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Functional Question Higher (Algebra 1) For the week beginning ….
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Q1. Prove that (Total 4 marks)
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One fraction correct or n(n + 6) or (n + 5)(n – 4) M1 – Method mark n 2 + 6n and n 2 + 5n – 4n – 20 n 2 + 6n or n 2 + n – 20 Condone – n 2 + 5n – 4n – 20 Method mark n 2 + 6n – n 2 – 5n + 4n + 20 n 2 + 6n – n 2 – n + 20 A1 – Accuracy marks are awarded when following on from a correct method 5n + 20 and Answer given Must see all working for final mark Must see use of denominators for final mark A1 Accuracy marks are awarded when following on from a correct method [4]
![One fraction correct or n(n + 6) or (n + 5)(n – 4) M1 – Method mark n 2 + 6n and n 2 + 5n – 4n – 20 n 2 + 6n or n 2 + n – 20 Condone – n 2 + 5n – 4n – 20 Method mark n 2 + 6n – n 2 – 5n + 4n + 20 n 2 + 6n – n 2 – n + 20 A1 – Accuracy marks are awarded when following on from a correct method 5n + 20 and Answer given Must see all working for final mark Must see use of denominators for final mark A1 Accuracy marks are awarded when following on from a correct method [4]](http://images.slideplayer.com./9/2548603/slides/slide_3.jpg "One fraction correct or n(n + 6) or (n + 5)(n – 4) M1 – Method mark n 2 + 6n and n 2 + 5n – 4n – 20 n 2 + 6n or n 2 + n – 20 Condone – n 2 + 5n – 4n – 20 Method mark n 2 + 6n – n 2 – 5n + 4n + 20 n 2 + 6n – n 2 – n + 20 A1 – Accuracy marks are awarded when following on from a correct method 5n + 20 and Answer given Must see all working for final mark Must see use of denominators for final mark A1 Accuracy marks are awarded when following on from a correct method [4]")
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Hardly any fully correct answers were seen. Few candidates knew that a common denominator was required. Many attempted to substitute numerical values into both sides as a test of validity. Common Mistakes – what did the examiners say?
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