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Chapter 7 Algebra II Review JEOPARDY Jeopardy Review.

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Presentation on theme: "Chapter 7 Algebra II Review JEOPARDY Jeopardy Review."— Presentation transcript:

1 Chapter 7 Algebra II Review JEOPARDY Jeopardy Review

2 Logarithms Exponential Growth and Decay Exponential Functions Solving Logarithmic Equations Solving Exponential Equations 200 200 200 200 200 400 400 400 400 400 600 600 600 600 600 800 800 800 800 800 1000 1000 1000 1000 1000

3 Logarithms 200 log3 (1/9) = A: -2 Jeopardy Review

4 Logarithms 400 log .001 A: -3 Jeopardy Review

5 Use the change of base formula to evaluate: log6 21
Logarithms 600 Use the change of base formula to evaluate: log6 21 A: Jeopardy Review

6 Daily Double Jeopardy Review

7 Using the properties of logarithms, expand log (x2y/z)
A: 2 log x + log y – log z Jeopardy Review

8 Write as a single logarithm:
Logarithms 1000 Write as a single logarithm: y = 4 log m + 2 log n – 3 log k A: log (m4n2/k3) S2C13 Jeopardy Review

9 Exponential Growth & Decay 200
Identify the percent of decay in the equation: y = 6000 (.48)x A: 52% S2C13 Jeopardy Review

10 Exponential Growth & Decay 400
Write the equation that models exponential growth of 6% per year with a starting population of 22,000. A: y = 22,000 (1.06)x S2C13 Jeopardy Review

11 Exponential Growth & Decay 600
Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04)x where x represents the years after 1990. A: million S2C13 Jeopardy Review

12 Exponential Growth & Decay 800
A city’s population is modeled by the equation y = 14,000 (.98)x, where x represents the number of years after the year Predict during which year the population will decrease to 8,900. A: 2022 S2C13 Jeopardy Review

13 Exponential Growth & Decay 1000
In the equation: y = 13 (2.58)x, Identify Growth or decay Growth or decay factor Percent of growth or decay A: a) growth b) c) 158% S2C13 Jeopardy Review

14 Exponential Functions 200
Evaluate y = 2x for x = -1, 0, and 2. A: y = ½, 1, and 4 S2C13 Jeopardy Review

15 Exponential Functions 400
Write the equation to describe the exponential function with a base of 2, passing through the point (4,7). A: y = (7/16)(2)x S2C13 Jeopardy Review

16 Exponential Functions 600
Find the amount of money you have if you invest $20,000 for 5 years at 6% compounded continuously. A: 20,000 e^(.06*5) = $26,977.18 S2C13 Jeopardy Review

17 Exponential Functions 800
Find the amount of money you have if you invest $3000 for 3 years at 5% compounded continuously. A: 3000 e (.05)(3) = $ S2C13 Jeopardy Review

18 Exponential Functions 1000
You invest $2000 in an account earning 3% interest compounded continuously. How long will it be until you have $2500? A: = 2000 e (.03t) t = 7.44 years S2C13 Jeopardy Review

19 Solving Logarithmic Equations 200
2 log24 – log22 = A: log28 = 3 S2C13 Jeopardy Review

20 Solving Logarithmic Equations 400
S2C13 Jeopardy Review

21 Solving Logarithmic Equations 600
Solve for x. log 5x = 2 A: 102 = 5x x = 20 S2C13 Jeopardy Review

22 Solving Logarithmic Equations 800
Solve for x. ln 3 + ln x – ln 2 = 6 A: ln (3x/2) = x = S2C13 Jeopardy Review

23 Solving Logarithmic Equations 1000
ln x + ln (x + 3) = 2 A: ln (x2 + 3x) = x = 1.6, using quadratic formula S2C13 Jeopardy Review

24 Solving Exponential Equations 200
A: 7 or -7 S2C13 Jeopardy Review

25 Solving Exponential Equations 400
A: x = S2C13 Jeopardy Review

26 Solving Exponential Equations 600
A: x = 2.096 S2C13 Jeopardy Review

27 Daily Double

28 Solving Exponential Equations 800
4√m = 10 A: m = 16 S2C13 Jeopardy Review

29 Solving Exponential Equations 1000
A: 4x = ln 10 x = .576 S2C13 Jeopardy Review


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