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Algebraic Manipulation – Higher – GCSE Questions – AQA
These questions are the same format as previous GCSE exams. COPY means they use the exact same numbers as the original GCSE question. Otherwise, they are clone questions using different numbers. The worksheets are provided in 2 sizes.
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5𝑥+4 5𝑥+15 5(𝑥+4) 5𝑥−4 5𝑥+4 5𝑥+15 5(𝑥+4) 5𝑥−4 5𝑥+4 5𝑥+15 5(𝑥+4) 5𝑥−4
AQA Higher: June 2018 Paper 3, Q15 AQA Higher: June 2018 Paper 3, Q15 1 Amy has 𝑥 beads. Billy has four more beads than Amy. Carly has five times as many beads as Billy. Circle the expression for the number of beads that Carly has. 1 Amy has 𝑥 beads. Billy has four more beads than Amy. Carly has five times as many beads as Billy. Circle the expression for the number of beads that Carly has. [1 mark] [1 mark] 5𝑥+4 5𝑥+15 5(𝑥+4) 5𝑥−4 5𝑥+4 5𝑥+15 5(𝑥+4) 5𝑥−4 AQA Higher: June 2018 Paper 3, Q15 AQA Higher: June 2018 Paper 3, Q15 1 Amy has 𝑥 beads. Billy has four more beads than Amy. Carly has five times as many beads as Billy. Circle the expression for the number of beads that Carly has. 1 Amy has 𝑥 beads. Billy has four more beads than Amy. Carly has five times as many beads as Billy. Circle the expression for the number of beads that Carly has. [1 mark] [1 mark] 5𝑥+4 5𝑥+15 5(𝑥+4) 5𝑥−4 5𝑥+4 5𝑥+15 5(𝑥+4) 5𝑥−4
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AQA Higher: November 2017 Paper 1, Q10
Three identical isosceles triangles are joined to make this trapezium. Each triangle has base 𝑏 cm and perpendicular height ℎ cm 1 Three identical isosceles triangles are joined to make this trapezium. Each triangle has base 𝑏 cm and perpendicular height ℎ cm 𝑏 cm 𝑏 cm Not drawn accurately Not drawn accurately ℎ cm ℎ cm 1 (a) Work out an expression, in terms of 𝑏 and ℎ , for the area of the trapezium. Give your answer in its simplest form. 1 (a) Work out an expression, in terms of 𝑏 and ℎ , for the area of the trapezium. Give your answer in its simplest form. [2 marks] [2 marks] Answer cm2 Answer cm2 1 (b) This diagram shows the same trapezium. 1 (b) This diagram shows the same trapezium. Not drawn accurately Not drawn accurately 𝑏 cm 𝑏 cm 𝑠 cm 𝑠 cm [2 marks] [2 marks] 𝑏 : 𝑠 = 2 : 3 Work out an expression, in terms of 𝑏, for the perimeter of the trapezium. 𝑏 : 𝑠 = 2 : 3 Work out an expression, in terms of 𝑏, for the perimeter of the trapezium. Answer cm Answer cm
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AQA Higher: June 2017 Paper 3, Q3 AQA Higher: June 2017 Paper 3, Q3
Rearrange 𝑡= 𝑦 𝑥 to make 𝑥 the subject. Circle your answer. 1 [1 mark] 𝑥 = 𝑦 3𝑡 𝑥 = 3𝑡 𝑦 𝑥 = 𝑡 3𝑦 𝑥 = 3𝑦 𝑡 Rearrange 𝑡= 𝑦 𝑥 to make 𝑥 the subject. Circle your answer. 1 [1 mark] 𝑥 = 𝑦 3𝑡 𝑥 = 3𝑡 𝑦 𝑥 = 𝑡 3𝑦 𝑥 = 3𝑦 𝑡 Rearrange 𝑠= 2𝑥 𝑔 to make 𝑥 the subject. Circle your answer. 2 [1 mark] 𝑥 = 2𝑔 𝑠 𝑥 = 2𝑠 𝑔 𝑥 = 2 𝑔𝑠 𝑥 = 𝑔𝑠 2 Rearrange 𝑠= 2𝑥 𝑔 to make 𝑥 the subject. Circle your answer. 2 [1 mark] 𝑥 = 2𝑔 𝑠 𝑥 = 2𝑠 𝑔 𝑥 = 2 𝑔𝑠 𝑥 = 𝑔𝑠 2 Rearrange 𝑔= 𝑘 3ℎ to make ℎ the subject. Circle your answer. 3 [1 mark] ℎ = 6𝑘 ℎ ℎ = 6𝑘 𝑔 ℎ = 𝑘 6𝑔 ℎ = 𝑘 3𝑔 Rearrange 𝑔= 𝑘 3ℎ to make ℎ the subject. Circle your answer. 3 [1 mark] ℎ = 6𝑘 ℎ ℎ = 6𝑘 𝑔 ℎ = 𝑘 6𝑔 ℎ = 𝑘 3𝑔 AQA Higher: June 2017 Paper 3, Q3 AQA Higher: June 2017 Paper 3, Q3 Rearrange 𝑡= 𝑦 𝑥 to make 𝑥 the subject. Circle your answer. 1 [1 mark] 𝑥 = 𝑦 3𝑡 𝑥 = 3𝑡 𝑦 𝑥 = 𝑡 3𝑦 𝑥 = 3𝑦 𝑡 Rearrange 𝑡= 𝑦 𝑥 to make 𝑥 the subject. Circle your answer. 1 [1 mark] 𝑥 = 𝑦 3𝑡 𝑥 = 3𝑡 𝑦 𝑥 = 𝑡 3𝑦 𝑥 = 3𝑦 𝑡 Rearrange 𝑠= 2𝑥 𝑔 to make 𝑥 the subject. Circle your answer. 2 [1 mark] 𝑥 = 2𝑔 𝑠 𝑥 = 2𝑠 𝑔 𝑥 = 2 𝑔𝑠 𝑥 = 𝑔𝑠 2 Rearrange 𝑠= 2𝑥 𝑔 to make 𝑥 the subject. Circle your answer. 2 [1 mark] 𝑥 = 2𝑔 𝑠 𝑥 = 2𝑠 𝑔 𝑥 = 2 𝑔𝑠 𝑥 = 𝑔𝑠 2 Rearrange 𝑔= 𝑘 3ℎ to make ℎ the subject. Circle your answer. 3 [1 mark] ℎ = 6𝑘 ℎ ℎ = 6𝑘 𝑔 ℎ = 𝑘 6𝑔 ℎ = 𝑘 3𝑔 Rearrange 𝑔= 𝑘 3ℎ to make ℎ the subject. Circle your answer. 3 [1 mark] ℎ = 6𝑘 ℎ ℎ = 6𝑘 𝑔 ℎ = 𝑘 6𝑔 ℎ = 𝑘 3𝑔
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AQA Higher: November 2017 Paper 3, Q9
Rearrange 𝑣=𝑢+𝑎𝑡 to make 𝑡 the subject of the formula. 1 (a) Rearrange 𝑣=𝑢+𝑎𝑡 to make 𝑡 the subject of the formula. [2 marks] [2 marks] Answer Answer 1 (b) Complete this table with consistent metric units. 1 (b) Complete this table with consistent metric units. [2 marks] [2 marks] Distance Time Speed Acceleration m s Distance Time Speed Acceleration m s AQA Higher: November 2017 Paper 3, Q9 AQA Higher: November 2017 Paper 3, Q9 1 (a) Rearrange 𝑣=𝑢+𝑎𝑡 to make 𝑡 the subject of the formula. 1 (a) Rearrange 𝑣=𝑢+𝑎𝑡 to make 𝑡 the subject of the formula. [2 marks] [2 marks] Answer Answer 1 (b) Complete this table with consistent metric units. 1 (b) Complete this table with consistent metric units. [2 marks] [2 marks] Distance Time Speed Acceleration m s Distance Time Speed Acceleration m s
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AQA Higher: November 2017 Paper 3, Q5
Multiply out and simplify 𝑥−5 2 [2 marks] 1 Multiply out and simplify 𝑥−5 2 [2 marks] Answer Answer 2 Multiply out and simplify 𝑥−3 2 [2 marks] 2 Multiply out and simplify 𝑥−3 2 [2 marks] Answer Answer AQA Higher: November 2017 Paper 3, Q5 AQA Higher: November 2017 Paper 3, Q5 1 Multiply out and simplify 𝑥−5 2 [2 marks] 1 Multiply out and simplify 𝑥−5 2 [2 marks] Answer Answer 2 Multiply out and simplify 𝑥−3 2 [2 marks] 2 Multiply out and simplify 𝑥−3 2 [2 marks] Answer Answer
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AQA Higher: May 2017 Paper 1, Q26 AQA Higher: May 2017 Paper 1, Q26
Expand and simplify 𝑥−5 2𝑥+5𝑦 2 [4 marks] 1 Expand and simplify 𝑥−5 2𝑥+5𝑦 2 [4 marks] Answer Answer AQA Higher: May 2017 Paper 1, Q26 AQA Higher: May 2017 Paper 1, Q26 1 Expand and simplify 𝑥−5 2𝑥+5𝑦 2 [4 marks] 1 Expand and simplify 𝑥−5 2𝑥+5𝑦 2 [4 marks] Answer Answer
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AQA Higher: November 2017 Paper 3, Q15
3𝑥2𝑦3 1 [1 mark] Circle the highest common factor (HCF) of 6𝑥3𝑦2 and 9𝑥𝑦2 3𝑥2𝑦 6𝑥2𝑦2 3𝑥𝑦2 3𝑥2𝑦3 1 [1 mark] Circle the highest common factor (HCF) of 6𝑥3𝑦2 and 9𝑥𝑦2 3𝑥2𝑦 6𝑥2𝑦2 3𝑥𝑦2 4𝑥𝑦2 2 [1 mark] Circle the highest common factor (HCF) of 6𝑥3𝑦 and 4𝑥𝑦4 2𝑥𝑦 4𝑥𝑦 2𝑥2𝑦3 4𝑥𝑦2 2 [1 mark] Circle the highest common factor (HCF) of 6𝑥3𝑦 and 4𝑥𝑦4 2𝑥𝑦 4𝑥𝑦 2𝑥2𝑦3 8𝑥3𝑦 3 [1 mark] Circle the highest common factor (HCF) of 24𝑥3𝑦 and 8𝑥2𝑦2 8𝑥2𝑦 8𝑥𝑦 4𝑥2𝑦 8𝑥3𝑦 3 [1 mark] Circle the highest common factor (HCF) of 24𝑥3𝑦 and 8𝑥2𝑦2 8𝑥2𝑦 8𝑥𝑦 4𝑥2𝑦 AQA Higher: November 2017 Paper 3, Q15 AQA Higher: November 2017 Paper 3, Q15 3𝑥2𝑦3 1 [1 mark] Circle the highest common factor (HCF) of 6𝑥3𝑦2 and 9𝑥𝑦2 3𝑥2𝑦 6𝑥2𝑦2 3𝑥𝑦2 3𝑥2𝑦3 1 [1 mark] Circle the highest common factor (HCF) of 6𝑥3𝑦2 and 9𝑥𝑦2 3𝑥2𝑦 6𝑥2𝑦2 3𝑥𝑦2 4𝑥𝑦2 2 [1 mark] Circle the highest common factor (HCF) of 6𝑥3𝑦 and 4𝑥𝑦4 2𝑥𝑦 4𝑥𝑦 2𝑥2𝑦3 4𝑥𝑦2 2 [1 mark] Circle the highest common factor (HCF) of 6𝑥3𝑦 and 4𝑥𝑦4 2𝑥𝑦 4𝑥𝑦 2𝑥2𝑦3 8𝑥3𝑦 3 [1 mark] Circle the highest common factor (HCF) of 24𝑥3𝑦 and 8𝑥2𝑦2 8𝑥2𝑦 8𝑥𝑦 4𝑥2𝑦 8𝑥3𝑦 3 [1 mark] Circle the highest common factor (HCF) of 24𝑥3𝑦 and 8𝑥2𝑦2 8𝑥2𝑦 8𝑥𝑦 4𝑥2𝑦
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AQA Higher: November 2017 Paper 2, Q16
Factorise fully 8𝑥3−2𝑥 [2 marks] 1 (a) Factorise fully 8𝑥3−2𝑥 [2 marks] Answer Answer 1 (b) Factorise fully 5𝑥2−10𝑥+5 [2 marks] 1 (b) Factorise fully 5𝑥2−10𝑥+5 [2 marks] Answer Answer AQA Higher: November 2017 Paper 2, Q16 AQA Higher: November 2017 Paper 2, Q16 1 (a) Factorise fully 8𝑥3−2𝑥 [2 marks] 1 (a) Factorise fully 8𝑥3−2𝑥 [2 marks] Answer Answer 1 (b) Factorise fully 5𝑥2−10𝑥+5 [2 marks] 1 (b) Factorise fully 5𝑥2−10𝑥+5 [2 marks] Answer Answer
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AQA Higher: November 2017 Paper 1, Q5
Factorise 𝑥2 −49 [1 mark] 1 (a) Factorise 𝑥2 −49 [1 mark] Answer Answer 1 (b) Solve 5𝑥+7>1+3𝑥 [2 marks] 1 (b) Solve 5𝑥+7>1+3𝑥 [2 marks] Answer Answer AQA Higher: November 2017 Paper 1, Q5 AQA Higher: November 2017 Paper 1, Q5 1 (a) Factorise 𝑥2 −49 [1 mark] 1 (a) Factorise 𝑥2 −49 [1 mark] Answer Answer 1 (b) Solve 5𝑥+7>1+3𝑥 [2 marks] 1 (b) Solve 5𝑥+7>1+3𝑥 [2 marks] Answer Answer
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AQA Higher: May 2018 Paper 1, Q3 AQA Higher: May 2018 Paper 1, Q3
Circle the expression that is equivalent to 4𝑏+2𝑏×𝑏−3𝑏 1 Circle the expression that is equivalent to 4𝑏+2𝑏×𝑏−3𝑏 6𝑏2−3𝑏 2𝑏2−𝑏 −6𝑏2 2𝑏2+𝑏 [1 mark] 6𝑏2−3𝑏 2𝑏2−𝑏 −6𝑏2 2𝑏2+𝑏 [1 mark] 2 Circle the expression that is equivalent to 7𝑏−2𝑏×2𝑏−𝑏 2 Circle the expression that is equivalent to 7𝑏−2𝑏×2𝑏−𝑏 5𝑏2 6𝑏−4𝑏2 10𝑏2−𝑏 7𝑏−2𝑏2 [1 mark] 5𝑏2 6𝑏−4𝑏2 10𝑏2−𝑏 7𝑏−2𝑏2 [1 mark] 3 Circle the expression that is equivalent to 4𝑏×2𝑏−𝑏×3𝑏 3 Circle the expression that is equivalent to 4𝑏×2𝑏−𝑏×3𝑏 −12𝑏3 12𝑏3 3𝑏2 5𝑏2 [1 mark] −12𝑏3 12𝑏3 3𝑏2 5𝑏2 [1 mark] AQA Higher: May 2018 Paper 1, Q3 AQA Higher: May 2018 Paper 1, Q3 1 Circle the expression that is equivalent to 4𝑏+2𝑏×𝑏−3𝑏 1 Circle the expression that is equivalent to 4𝑏+2𝑏×𝑏−3𝑏 6𝑏2−3𝑏 2𝑏2−𝑏 −6𝑏2 2𝑏2+𝑏 [1 mark] 6𝑏2−3𝑏 2𝑏2−𝑏 −6𝑏2 2𝑏2+𝑏 [1 mark] 2 Circle the expression that is equivalent to 7𝑏−2𝑏×2𝑏−𝑏 2 Circle the expression that is equivalent to 7𝑏−2𝑏×2𝑏−𝑏 5𝑏2 6𝑏−4𝑏2 10𝑏2−𝑏 7𝑏−2𝑏2 [1 mark] 5𝑏2 6𝑏−4𝑏2 10𝑏2−𝑏 7𝑏−2𝑏2 [1 mark] 3 Circle the expression that is equivalent to 4𝑏×2𝑏−𝑏×3𝑏 3 Circle the expression that is equivalent to 4𝑏×2𝑏−𝑏×3𝑏 −12𝑏3 12𝑏3 3𝑏2 5𝑏2 [1 mark] −12𝑏3 12𝑏3 3𝑏2 5𝑏2 [1 mark]
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AQA Higher: November 2017 Paper 1, Q3
Circle the expression that is equivalent to 2 𝑏 2 2 [1 mark] 1 Circle the expression that is equivalent to 2 𝑏 2 2 [1 mark] 4𝑏 4 𝑏 4 2 𝑏 2 4 𝑏 2 4𝑏 4 𝑏 4 2 𝑏 2 4 𝑏 2 2 Circle the expression that is equivalent to 5 𝑏 5 2 [1 mark] 2 Circle the expression that is equivalent to 5 𝑏 5 2 [1 mark] 25 𝑏 7 7 𝑏 7 10 𝑏 10 25 𝑏 10 25 𝑏 7 7 𝑏 7 10 𝑏 10 25 𝑏 10 3 Circle the expression that is equivalent to 4 𝑏 3 2 [1 mark] 3 Circle the expression that is equivalent to 4 𝑏 3 2 [1 mark] 8 𝑏 6 6 𝑏 5 16 𝑏 5 16 𝑏 6 8 𝑏 6 6 𝑏 5 16 𝑏 5 16 𝑏 6 AQA Higher: November 2017 Paper 1, Q3 AQA Higher: November 2017 Paper 1, Q3 1 Circle the expression that is equivalent to 2 𝑏 2 2 [1 mark] 1 Circle the expression that is equivalent to 2 𝑏 2 2 [1 mark] 4𝑏 4 𝑏 4 2 𝑏 2 4 𝑏 2 4𝑏 4 𝑏 4 2 𝑏 2 4 𝑏 2 2 Circle the expression that is equivalent to 5 𝑏 5 2 [1 mark] 2 Circle the expression that is equivalent to 5 𝑏 5 2 [1 mark] 25 𝑏 7 7 𝑏 7 10 𝑏 10 25 𝑏 10 25 𝑏 7 7 𝑏 7 10 𝑏 10 25 𝑏 10 3 Circle the expression that is equivalent to 4 𝑏 3 2 [1 mark] 3 Circle the expression that is equivalent to 4 𝑏 3 2 [1 mark] 8 𝑏 6 6 𝑏 5 16 𝑏 5 16 𝑏 6 8 𝑏 6 6 𝑏 5 16 𝑏 5 16 𝑏 6
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AQA Higher: June 2017 Paper 3, Q12 AQA Higher: June 2017 Paper 3, Q12
𝑎𝑥𝑏 3 =27𝑥21 where 𝑎 and 𝑏 are positive integers. Work out 𝑎 and 𝑏 1 𝑎𝑥𝑏 3 =27𝑥21 where 𝑎 and 𝑏 are positive integers. Work out 𝑎 and 𝑏 [2 marks] [2 marks] 𝑎 = 𝑏 = 𝑎 = 𝑏 = AQA Higher: June 2017 Paper 3, Q12 AQA Higher: June 2017 Paper 3, Q12 1 𝑎𝑥𝑏 3 =27𝑥21 where 𝑎 and 𝑏 are positive integers. Work out 𝑎 and 𝑏 1 𝑎𝑥𝑏 3 =27𝑥21 where 𝑎 and 𝑏 are positive integers. Work out 𝑎 and 𝑏 [2 marks] [2 marks] 𝑎 = 𝑏 = 𝑎 = 𝑏 =
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AQA Higher: November 2017 Paper 3, Q21
𝑁 is a number. As a product of prime factors in index form 𝑁 = 2 × 34 × 𝑦3 Work out 3𝑁2 as a product of prime factors in index form. Give your answer in terms of 𝑦. 1 𝑁 is a number. As a product of prime factors in index form 𝑁 = 2 × 34 × 𝑦3 Work out 3𝑁2 as a product of prime factors in index form. Give your answer in terms of 𝑦. [3 marks] [3 marks] Answer Answer AQA Higher: November 2017 Paper 3, Q21 AQA Higher: November 2017 Paper 3, Q21 1 𝑁 is a number. As a product of prime factors in index form 𝑁 = 2 × 34 × 𝑦3 Work out 3𝑁2 as a product of prime factors in index form. Give your answer in terms of 𝑦. 1 𝑁 is a number. As a product of prime factors in index form 𝑁 = 2 × 34 × 𝑦3 Work out 3𝑁2 as a product of prime factors in index form. Give your answer in terms of 𝑦. [3 marks] [3 marks] Answer Answer
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AQA Higher: November 2017 Paper 2, Q11
4𝑥2 8𝑥2 + 4 4𝑥2 8𝑥2 + 4 1 Circle the expression that is equivalent to 1 Circle the expression that is equivalent to 𝑥2 2𝑥2 +4 𝑥2 2𝑥2 + 1 𝑥2 8𝑥2 +1 2𝑥2 4𝑥2 +1 [1 mark] 𝑥2 2𝑥2 +4 𝑥2 2𝑥2 + 1 𝑥2 8𝑥2 +1 2𝑥2 4𝑥2 +1 [1 mark] 5𝑥2 20𝑥2 −15 5𝑥2 20𝑥2 −15 2 Circle the expression that is equivalent to 2 Circle the expression that is equivalent to 𝑥2 4𝑥2 −2 4𝑥2 4𝑥2 −3 𝑥2 5𝑥2 − 3 𝑥2 4𝑥2 − 3 [1 mark] 𝑥2 4𝑥2 −2 4𝑥2 4𝑥2 −3 𝑥2 5𝑥2 − 3 𝑥2 4𝑥2 − 3 [1 mark] AQA Higher: November 2017 Paper 2, Q11 AQA Higher: November 2017 Paper 2, Q11 4𝑥2 8𝑥2 + 4 4𝑥2 8𝑥2 + 4 1 Circle the expression that is equivalent to 1 Circle the expression that is equivalent to 𝑥2 2𝑥2 +4 𝑥2 2𝑥2 + 1 𝑥2 8𝑥2 +1 2𝑥2 4𝑥2 +1 [1 mark] 𝑥2 2𝑥2 +4 𝑥2 2𝑥2 + 1 𝑥2 8𝑥2 +1 2𝑥2 4𝑥2 +1 [1 mark] 5𝑥2 20𝑥2 −15 5𝑥2 20𝑥2 −15 2 Circle the expression that is equivalent to 2 Circle the expression that is equivalent to 𝑥2 4𝑥2 −2 4𝑥2 4𝑥2 −3 𝑥2 5𝑥2 − 3 𝑥2 4𝑥2 − 3 [1 mark] 𝑥2 4𝑥2 −2 4𝑥2 4𝑥2 −3 𝑥2 5𝑥2 − 3 𝑥2 4𝑥2 − 3 [1 mark]
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AQA Higher: June 2018 Paper 2, Q13
Show that, for 𝑥 ≠ –1 1 Show that, for 𝑥 ≠ –1 6𝑥2 − 24 2𝑥 simplifies to the form a𝑥 + b where a and b are integers. 6𝑥2 − 24 2𝑥 simplifies to the form a𝑥 + b where a and b are integers. [3 marks] [3 marks] Answer Answer AQA Higher: June 2018 Paper 2, Q13 AQA Higher: June 2018 Paper 2, Q13 1 Show that, for 𝑥 ≠ –1 1 Show that, for 𝑥 ≠ –1 6𝑥2 − 24 2𝑥 simplifies to the form a𝑥 + b where a and b are integers. 6𝑥2 − 24 2𝑥 simplifies to the form a𝑥 + b where a and b are integers. [3 marks] [3 marks] Answer Answer
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AQA Higher: November 2017 Paper 1, Q10
Three identical isosceles triangles are joined to make this trapezium. Each triangle has base 𝑏 cm and perpendicular height ℎ cm 𝑏 cm Not drawn accurately ℎ cm 1 (a) Work out an expression, in terms of 𝑏 and ℎ , for the area of the trapezium. Give your answer in its simplest form. [2 marks] Answer cm2 1 (b) This diagram shows the same trapezium. Not drawn accurately 𝑏 cm 𝑠 cm [2 marks] 𝑏 : 𝑠 = 2 : 3 Work out an expression, in terms of 𝑏, for the perimeter of the trapezium. Answer cm
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Area = (½ b × h) × 3 3𝑏ℎ 2 𝑏 𝑠 = 2 3 3𝑏 = 2𝑠 b b 3b + 2s 2s = 3b
AQA Higher: November 2017 Paper 1, Q10 1 Three identical isosceles triangles are joined to make this trapezium. Each triangle has base 𝑏 cm and perpendicular height ℎ cm 𝑏 cm Not drawn accurately ℎ cm 1 (a) Work out an expression, in terms of 𝑏 and ℎ , for the area of the trapezium. Give your answer in its simplest form. [2 marks] Area = (½ b × h) × 3 3𝑏ℎ 2 Answer cm2 1 (b) This diagram shows the same trapezium. Not drawn accurately 𝑏 𝑠 = 2 3 𝑏 cm 𝑠 cm 3𝑏 = 2𝑠 [2 marks] b b 𝑏 : 𝑠 = 2 : 3 Work out an expression, in terms of 𝑏, for the perimeter of the trapezium. 3b + 2s 2s = 3b 3b + 3b = 6b 6b Answer cm
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AQA Higher: November 2017 Paper 3, Q21
𝑁 is a number. As a product of prime factors in index form 𝑁 = 2 × 34 × 𝑦3 Work out 3𝑁2 as a product of prime factors in index form. Give your answer in terms of 𝑦. [3 marks] 3 2 × 34 × 𝑦3 2 3 22 × 38 × 𝑦6 3 × 22 × 38 × 𝑦6 22 × 39 × 𝑦6 22 × 39 × 𝑦6 Answer
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tom@goteachmaths.co.uk Questions? Comments? Suggestions?
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