1. 1) Given: vf = vi + at vi = 0 m/s vf = -58.8 m/s t = 6 s a = -9.8 m/s2
58.8 m/s down
2) Given:
vi = 0 m/s
d = 0(3) + ½(-9.8)(3)2
d = vit +½at2
t = 3 s
d = m
a = -9.8 m/s2; -32ft/s2
d = ? m
redo with a = -32 ft/s2
If falls 44.1 m or 144 ft

2. tower is 219 ft tall; ball is moving at 118.4 ft/s down vf = vi + at
3) Given:
d = 0(3.7) + ½(-32)(3.7)2
d = vit +½at2
vi = 0 ft/s
d = -219 ft
t = 3.7 s
a = -32 ft/s2
vf = vi + at
d = ? ft
vf = ft/s
vf = ? ft/s
vf = 0 + (-32)(3.7)
tower is 219 ft tall; ball is moving at ft/s down
vf = vi + at
4) Given:
vf = -116 ft/s
vi = -20 ft/s
vf = (-32)(3)
t = 3 s
a = -32 ft/s2
d = vit +½at2
d = (-20)(3) + ½(-32)(3)2
vf = ? ft/s
d = ? ft
d = -204 ft
ball is moving at 116 ft/s down and fell 204 ft

3. 5) 45.2 ft/s down 6)12.2 s; 735 m 7) 172 ft; 3.3 s 8) 49 ft
2d = (vf + vi)t
vf = vi + at
d = vit +½at2
vf2 = vi2 + 2ad