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The Chain Rule.

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Presentation on theme: "The Chain Rule."— Presentation transcript:

1 The Chain Rule

2 What is to be learned? How to differentiate a composite function

3 f(x) = (x + 5)2 = x2 + 10x + 25 f(x) = (x + 5)7

4  y = (2x + 5)7 remember sin(2x + 30) = 0.8 dy/dx sinA = 0.8,
where A = 2x + 30 let y= u7 where u = 2x + 5 dy/du = 7u6 du/dx = 2 = dydu dy/du X du/dx dudx dy/du du/dx = dy/dx = 7u6 2 dy/dx = 14u6

5  y = (2x + 5)7 remember sin(2x + 30) = 0.8 dy/dx sinA = 0.8,
where A = 2x + 30 let y= u7 where u = 2x + 5 dy/du = 7u6 du/dx = 2 = dydu dy/du du/dx dudx dy/du du/dx = dy/dx = 7u6 2 dy/dx = 14u6

6  y = (2x + 5)7 remember sin(2x + 30) = 0.8 dy/dx sinA = 0.8,
where A = 2x + 30 let y= u7 where u = 2x + 5 dy/du = 7u6 du/dx = 2 = dydu dy/du du/dx dudx dy/du du/dx = dy/dx = 7u6 2 dy/dx The Chain Rule = 14u6 = 14(2x+5)6

7 y = (7x + 2)5 let y= u5 where u = 7x + 2 dy/du = 5u4 du/dx = 7 dy/dx = dy/du du/dx = 5u4 7 dy/dx = 35u4 = 35(7x + 2)4

8 The Chain Rule For Type (ax + b)n
Key to the chain rule dy/dx = dy/du du/dx

9 y = (x2 + 2)9 let y= u9 where u = x2 + 2 * dy/du = 9u8 du/dx = 2x dy/dx = dy/du du/dx = 9u8 2x dy/dx = 18x u8 = 18x(x2 + 2)8 from*

10 Fast Tracking y = (7x + 2)5 let y= u5 where u = 7x + 2 dy/du = 5u4 du/dx = 7 dy/dx = dy/du du/dx =5(7x + 2)4 = 5u4 7 dy/dx derivative of bit in brackets


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