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Applied Statistical and Optimization Models
Topic 06-01: Basic Probability Concepts
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Objectives Approaches to probability: Classical, Empirical, Subjective
Probability rules for events and their complements Probability rules for unions of mutually and non-mutually exclusive events Probability rules for intersections of dependent and independent events
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Probability Approaches to Probability Classical Approach
A priori information is give For example: Probability of rolling a “six” with a fair dice is P(“six”) = 1/6 Empirical Approach No a priori information is given Probability needs to be gauged by empirical work For example: A survey of 100 randomly selected students revealed that 60% use the gym regularly. We therefore assume that there is a 60% chance that a randomly selected student goes to the gym regularly. Subjective Approach Empirical work not possible Therefore only applicable to singular events For example: Outcome of a boxing fight between two first time opponents. Most of this chapter is concerned with the classical approach.
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Probability Mutually and Non-Mutually Exclusive Events
Mutually exclusive: Rolling a “1” and a “six” in a single dice roll are mutually exclusive events. Non mutually exclusive: Rolling an odd number and a number less than 5 are not mutually exclusive events. A Venn diagram for two mutually exclusive events A Venn diagram for two non-mutually exclusive events
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Probability Probability of mutually exclusive events
Example: What’s the probability of getting a “5” or “6” in a single roll dice? N(A) = Set of number of events for which we want to know the probability A={5,6} N(A) = 2 N(S) = Set of all possible events S = {1,2,3,4,5,6} N(S) = 6
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Probability Probability of complements
The sum of the probability of event A to occur and event A not to occur (A’) must be equal to one: P(A)+P(A’)=1. A’ is the complement of A (Read: A prime is the complement of A). Or, N(A)+N(A’)=N Example: A bowl has 10 chocolate squares, 6 dark and 4 milk chocolate squares. In this case, the complementary event to drawing a dark chocolate square is drawing a milk chocolate square. A Venn diagram for event A and its complement “not A” (A’).
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Probability Unions and the Addition Rule
A ∪ B - read “A union B” (or “A OR B”) P(A ∪ B) = P(A)+P(B) if A and B are mutually exclusive P(A ∪ B) = P(A)+P(B)–P(A ∩ B) if A and B are not mutually where P(A ∩ B) reads “A intersection B” (or “A AND B”)
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Probability Example: Unions and the Addition Rule for mutually-exclusive events Example for a union of mutually exclusive events: What’s the probability of drawing a “Jack” or a “Queen” in a random drawing from a deck of cards? Answer: P(Jack ∪ Queen) = P(Jack)+P(Queen) = 4/52+4/52=8/52=2/13 Example: Unions and the Addition Rule for non mutually-exclusive events Example for a union of non mutually exclusive events: What’s the probability of drawing a “Queen” or a “Heart” in a random drawing from a deck of cards? Answer: P(Queen ∪ Heart) = P(Queen)+P(Heart)-P(Queen of Heart) = 4/52+13/52-1/52=16/52=4/13
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Probability Intersections and the Multiplication Rules
A B “The intersection of A and B” P(AB) = P(A)∙ P(B) if A and B are independent P(AB) = P(A)∙ P(B|A) if B depends on A where P(B|A) is the probability of B given that A has occurred. Test for Independence of two events Two events are independent if P(A)∙ P(B) = P(A)∙ P(B|A), which, of course simplifies to P(B) = P(B|A) where P(B|A) is the probability of B given that A has occurred.
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Probability Example: Two independent events: The probability of rolling a “six” in the first and rolling a “six” in the second roll of a dice Answer: P(“Six””Six”) = P(“Six”)∙ P(“Six”)=1/6∙1/6=1/36 Example for two dependent events: A candy jar contains three dark chocolate squares and two milk chocolate squares. What is the probability that in two drawings without replacement both milk chocolate squares are selected? Answer: P(“First is Milk””Second is Milk”) = P(“First is Milk”)∙P(“Second is Milk”|”First was Milk”) = 2/5 ∙ 1/4 = 2/20=1/10
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