Download presentation
Published byAntwan Surman Modified over 10 years ago
1
Looking at position, velocity, and acceleration from the integral.
Straight Line Motion Looking at position, velocity, and acceleration from the integral.
2
What does s(t), v(t), and a(t) mean? How are they connected?
3
1) a(t) = 4t – 6 and the initial velocity is 3, find v(t).
4
2) a(t) = sin t + 2t and the initial velocity is 5, find v(t).
5
Displacement and Distance
80 miles to the right then turn around … Go 30 miles back Displacement = 80 – 30 or 50 miles Distance = or 110 miles Can displacement equal distance? How?
6
Displacement and Distance
80 miles to the right then turn around … Go 30 miles back Given a particle moving on a straight line with velocity v(t) between time t = a and time t = b then . . .
7
3) A particle is moving along a straight line with velocity v(t) = t2 – 7t +10 ft/sec. Find the displacement and distance on the interval [1, 7]
8
3) A particle is moving along a straight line with velocity v(t) = t2 – 7t +10 ft/sec. Find the displacement and distance on the interval [1, 7]
10
Given an object moving in a straight line with
v(0) = -18, t = 0 to t =16. Find v(t) and the displacement and distance of the object.
11
5) A subway train accelerates as it leaves one station, then decelerates as it comes into the next station. The following chart measures the velocity v given in miles per hour. a) Find the distance the train travels every 5 second interval.
12
5) A subway train accelerates as it leaves one station, then decelerates as it comes into the next station. The following chart measures the velocity v given in miles per hour. b) Find the total distance between subway stops.
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.