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2Na(s) + 2H2O  2NaOH(aq) + H2(g)

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Presentation on theme: "2Na(s) + 2H2O  2NaOH(aq) + H2(g)"— Presentation transcript:

1 2Na(s) + 2H2O  2NaOH(aq) + H2(g)
Solutions Solution - A homogeneous mixture of substances that consists of a solvent and one or more solutes. Solvent - Generally the most abundant substance in a solution. Solute - The impurity in a solution and less abundant than the solvent. Dissolution Dissolution - The formation of a solution by the addition of a solute to a solvent. This may occur with or without reaction. Solvation - Dissolution without the occurrence of a reaction. 2Na(s) + 2H2O  2NaOH(aq) + H2(g) H2O NaCl(s)  NaCl(aq)

2 Ease of Dissolution Two factors that affect the ease of dissolution:
1) The change in energy (enthalpy) 2) The change in order (entropy) Dissolution is favored by exothermic processes that increase disorder Interactions that favor dissolution 1) weak solute-solute intermolecular interactions 2) weak solvent-solvent intermolecular interactions 3) strong solvent-solute intermolecular interactions

3 (page 544) Enthalpy of solution - Hsol - The heat involved in the solvation of a solute. Generally dissolution accompanies an increase in disorder so, endothermic dissolutions can occur spontaneous depending on the magnitude of Hsol.

4 Solvation of solids Crystal lattice energy (solute-solute) - The energy change involved in the formation of one mole of formula units in a crystalline state from it’s particles in the gaseous state. (always exothermic) Na+(g) + Cl-(g) NaCl(s) + heat Hsol = (heat of solvation) - (crystal lattice energy) Hydration - Solvation where the solvent is water. The larger the ion the more waters hydrate it (4-9 waters, 6 average)

5 Dissolution of liquids
miscibility - the ability of one liquid to dissolve in another. Polar liquids tend to dissolve in polar liquids Non-polar liquids tend to dissolve in non-polar liquids The dissolution of liquids is generally exothermic

6 Dissolution of gases in liquids
Gases that are capable of hydrogen bonding or ionize are generally soluble in water (HF, HCl, HBr ...) Some non-polar gases are slightly soluble in water O2 due to dispersion forces between O2 and H2O CO2 due to reaction CO2(g) + H2O  H2CO3 H2CO3  HCO3- + H+ HCO3-  CO H+ An increase in pressure increases the solubility of a gas

7 Effect of temp. on solubility
Exothermic: reactant  product + heat Endothermic: reactant + heat  product negative Hsol (exothermic) solubility decreases with increasing temp. positive Hsol (endothermic) solubility increases with increasing temp. gas dissolutions in liquid are exothermic soda goes flat at room temperature faster than in the refrigerator (Don’t put your fish tank near a window... )

8 m = mol of solute/kg of solvent (mol/kg)
Molality molality - moles of solute per 1 kg of solvent. m = mol of solute/kg of solvent (mol/kg) Why molality instead of molarity? Molality is used when there is a change in temperature involved because it is temperature invarient. Molarity (moles/L) is dependent on the volume which changes with a change in temperature. What is the molality of a solution prepared from 50 g of sucrose (C12H22O11) and 117g of water? m = (50g sucrose * 1mol/342g sucrose)/0.117 kg H2O = 1.25 m

9 Mole Fraction Mole Fraction of A - XA = moles of A/total moles
dimensionless quantity What is the mole fraction of CH3OH and H2O in a solution composed of 128 g CH3OH and 108 g H2O? mol CH3OH = 128gCH3OH * (1 mol/32.0gCH3OH) = 4.00 mol CH3OH mol H2O = 108 g H2O * (1 mol/18.0 g H2O) = 6.00 mol H2O XCH3OH= 4.00 mol/(4.00 mol mol) = 0.400 XH2O = 6.00 mol/(4.00 mol mol) = 0.600 The mole fraction of all species in a solution add up to 1


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