1. Five-Minute Check (over Lesson 10–2) Then/Now Theorem 10.2
Proof: Theorem 10.2 (part 1)
Example 1: Real-World Example: Use Congruent Chords to Find Arc Measure
Example 2: Use Congruent Arcs to Find Chord Lengths
Theorems
Example 3: Use a Radius Perpendicular to a Chord
Example 4: Real-World Example: Use a Diameter Perpendicular to a Chord
Theorem 10.5
Example 5: Chords Equidistant from Center
Lesson Menu

2. A. 105
B. 114
C. 118
D. 124
5-Minute Check 1

3. A. 35
B. 55
C. 66
D. 72
5-Minute Check 2

4. A. 125
B. 130
C. 135
D. 140
5-Minute Check 3

5. A. 160
B. 150
C. 140
D. 130
5-Minute Check 4

6. A. 180
B. 190
C. 200
D. 210
5-Minute Check 5

7. Dianne runs around a circular track that has a radius of 55 feet
Dianne runs around a circular track that has a radius of 55 feet. After running three quarters of the distance around the track, how far has she run?
A ft
B. 165 ft
C ft
D ft
5-Minute Check 6

8. Splash Screen

9. TARGETS 10-3 Arcs and Chords (Pg. 701)
Recognize and use relationships between arcs and chords.
Recognize and use relationships between arcs, chords, and diameters.
Then/Now

10. Content Standards Mathematical Practices 4 Model with mathematics.
G-C.2 Identify and describe relationships among inscribed angles, radii, and chords.
G-CO.12 Make formal geometric constructions with a variety of tools and methods (compass and straightedge, string reflective devices, paper folding, dynamic geometric software, etc.).
G-MG.3 Apply geometric methods to solve design problems (e.g., designing an object or structure to satisfy physical constraints or minimize cost; working with typographic grid systems based on ratios).
Mathematical Practices
4 Model with mathematics.
1 Make sense of problems and persevere in solving them.
Then/Now

11. Recognize and use relationships between arcs and chords.
You used the relationships between arcs and angles to find measures. (Lesson 10–2)
Recognize and use relationships between arcs and chords.
Recognize and use relationships between arcs, chords, and diameters.
Then/Now

12. Concept

13. Concept

14. Use Congruent Chords to Find Arc Measure
Jewelry A circular piece of jade is hung from a chain by two wires around the stone. JM  KL and = 90. Find
Example 1

15. Use Congruent Chords to Find Arc Measure
Example 1

16. A. 42.5
B. 85 C
D. 170
Example 1

17. Use Congruent Arcs to Find Chord Lengths
Example 2

18. WX = YZ Definition of congruent segments 7x – 2 = 5x + 6 Substitution
Use Congruent Arcs to Find Chord Lengths
WX = YZ Definition of congruent segments
7x – 2 = 5x + 6 Substitution
7x = 5x + 8 Add 2 to each side.
2x = 8 Subtract 5x from each side.
x = 4 Divide each side by 2.
So, WX = 7x – 2 = 7(4) – 2 or 26.
Answer: WX = 26
Example 2

19. A. 6
B. 8
C. 9
D. 13
Example 2

20. Concept

21. Use a Radius Perpendicular to a Chord
Answer:
Example 3

22. A. 14
B. 80
C. 160
D. 180
Example 3

23. Use a Diameter Perpendicular to a Chord
CERAMIC TILE In the ceramic stepping stone below, diameter AB is 18 inches long and chord EF is 8 inches long. Find CD.
Example 4

24. Step 1 Draw radius CE. This forms right ΔCDE.
Use a Diameter Perpendicular to a Chord
Step 1 Draw radius CE.
This forms right ΔCDE.
Example 4

25. Use a Diameter Perpendicular to a Chord
Step 2 Find CE and DE.
Since AB = 18 inches, CB = 9 inches. All radii of a circle are congruent, so CE = 9 inches.
Since diameter AB is perpendicular to EF, AB bisects chord EF by Theorem So, DE = (8) or 4 inches. __ 1 2
Example 4

26. Step 3 Use the Pythagorean Theorem to find CD.
Use a Diameter Perpendicular to a Chord
Step 3 Use the Pythagorean Theorem to find CD.
CD2 + DE2 = CE2 Pythagorean Theorem
CD = 92 Substitution
CD = 81 Simplify.
CD2 = 65 Subtract 16 from each side.
Take the positive square root.
Answer:
Example 4

27. In the circle below, diameter QS is 14 inches long and chord RT is 10 inches long. Find VU.
Example 4

28. Concept

29. Chords Equidistant from Center
Since chords EF and GH are congruent, they are equidistant from P. So, PQ = PR.
Example 5

30. PQ = PR 4x – 3 = 2x + 3 Substitution x = 3 Simplify.
Chords Equidistant from Center
PQ = PR
4x – 3 = 2x + 3 Substitution
x = 3 Simplify.
So, PQ = 4(3) – 3 or 9
Answer: PQ = 9
Example 5

31. A. 7
B. 10
C. 13
D. 15
Example 5

32. End of the Lesson