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Binary acid (i.e. H & a non-metal) ◦ the prefix hydro is used ◦ the root of the anion is used ◦ the suffix -ic is used ◦ the word acid is used as the second word of the name Example ◦ HCl = hydrochloric acid ◦ HBr = hydrobromic acid ◦ HI = hydroiodic acid ◦ HF = hydrofluoric acid
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Polyatomic acids ◦ oxyacids: (acids with oxygen in the polyatomic anion) ◦ change suffix of –ate with -ic OR ◦ change suffix -ite to -ous ◦ These acids have the general formula H a X b O c where X = an element other than Hydrogen or Oxygen Examples ◦ HNO 3 (nitrate) (-ate -ic) ◦ HSO 3 (sulfite) (-ite -ous) ◦ H 2 SO 4 (sulfate) (-ate -ic) Nitric acid Sulfurous acid Sulfuric acid
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Strong Acid: ◦ an acid that completely dissociates into ions. ◦ (100 molecules of HCl → 100 H + ions) The six strong acids to be memorized ◦ HCl ◦ HBr ◦ HI ◦ H 2 SO 4 ◦ HNO 3 ◦ HClO 4 (Perchloric acid)
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Strong Bases ◦ a base that completely dissociates into ions. ◦ (100 formula units of NaOH → 100 OH - ions) ◦ When combined with the OH _ (hydroxide) ion, elements found in group 1 (IA) and 2 (IIA) form strong bases Examples ◦ KOH ◦ CsOH ◦ Ba(OH) 2 ◦ Ca(OH) 2
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H + (Hydrogen ion) indicates strong acid ◦ pH scale with a value of 2 or less OH - (Hydroxide ion) indicates strong base ◦ pH scale with a value of 12 or more
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Read p.271-273 Questions: P.273 #’s 29-33
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Current Assumption ◦ When strong acid and strong base are combined, all H + and OH - ions join to form HOH (H 2 O)
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Neutralization reaction is a double displacement Example ◦ For NaOH and HCl Predict the products of the reaction balance the equation ◦ NaOH (aq) + HCl (aq) NaCl + HOH ◦ Use solubility rules to confirm whether each product will be aqueous, solid or liquid ◦ NaOH (aq) + HCl (aq) NaCl ( aq) + HOH (l) ◦ Write the total ionic equation, showing all ions that are in solution
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Na + (aq) + OH - (aq) + H + (aq) + Cl - (aq) → Na + (aq) + Cl - (aq) + H 2 O (l) Cancel the spectator ions and write the net ionic equation OH - (aq) + H + (aq) → H 2 O (l)
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Example ◦ Write the molecular, ionic, net ionic equations for Sulfuric acid & potassium hydroxide H 2 SO 4 (aq) + KOH (aq) → K 2 SO 4 + HOH 2 H + (aq) + SO 4 2- (aq) + 2 K + (aq) + 2 OH - (aq) → 2 K + (aq) + SO 4 2- (aq) +2 HOH (l) 2 H + (aq) + 2 OH - (aq) → + 2 HOH (l) Simplify H + (aq) + OH - (aq) → + HOH (l) (aq)(l) 22
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Recall: ◦ Concentration is calculated as moles per litre mol/L MM ◦ [NaOH] refers to the concentration of sodium hydroxide Equation ◦ [ ] =mol/L
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In the reaction of 35.0 mL of liquid drain cleaner containing NaOH, 50.08 mL of 0.409 mol/L HCl must be added to neutralize the base. What is the concentration of the base in the cleaner? ◦ Write a balanced equation and the chart NaOH (aq) + HCl (aq) → H 2 O (l) + NaCl (aq) Mm mol V m [ ] 0.0350L0.05008L 0.409M 0.0205mol 0.586M
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Calculate the volume of 0.256 mol/L Ba(OH) 2 that must be added to neutralize 46.0 mL of 0.407 mol/L HClO 4. Ba(OH) 2(aq) + 2 HClO 4(aq) → BaCl 2(aq) + 2H 2 O (l) Mm mol V m [ ] 0.256M0.407M 0.0460L 0.0187mol0.00935mol 0.0365L
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P. 614 ◦ #’s 30-31 P. 616 ◦ #’s 32-33, 36-37 Aqueous Reactions Worksheet #1 ◦ #’s 5-7 Aqueous Reactions Worksheet #2
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