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Angstrom Care 培苗社 Quadratic Equation II
積極推崇『我要學』的心態, 糾正『要我學』的被動心態。
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Quadratic Equations, Quadratic Functions and Absolute Values
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Solving a Quadratic Equation
by factorization by graphical method by taking square roots by quadratic equation by using completing square
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By factorization roots (solutions)
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By graphical method y roots x O
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? By taking square roots A quadratic equation must contain two roots.
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By taking square roots
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Solving a Quadratic Equation by the quadratic Formula
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By quadratic equation
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a = 1 b = -7 c = 10
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In general, a quadratic equation may have :
(1) two distinct (unequal) real roots (2) one double (repeated) real root (3) no real roots
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Two distinct (unequal) real roots
x-intercepts
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One double (repeated) real roots
x-intercept
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No real roots no x-intercept
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Nature of Roots
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△ = b2 - 4ac Since the expression b2 - 4ac can be used to determine the nature of the roots of a quadratic equation in the form ax2 – bx + c = 0, it is called the discriminant of the quadratic equation.
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Two distinct (unequal) real roots
△ = b2 - 4ac > 0 x-intercepts
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One double (repeated) real roots
△ = b2 - 4ac = 0 x-intercept
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No real roots △ = b2 - 4ac < 0 no x-intercept
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Solving a Quadratic Equation by Completing the Square
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Solving a Quadratic Equation by Completing the Square
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Relations between the Roots and the Coefficients
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If α and β(p and q, x1 and x2) are the roots of ax2 + bx + c = 0,
then sum of roots = α + β and product of roots = αβ
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Forming Quadratic Equations with Given Roots
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x = 2 or x = -3 x – 2 = 0 or x + 3 = 0 (x – 2)(x + 3) = 0
Forming Quadratic Equations with Given Roots In S.3, when α = 2 and β = -3 x = 2 or x = -3 x – 2 = 0 or x + 3 = 0 (x – 2)(x + 3) = 0 x2 + x – 6 = 0 x2 – (sum of the roots)x + (product of roots) = 0
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Linear Functions and Their Graphs
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y c>0 x O
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y x O c<0
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Linear Functions
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y m>0 c>0 c x O
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y m>0 c<0 x O c
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y c x O m<0 c>0
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y x O c m<0 c<0
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y O x c m<0 c=0
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Open upwards Open upwards (a>0) Vertex Line of symmetry
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Vertex Open downwards Line of symmetry (a>0)
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Vertex (Turning point)
Local (Relative) Maximum point (max. pt.) Local (Relative) Minimum point point (mini. pt.)
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y = ax2
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y y = ax2 (a>0) x O
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y y = ax2 + bx + c b2 - 4ac>0 2 real roots (a>0) (c<0) x roots O
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y y = ax2 + bx + c b2 - 4ac=0 repeated roots (a>0) (c>0) x root O
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y y = ax2 + bx + c B2 - 4ac<0 No real roots (a>0) (c>0) x No intercept
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mini value of the function = -1 mini point = (-2, -1)
Finding the turning point of a Quadratic Function by Completing the Square Because a = +ve, there exists a minimum point. mini value of the function = -1 mini point = (-2, -1)
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Absolute Values
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Let x be any real number. The absolute value of x, denoted by | x |, is defined as
x if x ≧ 0. -x if x < 0. eg. | 5 | = 5, | 0 | = 0, | -5 | = 5
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For all real numbers x and y,
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If | x | = a, where a ≧0, then x = a or x = -a
Generalization If | x | = a, where a ≧0, then x = a or x = -a
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Thank you
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