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 l .  l   l   l   l  Io.

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Presentation on theme: " l .  l   l   l   l  Io."— Presentation transcript:

1

2  l 

3  l 

4  l 

5  l  Io

6  l  Io I

7 dx Io I

8 γ is the absorption coefficient
dx Io I γ is the absorption coefficient dI = - γIx dx

9  l  Io I dI = - γIx dx dI/Ix = - γdx

10 I = ∫I=Io 1/Ix dI = - γ ∫x=0 dx
 l  Io I dI = - γIx dx dI/Ix = - γdx I x=l I = ∫I=Io 1/Ix dI = - γ ∫x=0 dx

11 I = ∫I=Io 1/Ix dI = - γ ∫x=0 dx
 l  Io I dI = - γIx dx dI/Ix = - γdx I x=l I = ∫I=Io 1/Ix dI = - γ ∫x=0 dx [loge I – loge Io] = -γl

12 I = ∫I=Io 1/Ix dI = - γ ∫x=0 dx
 l  Io I dI = - γIx dx dI/Ix = - γdx I x=l I = ∫I=Io 1/Ix dI = - γ ∫x=0 dx [loge I – loge Io] = -γl I/Io = e-γl

13 I = Ioe-γl

14 I = Ioe-γl Beer’s Law

15  = (4/3ħc) Harry Kroto 2004

16  = (4/3ħc) n em2 1 Harry Kroto 2004

17  = (4/3ħc) n em2  Harry Kroto 2004

18  = (4/3ħc) n em2  (Nm-Nn) 1 2 3
Harry Kroto 2004

19  = (4/3ħc) n em2  (Nm-Nn) (o-) 1 2 3 4
Harry Kroto 2004

20  = (4/3ħc) n em2  (Nm-Nn) (o-) 1 2 3 4
Square of the transition moment n em2 Harry Kroto 2004

21 n em2 ≡ ∫ψn*μeψmdτ
NB n em2 ≡ ∫ψn*μeψmdτ Harry Kroto 2004

22  = (4/3ħc) n em2  (Nm-Nn) (o-) 1 2 3 4
Square of the transition moment n em2 Frequency of the light  Harry Kroto 2004

23  = (4/3ħc) n em2  (Nm-Nn) (o-) 1 2 3 4
Square of the transition moment n em2 Frequency of the light  Population difference (Nm- Nn) Harry Kroto 2004

24  = (4/3ħc) n em2  (Nm-Nn) (o-) 1 2 3 4
Square of the transition moment n em2 Frequency of the light  Population difference (Nm- Nn) Resonance factor - Dirac delta function (0) = 1 Harry Kroto 2004

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