & Minerals
Mechanical Engineering Dynamics ME 201 BY Dr. Meyassar N. Al-Haddad Lecture # 33
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General Application of the Equations of Motion
Summation of moment in FBD = summation of the kinetic moment in K.D
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Rectilinear Translation
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Curvilinear Translation
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Example mm=125 kg mR= 75 kg a= ? NB=? FB=? ms=? Minimum to Lift front wheel
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Problem m = 80 kg mB= 0.8 NA= ? NB= ? When rear wheel locks for break a = ? Deceleration aG mBNB NA NB
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Problem m= 80 kg mB= ? NA=? NB=? a =? When traveling at constant velocity and no break was applied NA NB mBNB a = 0
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Problem m= 80 kg NA=? NB=? a =? mk=? minimum When rider applies the front break and back wheel start to lift off the ground NA NB=0 mkNA
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Example mBD=100kg mAB=mCD= Neglect q = 30o w = 6 rad/s TA= ? TD= ?
aG=?
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Rotation About a Fixed Axis
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Pin Reaction Horizontal Reaction Vertical Reaction OR Normal Reaction
Tangential Reaction If G&O are same use horizontal and vertical If G&O are not same use normal and tangential On Ot Ox On Oy Ot
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Example 17-9 Start from rest m = 30 kg w=20rad/s Pin reaction? q=? Number
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Example 17-10 m= 20 kg
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Example 17-11 m=60 kg Radius of gyration kO=0.25 mb=20 kg a=? Drum a=?
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Example 17-12 W=50 Ib kG=0.6 ft w= 8 rad/s Pin reaction =?
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Thank you
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