1. Projectiles at an Angle
IB Physics | Unit 2 | Motion

2. Reminder of our Equations
Units m
m s-1
m s-2 s
𝑣=𝑢+𝑎𝑡 𝑢 𝑣 𝑎 𝑡
𝑠=𝑢𝑡 𝑎 𝑡 2 𝑠
𝑣 2 = 𝑢 2 +2𝑎𝑠
𝑠= 𝑣+𝑢 𝑡 2

3. 2-D Problem Solving Steps
Start with “suvat” in the vertical direction and pretend it’s just a freefall problem
The air time is the same for horizontal motion
Solve for horizontal using v = s/t
Vertical Only 𝑠 𝑢 𝑣 𝑎 𝑡

4. Remember Vectors? vx vy
v = 24 m s-1 vy
55° vx

5. One Dimensional Motion

6. Horizontal Projectile
Vertical Only 𝑠 𝑢 𝑣 𝑎 𝑡

7. Two Dimensional Projectile

8. Projectile – First Half
vx =
1st Half Vertical 𝑠 𝑢 𝑣 𝑎 𝑡
vy =
24 m s-1
55°
24 m s-1
19.7 m s-1
55°
13.8 m s-1

9. Projectile – Full Thing
𝑇𝑜𝑡𝑎𝑙 𝑇𝑖𝑚𝑒
𝐷𝑖𝑠𝑝𝑙𝑎𝑐𝑒𝑚𝑒𝑛𝑡 𝑥
24 m s-1
55°
24 m s-1
19.7 m s-1
55°
13.8 m s-1

10. Projectile – In General
vx =
1st Half Vertical 𝑠 𝑢 𝑣 𝑎 𝑡
vy = u uy θ ux
𝑇𝑜𝑡𝑎𝑙 𝑇𝑖𝑚𝑒
𝐷𝑖𝑠𝑝𝑙𝑎𝑐𝑒𝑚𝑒𝑛𝑡 𝑥

11. Try This… 𝑠 𝑢 𝑣 𝑎 𝑡 1st Half Vertical vx = 30 m s-1 vy = 24°
You hit a baseball at 24° above the horizontal as a speed of 30 m s-1. How far does the ball travel before it hits the ground?