1. WK 2 Homework – due Friday, 9/16
Reading assignment:
1.7 – 1.9
Posted notes on website
Reading question: 1.13; 1.16
Questions: 1.32, 31, 38, 41, 55, 59, 68 – the solutions are on the school website.
Homework – due Tuesday, 9/20 – 11:00 pm
Mastering physics wk 2

2. Vectors
A vector is a mathematical entity that possesses two properties, which physically we call magnitude and direction. displacement, velocity, acceleration, force, and momentum are vector quantities.
A scalar is a mathematical entity that has one property, magnitude, only. Temperature, mass, speed, and energy are scalar quantities. Scalars obey the familiar rules of addition, multiplication, etc.
The operation of vector include:
Addition,
Subtraction,
Multiplication
by a scalar,
by a vector:
Dot product,
Cross product

3. Two ways to represent vectors
Geometric approach
Vectors are symbolized graphically as arrows, in text by bold-face type or with a line/arrow on top.
Algebraic approach
To describe motion of an ideal particle, we choose a coordinate system, e.g. Cartesian x, y, z. The system must be an inertial coordinate system, which means it is non-accelerated. A x y o
p(x1, y1) y1 x1

4. Representing vector geometrically
If two vectors have the same size and same direction, they are equal. = = =
If two vectors have the same size but opposite direction, then we say one vector is the negative of the other.
= - A B A B

5. Adding vectors The sum of two vectors is also a vector.
Graphical method: Vectors are represented by arrows, drawn to scale. Place the tail of the 2nd vector on the head of the 1st, preserving the relative orientations. The resultant vector extends from the tail of the 1st to the head of the 2nd vector.
The sum of two vectors is also a vector.
Addition makes sense only for same kinds of vectors

6. The order of addition does not matter!

7. parallelogram
Parallelogram method
Head and tail method

8. Adding 3 or more vectors

9. Subtract vectors: adding a negative vector

10. Multiplication: scalar x vector

11. representing vector algebraically
A vector can be completely describe by its components in a coordinate system. The origin of the systems is the tail of vector
r is a position vector from the origin to the point x, y, z
The position vector r of the point P.

12. Unit vectors ^ i ^ j ^ ^ i k ^ k
A unit vector is a vector that has a magnitude of 1, with no units. Its only purpose is to point, or describe a direction in space.
Unit vector is denoted by “^” symbol.
For example:
represents a unit vector that points in the direction of the + x-axis
unit vector points in the + y-axis
unit vector points in the + z-axis ^ i y ^ j ^ j ^ i ^ k ^ k
A unit vector in any direction is represented by: x
where is the magnitude of the vector Often, the magnitude of a vector is indicated by the letter without the line on top: z

14. Any vector can be expressed with unit vectors:
A = Ax + Ay Az ^ i j k
The components Ax, Ay, Az of an arbitrary vector A.

15. In 2 dimensions

19. Addition/subtraction of vectors algebraically

20. Example: inclined plane

21. example Is the vector a unit vector?^ i j k
Is the vector a unit vector?
Can a unit vector have any components with magnitude greater than unity? Can it have any negative components?
If , where a is a constant, determine the value of a that makes A a unit vector.
A = a ( ) ^ i j

22. Example - Finding components
What is the x- and y- components of vector D in a) where the magnitude of the vector is D = 3.00 m and the angle θ = 45o?
What is the x- and y- components of vector E in b) where the magnitude of the vector is E = 4.50 m and the angle θ = 37o? y
Dx (+)
Ex (+) x
Ey (+)
θ=45o
θ=37o
Dy (-) D E x a) b) y

23. example
Let the angle θ be the angle that the vector A makes with the + x-axis, measured counter clockwise from that axis. Find the angle θ for a vector that has the following components:
Ax = 2.00 m; Ay = m
Ax = 2.00 m; Ay = 1.00 m
Ax = m; Ay = 1.00 m
Ax = m; Ay = m

24. Example – adding vectors with components
Three players on a reality TV show are brought to the center of a large, flat field. Each is given a meter stick, a compass, a calculator, a shovel, and the following three displacements;
74.4 m 32.0o east of N
57.3 m, 36.0o south of west
17.8 m straight south
The three displacement lead to the point where the keys to a new Porsche are buried. Two players start measuring immediately, but the winner first calculates where to go. What does she calculate?
R = A + B + C

26. Example – using unit vectors
Given the two displacement
B =( ) m ^ i j k
A =( ) m ^ i j k
Find the magnitude of the displacement 2A - B

27. Multiplying vectors There are two kinds of products of vectors
Scalar product or dot product, yields a result that is a scalar quantity
Vector product or cross product, yields another vector

28. Scalar product or dot product

33. Proof:

34. example

35. Application of scalar product
When a constant force F is applied to a body that undergoes a displacement d, the work done by the force is given by
W = F∙d
The work done by the force is
positive if the angle between F and d is between 0 and 90o (example: lifting weight)
Negative if the angle between F and d is between 90o and 180o (example: stop a moving car)
Zero and F and d are perpendicular to each other (example: waiter holding a tray of food while walk around)

36. Finding the angles with the scalar product
Find the dot product and the angle between the two vectors
A · B = |A||B|cosθ =
AxBx + AyBy + AzBz
|A| = √Ax2 + Ay2 + Az2
|B| = √Bx2 + By2 + Bz2
AxBx + AyBy + AzBz
|A||B|
A · B
cosθ = =
(√Ax2 + Ay2 + Az2 )(√Bx2 + By2 + Bz2 )
if cosθ is negative, θ is between 90o and 180o

37. example ? ?

38. example
Find the scalar product A∙B of the two vectors in the figure. The magnitudes of the vectors are A = 4.00 and B = 5.00 y B
130o A θ
53.0o x

39. Finding the angles with the scalar product
Find the dot product and the angle between the two vectors
A = 2i + 3j + k
B = -4i +2j - k

40. Vector product or cross product
The vector product of two vectors A and B, also called the cross product, is denoted by A x B.
The vector product is a vector. It has a magnitude and direction

41. The direction of a vector (cross) product
Place the vector tail to tail, they define the plane
A x B is perpendicular to the plane containing the vectors A and B.
It direction is determined by the right-hand rule. θ
A x B A B
A x B A B
Right-hand rule: That is, if we follow the direction of the fingers to go from the A to B, then the thumb points in the direction of A x B
B x A = - A x B θ
B x A A B θ

42. Magnitude of a vector (cross) product
A x B = ABsinθ
Where θ is the angle from A toward B, and θ is the smaller of the two possible angles.
Since 0 ≤ θ ≤ 180o, 0 ≤ sinθ ≤ 1, A x B is never negative.
Therefore, the magnitude of a vector product is never negative.
Note when A and B are in the same direction or in the opposite direction, sinθ = 0;
The vector product of two parallel or anti-parallel vectors is always zero

43. Vector product vs. scalar product
A x B = ABsinθ (magnitude)
Direction: right-hand rule-perpendicular to the A, B plane
Scalar product:
A∙B = ABcosθ (magnitude)
It has no direction.
When A and B are perpendicular to each other
AxB is maximum
A∙B is zero
When A and B are parallel
AxB is zero
A∙B is maximum

44. Calculating the vector product using components
If we know the components of A and B, we can calculate the components of the vector product.
The product of any vector with itself is zero
i x i = 0; j x j = 0; k x k = 0
Using the right hand rule and A x B = ABsinθ
i x j = -j x i = k;
j x k = -k x j = i;
k x i = - i x k = j

45. A x B = (Axi + Ayj + Azk) x (Bxi + Byj + Bzk)
= AxByk - AxBzj
– AyBxk + AyBzi
+ AzBxj - AzByi
A x B = (AyBz – AzBy) i + (AzBx - AxBz) j + (AxBy – AyBx) k
If C = A x B then
Cx = AyBz – AzBy; Cy = AzBx - AxBz; Cz = AxBy – AyBx

46. The vector product can also be expressed in determinant form asj k Ax Ay Az Bx By Bz
A x B =
- direction
+ direction
A x B =(AyBz – AzBy) i + (AzBx - AxBz) j + (AxBy – AyBx) k

47. Example 1.12
Vector A has magnitude 6 units and is in the direction of the + x-axis. Vector B has magnitude 4 units and lies in the xy-plane, making an angle of 30o with the + x-axis (fig. 1.32). Find the vector product C = A x B. y B
30o A C x z

48. example
Find the vector product A X B (expressed in unit vectors) of the two vectors given in the figure.
A (3.60 m)
70o
30o
B (2.4 m)

49. Class work - Homework – due Friday, 9/23
Reading assignment:
12.6;
Questions: 2, 7, 9, 12, 13, 22, 23, 24, 25, 29, 31, 34, 40, 44 – the solutions are on the school website.
Homework – due Tuesday, 9/20 – 11:00 pm
Mastering physics wk 3