SPSS Session 3: Finding Differences Between Groups

Name: SPSS Session 3: Finding Differences Between Groups
Uploaded: 2017-09-09T13:37:47+00:00
Duration: PTM27S39
Channel: Karli Gravley
Description: SPSS Session 3: Finding Differences Between Groups

SPSS Session 3: Finding Differences Between Groups

Learning Objectives Review Lectures from 8 and 9
Understand how to test for differences between two or more groups Describe the relationship between variability and standard deviation of means Be able to conduct t-tests and ANOVAs within SPSS From the statistical output, be able to discuss results of analyses using t-tests and ANOVAs

Review of Lecture 8 Defined and discussed the theory and rules of probability Calculated probability and created a probability distribution with example data Described the characteristics of a normal curve and interpreted a normal curve using example data

Review from Lecture 9 Defined research hypothesis, null hypothesis and statistically significance Discussed the basic requirements for testing the difference between two means Defined and described the difference between the alpha value and P value, and Type I and Type II errors Calculated the difference between the means (t-ratio) using example data through advanced study

Testing for Differences between Groups
Often times in social work research, we wish to know if the differences between two groups is significant. No two groups of people are alike, but are their dissimilarities important? That is to say, are the differences significant or did these differences likely happen by chance? Think about comparing p-value to α.

Testing for differences between groups of people on some score or measure is reliant on: The average scores for each group on that measure (mean scores) The variability of each group’s scores on that measure (standard deviation scores) Mean and standard deviation scores are very important when comparing groups

Standard Deviation Scores
Standard Deviation (SD) is an important piece of statistical information Stand Deviation scores indicate the extent to which the data cluster around the mean of a distribution. It is the most common score of “data dispersion” and variability in a particular variable. It is often reported in studies with the mean: Example, “children in the study were 7.69 years of age on average (SD=4.85)”.

Deviation Scores Deviation is the amount that an individual score is different from the mean score for that variable. Recall that the children in the study were on average (mean) 7.69 years of age. Deviation scores for specific cases then would be: A child that is 10 years old would deviate from the mean by 2.31 years ( =2.31) A child that is 3 years old would deviate from the mean by years ( = -4.69)

Standard Deviation Scores
Standard Deviation scores (SD) are the square root of sum of all squared deviation scores for all individuals and divided by the total number of individuals minus one.

Standard Deviation Scores and Variability
Standard Deviation Scores (SD) are important as they give information about how closely the values in a distribution cluster around the mean. Essentially, this is how much scores in a variable actually vary! The next three slides demonstrate the variability. Watch for the Standard Deviation Scores and changes in the histograms.

Histogram with Large SD scores
Mean = 50 SD = 30

Histogram with Medium SD scores
Mean = 50 SD = 14

Histogram with SD scores of 0
Mean = 50 SD = 0 (no variability)

Group Differences in Child Protection
In our child protection study, we wanted to for differences between two groups of parents. All parents completed the General Health Questionnaire, and were categorized as having clinically scores or not. Clinically elevated scores are those where the parents likely are experiencing severe psychiatric stress.

Group Differences in Child Protection
We hypothesized that there would be significant differences between these two groups of parents on their mean scores on the Family Environment Scale (FES) and the Strengths and Difficulty Questionnaire (SDQ). The FES concerns three aspects of their social environment in their home: Family Cohesion, Family Expressiveness, and Family Conflict. The SDQ total score concerns the parents’ views of the behaviour and social problems experienced by their child.

In order to test for differences between two groups based on their mean scores on a measure, we use a statistical test called a t-test. t-tests use one nominal independent variable (IV) and one interval/ratio dependent variable (DV) In this case: GHQ groups (IV): Clinically elevated scores and not clinically elevated groups (one variable with two groups) FES and SDQ scores (DV): interval/ratio level variables

T-tests Hypotheses We hypothesized (research hypothesis) that there would be significant differences between these two groups of parents on their mean scores on the Family Environment Scale (FES) and the Strengths and Difficulty Questionnaire (SDQ). Parents reporting greater stress would also have higher FES and SDQ scores. Our null hypothesis states that there are no significant differences between these two groups of parents based on their mean scores on the FES and SDQ measures. We have the data, so time to test!

T-tests Analysis Demonstrated in SPSS
When conducting a t-test, use the “Analyze” menu and select “Compare Means”. In this case, we select “Independent Samples t-test” as the parents either have clinically elevated GHQ scores or they do not.

Firstly, we identify our DV called here as our “Test Variable(s)”.
Find “SDQ_TotalDif” in the list on the left and select it for the “Test Variable(s)”.

Next, we identify our IV and the particular groups of interest.
Select “GHQ_Cutoff_4” from the list on the left and select this variable for the “Grouping Variable”. GHQ scores use a clinical cutoff score of 4 or more, hence the variable name.

This variable is coded as the following:
Now that the IV variable is identified, we have to tell SPSS which two groups we are using in the analysis. This variable is coded as the following: 0 = "Subclinical score, 3 or less" 1 = "Clinically elevated score, 4 or more" Knowing the coding for each group, select “Define Groups…” Specify the two groups as: Group 1: 0 Group 2: 1 Click “Continue”

Identify the values for each group in the variable based on how the variable is coded.
After clicking “Continue”, the “Grouping Variable” shows the grouping numbers. Now click “OK”.

T-tests Analysis Results in SPSS
Now we see the results of the test between the two parent groups on the SDQ measure. The first table give the mean and standard deviations scores on the SDQ measure for group of parents with clinically elevated GHQ scores (42 people) and those without the elevated scores (53 people).

The mean SDQ scores for each group do not appear significantly different. The group with the elevated GHQ scores had a mean SDQ score of (SD=6.868). The group of parents without an elevated GHQ score actually had lower mean SDQ scores of (SD=7.202). We had hypothesized that parents with elevated GHQ scores would also rate their children as having more total difficulties as rated by the SDQ (research hypothesis).

To see if these results likely occurred by chance, or if there is a statistically significant difference between these two groups of parents, we look to the next table for the results of the t-test.

From the table below, we see the t-test score of t=
From the table below, we see the t-test score of t=.386 and a p-value of .701 shown here as “Sig. (2-tailed)” with 93 degrees of freedom (“df”). Because the p-value of .701 is greater than our α = .05 level of significance, we say that we failed to reject our null hypothesis. These results likely happened by chance, and we cannot confirm our research hypothesis.

Our null hypothesis stated that there were no statistically significant differences between these two groups of parents based on their SDQ means scores. From our data, this appears to be the case. SDQ scores were not significantly different (t=.386, df=93, p>.05) between parents with clinically elevated GHQ scores (mean SDQ scores of 20.38, SD=6.868) and those parents without clinically elevated GHQ scores (mean SDQ scores of 20.94, SD=7.202). Parents with increased levels of stress did not rate their children has having greater behavioural and social problems when compared to the parents reporting lower levels of stress.

T-tests Analysis in SPSS: Second Example
For a second example, we wanted to know if these same two groups of parents differed in terms of their family environment. We used the Conflict subscale of the Family Environment Scale as a measure of their family social environment. Our research hypothesis is that the group of parents with clinically elevated GHQ scores would have significantly higher FES-Conflict scores when compared to the group of parents without clinically elevated scores. Our null hypothesis stated that there is no difference between these groups of parents based on their FES-Conflict scores.

To test this second research hypothesis, we again select the “Analyze” menu and select “Compare Means”. Again, we use “Independent Samples t-test” to test for differences between to independent groups of parents.

From the window for “Independent-Samples T Test”, the previous analysis is shown. Because we are interested in testing the new DV of FES-Conflict scores, we remove “SDQ_TotalDif” from the list and replace it with “FES_Conflict” from the list on the right. The “Grouping Variable” is still set from the previous analysis and does not need changing. As the analysis is set, we click “OK” for the results.

T-tests Results in SPSS: Second Example
From the results in the output window, we see the first table with the mean and standard deviation scores for each group. We see that the mean FES-Conflict scores for the clinically elevated group (mean=5.19, SD=2.32) appears to be higher than the group of parents without clinically elevated scores (mean=3.87, SD=2.72). To find if this difference is statistically significant, we look to the next table in the output.

From the table below, we see the t-test score of t=-2
From the table below, we see the t-test score of t= and a p-value of .014 shown here as “Sig. (2-tailed)” with 93 degrees of freedom (“df”). Because the p-value of .014 is less than our α = .05 level of significance, we say that succeeded in rejecting our null hypothesis. These results were unlikely to have happened by chance, and we accept our research hypothesis.

Our null hypothesis stated that there were no statistically significant differences between these two groups of parents based on their FES-Conflict means scores. From our data, this appears not to be the case. FES-Conflict scores were significantly different (t=-2.511, df=93, p<.05) between parents with clinically elevated GHQ scores (mean FES-Conflict scores of 5.19, SD=2.32) and those parents without clinically elevated GHQ scores (mean FES-Conflict scores of 3.87, SD=2.72).

T-tests Results in SPSS: Second Example
From the results of this second t-test, we can conclude that parents with clinically elevated GHQ scores reported significantly greater amounts of social conflict in their family environments.

Analysis of Variance (ANOVA): Testing for Differences between Three or More Groups

Analysis of Variance (ANOVA)
Where T-tests look for differences between only two groups, Analysis of Variance (ANOVA) tests for similar differences between three or more groups. The independent variable is a nominal or ordinal variable with three or more categories The dependent variable is a interval/ratio variable

The null hypothesis for an ANOVA test is that the mean score for each group on a particular measure will not significant differ from any other group. The research hypothesis is usually that some group will be significant different from another group. The ANOVA test produces a statistical score called a “F-value” through a “F test”.

The logic behind the ANOVA test is that the differences within a group of people is less so than those differences between the three or more groups. ANOVA tests become a comparison of between group differences and within group differences. Hence, it is an ANALYSIS of VARIANCE between groups compared to VARIANCE within each group. T-tests are actually a mathematically simplified version of an ANOVA because it only needs to compare two groups!

The Two Parts of ANOVA First Step Second Step
ANOVA tests are conducted in two parts. The first step is to test whether any group is significantly different from any other group. This first step uses a F-test and is called an “omnibus” test meaning an “over all” test. If the F-test is significant (p<.05), it means that there is one group significantly different from another. The second part of an ANOVA is to which group(s) are different. This is called a “post hoc” test meaning “after that” Post Hoc tests can be conducted many different ways.

ANOVA Examples in Child Protection
For our child protection study, we wanted to test for differences between three groups of parents based on two different measures. Using the Previous Involvement variable, we have all of the cases categorized in one of the following ways: Cases with a history of occasional child protection involvement Cases with a long standing history of child protection involvement Cases with no history of child protection involvement

ANOVA Examples in Child Protection
Based on these three groups of parents and cases, we wanted to test for differences between them on two measures: Family Environment Scale – Family Cohesion We would expect that families with long standing or occasional involvement would have less family cohesion than families with no prior involvement with child protection services. General Health Questionnaire – Total Score We would expect that families with long standing or occasional involvement would have higher levels of psychological distress compared to families with no prior involvement with child protection services. The null hypothesis for each test is that there are no differences between the three groups of cases based on any measure or score.

ANOVA Example: 1. Family Cohesion
Testing for differences between these three groups of cases based on the FES – Cohesion scores. We need to find “Compare Means” under the “Analyze” menu. Under “Compare Means”, select “One-Way ANOVA”

Once “One-Way ANOVA” is selected a new window for ANOVA will appear

First, we need to add the Dependent Variable which is the FES – Cohesion scores to the “Dependent List”. Find this variable on the list on the left and add it to this list.

Now we need to add the Independent Variable to the “Factor” list. The Independent Variable is the groups of cases called “Previous_Involvement”

This ANOVA test will now search for differences between the three groups, but it will not yet test for where exactly the differences exist. This is the “omnibus test” portion. We need to ask the ANOVA test also to conduct the “post hoc” test to find which group or groups are significantly different from other groups. We do this by selecting a post hoc test from the “Post Hoc” option on the right.

After selecting the “Post Hoc” button, a new menu will appear. This lists all of the options for any number of post hoc tests. One of the most common post hoc tests is called the “Tukey” post hoc test. Select this test and press “Continue”

In the “Options” menu, a few more valuable pieces of the analysis need to be added to our ANOVA. The three most common are the following: “Descriptive”: provides the mean and standard deviation scores for each group in the analysis “Homogeneity of variance test”: tests a major assumption of ANOVA “Means plot”: provides a chart of each groups mean and gives a good visual of the results Click “Continue” and then “OK”

Results! The first table provides the descriptive statistics for each “previous involvement” group based on the “FES – Cohesion” measure. Importantly, this table also provides the overall descriptive statistics for the “FES – Cohesion” measure.

We can see that each “previous involvement” group has different scores on the FES – Cohesion measure. Question: Are these differences statistically significant (p<.05) or did they happen by chance (p>.05) ?

The “ANOVA” table gives the results of the F-test. The F-test is a comparison of variation in each group compared to the variation between groups. If the variation between groups is comparatively greater then the variation within the groups, then this test is more likely to be statistically significant.

The ANOVA table does give a statistically significant result. The “Sig.” value is our p-value for this test, and is well below our significant level standard of α=.05. We reject the null hypothesis.

We now know that significant differences exist between at least one group based on the FES-Cohesion scores, and that this difference was unlikely to have been due to chance. The problem is that we don’t yet know which group or groups were significantly different! Solution: This is why we need a second part which is the “Post Hoc – Tukey” test to show us exact which significant between group differences exist.

The “Multiple Comparisons” table starts to give us a picture of which groups are different.

This table shows you each group compared to every other group, and it provides a further test to show you if these two groups significantly differ.

Another table, labeled “Tukey HSD” gives you subsets of groups. If the groups have similar scores on the FES – Cohesion measure, they will appear on the same subset column. Groups that are significantly different will appear in different columns.

The “Tukey HSD” table from this analysis indicates that each group significantly differs because each sits in a separate column.

The chart at the end of the results gives us a good visualization of the mean FES – Cohesion scores for each “previous involvement” group.

ANOVA Conclusion: 1. Family Cohesion
From this analysis, we can say that each “previous involvement” group had significantly different FES – Cohesion scores (F=33.96, df= 2, 92, p<.05). We rejected our null hypothesis. Those families with long standing involvement in child protection services had significantly lower FES scores (mean = 2.23, SD = 1.64) than both the families with occasional involvement (mean = 5.10, SD = 2.21) and families with no prior involvement (mean = 7.19, SD = 2.02). Families with occasional involvement also had significantly different FES – Cohesion scores then the families with no prior involvement. We can say that families with greater previous involvement in child protection services reported that their families were less cohesive. This is an important finding concerning the family environment for these parents and children receiving services.

ANOVA Example: 2. General Health Questionnaire (GHQ)
Our finding about those families with varying degrees of previous child protection involvement raised further questions. We wanted to know if these same families, grouped by their degree of previous child protection involvement, also reported significantly different General Health Questionnaire scores (GHQ), which is a measure of psychological distress. We would expect that families with greater degrees of previous involvement would have significantly higher GHQ mean scores (research hypothesis). Our null hypothesis for this analysis would again state that no significant differences between these groups exist based on their GHQ mean scores.

ANOVA Example: 2. GHQ scores
To complete this analysis, we return to the “Analyze” menu, select “Compare Means”, and then “One-Way ANOVA”

Replace “FES_Cohesion” with “GHQ_TotalScore”

On “Post Hoc” menu, leave “Tukey” selected.

Under the “Options” button, leave these options selected. Press “Continue” and then “OK” to conduct analysis

ANOVA Results: 2. GHQ scores
The first table is the descriptive statistics for each previous involvement group and their GHQ scores. The group without previous involvement appears to have a much lower mean than the other two groups. The other two groups do not appear significantly different. The question remains if the differences between the groups is significantly different.

From the “ANOVA” table, we can see that the p-value listed under “Sig.” is well above our significance level of α=.05. In this case, we failed to reject our null hypothesis.

From the post hoc analysis, the Tukey test shows all families existing in the same subset.

Here is the chart showing the means. While there appears to be a significant visual difference, our statistical test indicates that these differences were likely to happen by chance.

GHQ scores do not significantly differ between groups of families separated by their previous involvement with child protection services (F=.516, df=2,92, p>.05). We failed to reject our null hypothesis. These differences likely happened by chance and not due to a real difference between these groups of families based on their GHQ scores. Parent and carer psychological distress, while high, appears not to be associated with previous involvement in child protection services. Perhaps families currently involved with services all experience high levels of distress regardless of the degree of prior involvement.

SPSS Session 3: Finding Differences Between Groups

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