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Published bySienna Seaver Modified over 10 years ago
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+ + + + + + - - - - - - + q free on inner surface - q free on inner surface Interior points electric field must be zero - q bound + q bound Symmetry – fields must be uniform – field lines perpendicular to plates
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conductordielectric ++++ +++++ + ------ Gauss’s Law
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frequency dielectric constant
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+ + + + + + - - - - - - V = 0
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B Fe H Fe B gap H gap B air H air i coil windings gap region iron core
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width L thickness t area A q = - e electrons are the charge carriers in copper
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+ + + + + + + + + - - - - - - - - - dy F +q+q -q-q
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Induced dipole moment – helium atom -e +2e Zero electric field – helium atom symmetric zero dipole moment -e +2e -e A B effectively charge +2e at A and -2e at B dipole moment p = 2 e d
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-q-q +q+q r 1 r – (d/2)cos r 2 r + (d/2)cos r P ErEr EE (d/2)cos
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+ + + + + + + + + - - - - - - - - - +f+f -f-f dA -b-b +b+b
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+q+q -q-q
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+f+f -b-b +b+b - f O r S
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- dd r Pcos S - - + + + The area of the shaded ring between and + d is equal to
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a +Ze a d d << a
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