1. Substitution – Without Indices – Foundation – GCSE Questions
These questions are the same format as previous GCSE exams.
COPY means they use the exact same numbers as the original GCSE question.
Otherwise, they are clone questions using different numbers.
The worksheets are provided in a variety of sizes.

2. Printing To print handouts from slides -
Select the slide from the left. Then click:
File > Print > ‘Print Current Slide’
To print multiple slides -
Click on a section title to highlight all those slides,
or press ‘Ctrl’ at the same time as selecting slides to
highlight more than one. Then click:
File > Print > ‘Print Selection’
To print double-sided handouts -
Highlight both slides before using ‘Print Selection’.
Choose ‘Print on Both Sides’ and ‘Flip on Short Edge’.

3. GCSE GCSE GCSE GCSE Edexcel Foundation: May 2017 Paper 1, Q16
v = u + at
u = 2 a = t = 1 5 1
v = u + at
u = 2 a = t = 1 5
𝑣 =
𝑣 =
(Total for Question 1 is 2 marks)
(Total for Question 1 is 2 marks) 2
g = p - bw
g = 4 b = w = 1 2 2
g = p - bw
g = 4 b = w = 1 2
𝑔 =
𝑔 =
(Total for Question 2 is 2 marks)
(Total for Question 2 is 2 marks)
GCSE
Edexcel Foundation: May 2017 Paper 1, Q16
GCSE
Edexcel Foundation: May 2017 Paper 1, Q16 1
v = u + at
u = 2 a = t = 1 5 1
v = u + at
u = 2 a = t = 1 5
𝑣 =
𝑣 =
(Total for Question 1 is 2 marks)
(Total for Question 1 is 2 marks) 2
g = p - bw
g = 4 b = w = 1 2 2
g = p - bw
g = 4 b = w = 1 2
𝑔 =
𝑔 =
(Total for Question 2 is 2 marks)
(Total for Question 2 is 2 marks)

5. GCSE GCSE GCSE GCSE Edexcel Foundation: June 2017 Paper 3, Q11
P = 5g + 4
(a) Work out the value of P when g = 3 1
P = 5g + 4
(a) Work out the value of P when g = 3
(2)
(2)
(b) Make g the subject of the formula P = 5g + 4
(b) Make g the subject of the formula P = 5g + 4
(2)
(2)
(Total for Question 1 is 4 marks)
(Total for Question 1 is 4 marks)
GCSE
GCSE
Edexcel Foundation: June 2017 Paper 3, Q11
Edexcel Foundation: June 2017 Paper 3, Q11 1
P = 5g + 4
(a) Work out the value of P when g = 3 1
P = 5g + 4
(a) Work out the value of P when g = 3
(2)
(2)
(b) Make g the subject of the formula P = 5g + 4
(b) Make g the subject of the formula P = 5g + 4
(2)
(2)
(Total for Question 1 is 4 marks)
(Total for Question 1 is 4 marks)

7. GCSE GCSE GCSE GCSE Edexcel Foundation: May 2018 Paper 1, Q16
T = 3x + 4y
x = 5
y = − 3
(a) Work out the value of T. 1
T = 3x + 4y
x = 5
y = − 3
(a) Work out the value of T.
(2)
(2)
(b) Expand 3g(g + 3)
(b) Expand 3g(g + 3)
(2)
(2)
(c) Solve 4(b − 3) = 36
(c) Solve 4(b − 3) = 36
b =
b =
(2)
(2)
(Total for Question 1 is 6 marks)
(Total for Question 1 is 6 marks)
GCSE
GCSE
Edexcel Foundation: May 2018 Paper 1, Q16
Edexcel Foundation: May 2018 Paper 1, Q16 1
T = 3x + 4y
x = 5
y = − 3
(a) Work out the value of T. 1
T = 3x + 4y
x = 5
y = − 3
(a) Work out the value of T.
(2)
(2)
(b) Expand 3g(g + 3)
(b) Expand 3g(g + 3)
(2)
(2)
(c) Solve 4(b − 3) = 36
(c) Solve 4(b − 3) = 36
b =
b =
(2)
(2)
(Total for Question 1 is 6 marks)
(Total for Question 1 is 6 marks)

11. GCSE Edexcel Foundation: May 2018 Paper 1, Q16 1 T = 3x + 4y x = 5
(a) Work out the value of T.
(2)
(b) Expand 3g(g + 3)
(2)
(c) Solve 4(b − 3) = 36
b =
(2)
(Total for Question 1 is 6 marks)

12. v = 2 + (-4 x 1 5 ) = 2 + ( −4 5 ) = 2 – 0.8 1.2 g = 4 - (-3 x 1 2 )
GCSE
Edexcel Foundation: May 2017 Paper 1, Q16
v = 2 + (-4 x 1 5 )
= 2 + ( −4 5 ) = 2 – 0.8 1
v = u + at
u = 2 a = t = 1 5
1.2
𝑣 =
(Total for Question 1 is 2 marks)
g = 4 - (-3 x 1 2 )
= 4 - ( −3 2 ) = 4 – – 1.5 2
g = p - bw
g = 4 b = w = 1 2
5.5
𝑔 =
(Total for Question 2 is 2 marks)

13. 𝑃−4 5 = g GCSE P = (5x3) + 4 = 15 + 4 19 = 19 𝑃−4 = 5g 𝑔= 𝑃−4 5
Edexcel Foundation: June 2017 Paper 3, Q11 1
P = 5g + 4
(a) Work out the value of P when g = 3
P = (5x3) + 4 =
= 19 19
(2)
(b) Make g the subject of the formula P = 5g + 4
𝑃−4 = 5g
𝑃−4 5 = g
𝑔= 𝑃−4 5
(2)
(Total for Question 1 is 4 marks)

14. T = (3×5) + (4×-3) T = (15) + (-12) T = 3 3g2+9g 4b – 12 = 36 4b = 24
GCSE
Edexcel Foundation: May 2018 Paper 1, Q16 1
T = 3x + 4y
x = 5
y = − 3
(a) Work out the value of T.
T = (3×5) + (4×-3)
T = (15) + (-12)
T = 3
(2)
(b) Expand 3g(g + 3)
3g2+9g
4b – 12 = 36
(2)
(c) Solve 4(b − 3) = 36
4b = 24 6
b = 6
b =
(2)
(Total for Question 1 is 6 marks)

15. tom@goteachmaths.co.uk Questions? Comments? Suggestions?
…or have you found a mistake!?
Any feedback would be appreciated .
Please feel free to