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Published byDaryl Anne Modified over 10 years ago
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[H + ].[OH - ]=1x10 -14 pH=-log[H + ] pOH=-log[OH - ] pH + pOH=14
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Prentice-Hall © 2002General Chemistry: Chapter 17Slide 12 of 47 Asit Yağmurları CO 2 + H 2 O H 2 CO 3 H 2 CO 3 + H 2 O HCO 3 - + H 3 O + 3 NO 2 + H 2 O 2 HNO 3 + NO
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Prentice-Hall © 2002General Chemistry: Chapter 18Slide 13 of 42 Solutions of Weak Acids and Strong Acids Consider a solution that contains both 0.100 M CH 3 CO 2 H and 0.100 M HCl. CH 3 CO 2 H + H 2 O CH 3 CO 2 - + H 3 O + HCl + H 2 O Cl - + H 3 O + (0.100-x) M x M x M 0.100 M [H 3 O + ] = (0.100 + x) M essentially all due to HCl
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Prentice-Hall © 2002General Chemistry: Chapter 18Slide 14 of 42 Acetic Acid and Hydrochloric Acid 0.1 M HCl0.1 M CH 3 CO 2 H 0.1 M HCl + 0.1 M CH 3 CO 2 H
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Prentice-Hall © 2002General Chemistry: Chapter 18Slide 15 of 42 Suppression of Ionization of a Weak Acid
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Prentice-Hall © 2002General Chemistry: Chapter 18Slide 16 of 42 Suppression of Ionization of a Weak Base
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Prentice-Hall © 2002General Chemistry: Chapter 18Slide 17 of 42 Solutions of Weak Acids and Their Salts
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Prentice-Hall © 2002General Chemistry: Chapter 18Slide 18 of 42 Solutions of Weak Bases and Their Salts
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