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ASİT. BAZ [H + ].[OH - ]=1x10 -14 pH=-log[H + ] pOH=-log[OH - ] pH + pOH=14.

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Presentation on theme: "ASİT. BAZ [H + ].[OH - ]=1x10 -14 pH=-log[H + ] pOH=-log[OH - ] pH + pOH=14."— Presentation transcript:

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6 [H + ].[OH - ]=1x10 -14 pH=-log[H + ] pOH=-log[OH - ] pH + pOH=14

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12 Prentice-Hall © 2002General Chemistry: Chapter 17Slide 12 of 47 Asit Yağmurları CO 2 + H 2 O  H 2 CO 3 H 2 CO 3 + H 2 O  HCO 3 - + H 3 O + 3 NO 2 + H 2 O  2 HNO 3 + NO

13 Prentice-Hall © 2002General Chemistry: Chapter 18Slide 13 of 42 Solutions of Weak Acids and Strong Acids Consider a solution that contains both 0.100 M CH 3 CO 2 H and 0.100 M HCl. CH 3 CO 2 H + H 2 O  CH 3 CO 2 - + H 3 O + HCl + H 2 O  Cl - + H 3 O + (0.100-x) M x M x M 0.100 M [H 3 O + ] = (0.100 + x) M essentially all due to HCl

14 Prentice-Hall © 2002General Chemistry: Chapter 18Slide 14 of 42 Acetic Acid and Hydrochloric Acid 0.1 M HCl0.1 M CH 3 CO 2 H 0.1 M HCl + 0.1 M CH 3 CO 2 H

15 Prentice-Hall © 2002General Chemistry: Chapter 18Slide 15 of 42 Suppression of Ionization of a Weak Acid

16 Prentice-Hall © 2002General Chemistry: Chapter 18Slide 16 of 42 Suppression of Ionization of a Weak Base

17 Prentice-Hall © 2002General Chemistry: Chapter 18Slide 17 of 42 Solutions of Weak Acids and Their Salts

18 Prentice-Hall © 2002General Chemistry: Chapter 18Slide 18 of 42 Solutions of Weak Bases and Their Salts

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