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1 Print out these axes and put in plastic wallets
π‘₯ βˆ’3 βˆ’2 βˆ’1 1 2 3

2 The equation 𝑦= π‘₯ 2 can be written as 𝑓 π‘₯ = π‘₯ 2
𝑓 π‘₯ means the function 𝑓, where π‘₯ is the input

3 If 𝑓 π‘₯ = π‘₯ 2 βˆ’7, what is the value of 𝑓(6)?
On your whiteboards: If 𝑓 π‘₯ = π‘₯ 2 βˆ’7, what is the value of 𝑓(6)?

4 If 𝑓 π‘₯ = π‘₯ 2 βˆ’7, what is the value of 𝑓(6)?
On your whiteboards: If 𝑓 π‘₯ = π‘₯ 2 βˆ’7, what is the value of 𝑓(6)?

5 𝑓 π‘₯ = π‘₯ 2 βˆ’7 𝑓 6 = 6 2 βˆ’7 βˆ΄π‘“ 6 =29

6 If 𝑓 π‘₯ = π‘₯+1 2 , what is the value of 𝑓(19)?
On your whiteboards: If 𝑓 π‘₯ = π‘₯+1 2 , what is the value of 𝑓(19)?

7 If 𝑓 π‘₯ = π‘₯+1 2 , what is the value of 𝑓(19)?
On your whiteboards: If 𝑓 π‘₯ = π‘₯+1 2 , what is the value of 𝑓(19)?

8 𝑓 π‘₯ = π‘₯+1 2 𝑓 19 = βˆ΄π‘“ 19 =10

9 On your whiteboards: If 𝑓 π‘₯ =(π‘₯+1)(π‘₯+10) what is the value of 𝑓(9)?

10 On your whiteboards: If 𝑓 π‘₯ =(π‘₯+1)(π‘₯+10) what is the value of 𝑓(9)?

11 𝑓 π‘₯ = π‘₯+1 (π‘₯+10) 𝑓 9 =(9+1)(9+10) βˆ΄π‘“ 9 =10Γ—19=190
𝑓 π‘₯ = π‘₯+1 (π‘₯+10) 𝑓 9 =(9+1)(9+10) βˆ΄π‘“ 9 =10Γ—19=190

12 Draw the graph of the function:
𝑓 π‘₯ = π‘₯ 2 for βˆ’3≀π‘₯≀3 Do not rub out your graph! π‘₯ βˆ’3 βˆ’2 βˆ’1 1 2 3 𝑓(π‘₯) 9 4

13 Draw the graph of the function:
𝑓 π‘₯ = π‘₯ 2 for βˆ’3≀π‘₯≀3 The domain is the set of input values Here the domain is βˆ’πŸ‘β‰€π’™β‰€πŸ‘ π‘₯ βˆ’3 βˆ’2 βˆ’1 1 2 3 𝑓(π‘₯) 9 4

14 Draw the graph of the function:
𝑓 π‘₯ = π‘₯ 2 for βˆ’3≀π‘₯≀3 The range is the set of output values Here the range is πŸŽβ‰€π’‡(𝒙)β‰€πŸ— π‘₯ βˆ’3 βˆ’2 βˆ’1 1 2 3 𝑓(π‘₯) 9 4

15 Now draw the graph of: 𝑓 π‘₯ +1 Where: f(π‘₯)= π‘₯ 2 for βˆ’3≀π‘₯≀3 βˆ’3 βˆ’2 βˆ’1 1 2
𝒙 βˆ’3 βˆ’2 βˆ’1 1 2 3 𝒇(𝒙) 9 4 𝒇(𝒙)+𝟏 10 5

16 Try and use the following key words in your discussion:
What do you notice? Try and use the following key words in your discussion: Translate Parabola π‘₯-coordinates 𝑦-coordinates Domain Range Vector 𝒙 βˆ’3 βˆ’2 βˆ’1 1 2 3 𝒇(𝒙) 9 4 𝒇(𝒙)+𝟏 10 5

17 𝑓 π‘₯ →𝑓 π‘₯ +1 represents a translation of 0 1 The domain is unchanged:
βˆ’3≀π‘₯≀3 The range increases by 1 1≀𝑓 π‘₯ +1≀10 𝒙 βˆ’3 βˆ’2 βˆ’1 1 2 3 𝒇(𝒙) 9 4 𝒇(𝒙)+𝟏 10 5

18 On your whiteboards: The graphs of 𝑓(π‘₯) and 𝑓(π‘₯)+6 are shown. What are the missing coordinates? (0, 9)

19 On your whiteboards: The graphs of 𝑓(π‘₯) and 𝑓 π‘₯ βˆ’12 are shown. What are the missing coordinates? (0, βˆ’8)

20 On your whiteboards: What effect will the transformation: 𝑓 π‘₯ →𝑓 π‘₯ +2 have on the graph of 𝑓(π‘₯)? A: 2 0 B: 0 2 C: 2 2

21 On your whiteboards: What effect will the transformation: 𝑓 π‘₯ →𝑓 π‘₯ +2 have on the graph of 𝑓(π‘₯)? B: 0 2

22 The value of π‘₯ can be adjusted before the function is applied.
00 The value of π‘₯ can be adjusted before the function is applied. Now draw the graph of 𝑓 π‘₯+1 where: f(π‘₯)= π‘₯ 2 for βˆ’3≀π‘₯≀3 𝒙 βˆ’3 βˆ’2 βˆ’1 1 2 3 𝒙+𝟏 4 𝒇(𝒙+𝟏) 9 16

23 Try and use the following key words in your discussion:
00 What do you notice? Try and use the following key words in your discussion: Translate Parabola π‘₯-coordinates 𝑦-coordinates Domain Range Vector 𝒙 βˆ’3 βˆ’2 βˆ’1 1 2 3 𝒙+𝟏 4 𝒇(𝒙+𝟏) 9 16

24 𝑓 π‘₯ →𝑓 π‘₯+1 represents a translation of βˆ’1 0
00 𝑓 π‘₯ →𝑓 π‘₯+1 represents a translation of βˆ’1 0 The domain is unchanged: βˆ’3≀π‘₯≀3 The range becomes: 0≀𝑓(π‘₯+1)≀16 𝒙 βˆ’3 βˆ’2 βˆ’1 1 2 3 𝒙+𝟏 4 𝒇(𝒙+𝟏) 9 16

25 On your whiteboards: What effect will the transformation: 𝑓 π‘₯ →𝑓 π‘₯βˆ’2 have on the graph of 𝑓(π‘₯)? A: 2 0 B: βˆ’2 0 C: 0 2 D: 0 βˆ’2

26 On your whiteboards: What effect will the transformation: 𝑓 π‘₯ →𝑓 π‘₯βˆ’2 have on the graph of 𝑓(π‘₯)? A: 2 0

27 Fill in the box to match the transformation shown.
On your whiteboards: Fill in the box to match the transformation shown. (0, 9) βˆ’2

28 Fill in the box to match the transformation shown.
On your whiteboards: Fill in the box to match the transformation shown. +4 (0, 9) βˆ’2

29 On your whiteboards: The graph shows the function 𝑓(π‘₯) Write the coordinates of the roots of 𝑓(π‘₯+4)

30 Title: Translating Functions
𝑓 π‘₯ + π‘Ž represents a translation by 0 π‘Ž 𝑓 π‘₯+π‘Ž represents a translation by βˆ’π‘Ž 0

31 Match the transformations to the descriptions.
The first one is done for you. 2. On separate axes sketch the graph of the following functions. For each one, state the transformation that has occurred from the original graph. 𝑓 π‘₯ +1 𝑓(π‘₯+1) 𝑓(π‘₯) – 2 𝑓(π‘₯βˆ’2)

32 Mark your work


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