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BHASVIC MΞ±THS 1 A1 DOUBLES AssIGNMENT 2A
By completing the square, sketch the graphs of the following equations. For each graph, show the coordinates of the points where the graph crosses the coordinate axes, and write down the coordinate of the turning point and the equation of the line of symmetry. (a) π¦=4 π₯ 2 β20π₯+16 (b) π¦=0.5 π₯ π₯β0.04 (c) π¦=β π₯ 2 +10π₯+1
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BHASVIC MΞ±THS 2 A1 DOUBLES AssIGNMENT 2A
i) Sketch the following curves of y = f (x), stating the equations of the asymptotes and the coordinates of any axis intercepts: (a) π π₯ =2+ 1 π₯ (b) π π₯ = 1 π₯β3 (c) π π₯ = 2 π₯ ii) Sketch the following curves, showing any relevant features such as axis intercepts (a) π¦= π₯β (b) π¦=β 1 π₯+2 (c) π¦= π₯+2 2 (π₯β3) (d) π¦= 1 3π₯
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BHASVIC MΞ±THS 3 A1 DOUBLES AssIGNMENT 2A (a) Simplify π + π π β π .
(b) Hence show that β β β4 +β¦ =4
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BHASVIC MΞ±THS 4 A1 DOUBLES AssIGNMENT 2A
Given the two points A(4, 7) and B(β2, 5): Find the mid-point of A and B. Find the exact distance AB. Leave your answer in the form k 10 . Find the equation of the line through A and B, giving your answer in the form ax + by + c = 0 where a, b and c are integers. Find the area of the triangle with vertices at (0, β2), (0, 6) and (β2, β3)
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BHASVIC MΞ±THS 5 A1 DOUBLES AssIGNMENT 2A
The functions f and g are defined as for π₯ββ π π₯ =π₯2β4π₯+1 π π₯ =π₯+1 (a) The function β π₯ is defined as π π₯ +π(π₯) for π₯ββ . Show that β π₯ =π₯2β3π₯+2 (b) Write β π₯ in the form π₯βπ 2βπ where p and q are constants to be found. (c) Using the completed square form sketch the graph of π¦=β π₯ showing all the coordinates where the graph crosses the axes. (d) Write down the coordinates of the turning point and the equation of the line of symmetry.
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BHASVIC MΞ±THS 6 A1 DOUBLES AssIGNMENT 2A
In βπππ
, ππ= π₯+2 cm, ππ
= 5βπ₯ cm and β πππ
=30Β°. The area of the triangle is π΄ cm 2 . (a) Show that π΄= 1 4 (10+3π₯β π₯ 2 ). (b) Use the method of completing the square, or otherwise, to find the maximum value of A, and give the corresponding value of x.
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BHASVIC MΞ±THS 7 A1 DOUBLES AssIGNMENT 2A π π₯ =(π₯β1)(π₯β2)(π₯+1).
State the coordinates of the point at which the graph of π¦=π(π₯) intersects the y-axis. The graph of π¦=ππ(π₯) intersects the y-axis at (0,-4). Find the value of a. The graph of π¦=π(π₯+π) passes through the origin. Find three possible values of b.
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3 π₯ = 9 1βπ¦ π₯ 2 +4 π¦ 2 =4 Solve the simultaneous equations:
BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 8 Solve the simultaneous equations: 3 π₯ = 9 1βπ¦ π₯ 2 +4 π¦ 2 =4
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Solve the following simultaneous equations: π₯ 2 β π¦ 2 +5π₯=41 5π¦β4π₯=1
BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 9 Solve the following simultaneous equations: π₯ 2 β π¦ 2 +5π₯=41 5π¦β4π₯=1
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 10
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 11 The points A and C lie on the y-axis and the point B lies on the x-axis as shown in the diagram below. The line through points A and B is perpendicular to the line through points B and C. Find the value of c.
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 12 These sketches are graphs of quadratic functions in the form π¦=π π₯ 2 +ππ₯+π. Find the values of a,Β b,Β andΒ c for each function:
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BHASVIC MΞ±THS 13 A1 DOUBLES AssIGNMENT 2A
A circle with centre (a,b) and radius r has equation π₯βπ π¦βπ 2 = π 2 . Use this to answer the following questions: (i) Write down the equation of each circle: (a) Centre 3,2 , radius 4 (b) Centre β4,5 , radius 6 (c) Centre (5,β6), radius 2 3 (d) Centre 2π,7π , radius 5π (e) Centre β2 2 ,β3 2 , radius 1 (ii) By completing the square in the π₯ terms and the π¦ terms, write the following circle equations in the form π₯βπ π¦βπ 2 = π 2 , and hence state the centre and radius: (a) π₯ 2 + π¦ 2 β2π₯+8π¦β8=0 (b) π₯ 2 + π¦ 2 +12π₯β4π¦=9 (c) π₯ 2 + π¦ 2 β6π¦=22π₯β40 (d) π₯ 2 + π¦ 2 +5π₯βπ¦+4=2π¦+8 (e) 2 π₯ 2 +2 π¦ 2 β6π₯+5π¦=2π₯β3π¦β3
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 14
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BHASVIC MΞ±THS 1 - Answers A1 DOUBLES AssIGNMENT 2A
U shaped parabola. Cuts axes at 1,0 , 4,0 , 0,16 . Turning point ,β9 . Line of symmetry π₯= 5 2 U shaped parabola. Cuts axes at ,0 , β 2 5 ,0 , 0,β Turning point β 1 10 ,β Line of symmetry π₯=β 1 10 β© shaped parabola. Cuts axes at 5Β± 26 ,0 , 0,1 . Turning point 5,26 . Line of symmetry π₯=5
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BHASVIC MΞ±THS 2 - Answers A1 DOUBLES AssIGNMENT 2A
In the library computers you can plot the graphs on βautographβ. On your phone you could use the free app βdesmosβ. Or, use your graphical calculator to check. It is important you try these yourself first, donβt go straight to the answers!
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 3 - Answers Proof
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BHASVIC MΞ±THS 4 - Answers A1 DOUBLES AssIGNMENT 2A ( 1, 6) 2 10
2 10 π₯β3π¦+17=0 8
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BHASVIC MΞ±THS 5 - Answers A1 DOUBLES AssIGNMENT 2A b) π= 3 2 , π=β 1 4
(c) U shaped parabola, cuts x axis at (1,0) and (2,0), cuts y axis at (0,2) (d) TP , β1 4 line of symmetry is π₯= 3 2
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BHASVIC MΞ±THS 6 - Answers A1 DOUBLES AssIGNMENT 2A
π΄= , when π₯=1.5
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 7 - Answers (0,2) -2 -1,1,2
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 8 - Answers (0,1), (2,0)
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 9 - Answers
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 10 - Answers
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 11 - Answers π=β 9 4
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BHASVIC MΞ±THS 12 - Answers A1 DOUBLES AssIGNMENT 2A
(a) π = 1, π = β8, π = 15 (b) π = β1, π = 3, π = 10
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ii) (a) Centre (1,β4), radius 5 (b) Centre β6,2 , radius 7
BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 13 - Answers i) (a) π₯β π¦β2 2 =16 (b) π₯ π¦β5 2 =36 (c) π₯β π¦+6 2 =12 (d) π₯β2π π¦β7π 2 =25 π 2 (e) π₯ π¦ =1 ii) (a) Centre (1,β4), radius 5 (b) Centre β6,2 , radius 7 (c) Centre (11,3), radius 3 10 (d) Centre β 5 2 , 3 2 , radius (e) Centre (2,β2), radius
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BHASVIC MΞ±THS A1 DOUBLES AssIGNMENT 2A 14 - Answers
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