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X-Ray Diffraction Path Length Phase Difference

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Presentation on theme: "X-Ray Diffraction Path Length Phase Difference"— Presentation transcript:

1 X-Ray Diffraction Path Length Phase Difference
For a new atom in a unit cell yb xa

2 Diffraction angle: 2 d sin =  sin = /2d Bright spot  d (h,k,l)

3 Reflection from plane through new atom Planes at same angle 


4 New plane at spacing  = (hx + ky + lz) d 

5 Extra path length: x =  sin On each side  sin   sin

6  sin  sin Extra path length: x = 2  sin
But sin = /2d Bragg spot x = /d  sin x  sin

7  phase difference: 2 radians in one  x 2/ = 2 /d   sin 

8 phase difference:  = 2 (hx + ky + lz)  sin   sin

9 e e phase difference:  = 2 (hx + ky + lz)  2ix/  sin 

10 e e e phase difference:  = 2 (hx + ky + lz)  2ix/  sin 2ix/
2i(hx+ky+lz)  sin

11 Systematic Extinctions
yb Body Centered Cubic x = ½ y = ½ z = ½  = 2 (hx + ky + lz) = n with n odd  = 2 (h/2 + k/2 + l/2) = n xa

12 Systematic Extinctions
yb xa Body Centered Cubic (1,1,1):  = 2 (1/2 + 1/2 + 1/2) (1,1,1):  = 3 waves cancel h + k + l = even for reflection to appear


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