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U1B L2 Reviewing Linear Functions
UNIT 1B LESSON 2 REVIEW OF LINEAR FUNCTIONS
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U1B L2 Reviewing Linear Functions
Equations of Lines The vertical line through the point (a, b) has equation x = a since every x-coordinate on the line has the same value a. 𝟐,𝟓 −𝟏,𝟑 𝟎,𝟑 𝟐,𝟑 𝟒,𝟑 𝟐,𝟑 Similarly, the horizontal line through (a, b) has equation y = b 𝟐,𝟎 The horizontal line through the point (2, 3) has equation 𝟐,−𝟐 y = 3 The vertical line through the point (2, 3) has equation x = 2
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Finding Equations of Vertical and Horizontal Lines
U1B L2 Reviewing Linear Functions Finding Equations of Vertical and Horizontal Lines EXAMPLE 1 Write the equations of the vertical and horizontal lines through the point −𝟑, 𝟖 Horizontal Line is y = 8 −𝟑, 𝟖 Vertical Line is x = – 3
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U1B L2 Reviewing Linear Functions
EXAMPLE 2: Reviewing Slope-Intercept Form of Linear Functions Y1 = 2x + 7 Slope y-intercept form y = mx + b slope y-intercept (0, b) x Y = 2x + 7 −3 𝟐 −𝟑 +𝟕=𝟏 𝟐 𝟎 +𝟕=𝟕 y – intercept ( , ) 𝟎 𝟕 (𝟎,𝟕) 𝒎= 𝒓𝒊𝒔𝒆 𝒓𝒖𝒏 = 𝒚 𝟐 − 𝒚 𝟏 𝒙 𝟐 − 𝒙 𝟏 𝒎= 𝟏−𝟕 −𝟑−𝟎 = −𝟔 −𝟑 =𝟐 (−𝟑,𝟏)
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U1B L2 Reviewing Linear Functions
Unit 1B Lesson 2 Page 1 EXAMPLES State the slopes and y-intercepts of the given linear functions. y = 4x slope = m = _______ y -intercept ( , ) 3. 4 0 , 0 y = 3x – slope = m = _______ y -intercept ( , ) 4. 3 0 , −𝟓 = slope = m = _______ y -intercept ( , ) 6. ⅓ 0 , −𝟐 slope = m = _______ y -intercept ( , ) 6. − 𝟏 𝟐 0 , ½ 𝒇 𝒙 = 𝟏 𝟐 − 𝟏 𝟐 𝒙
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General Linear Equation
U1B L2 Reviewing Linear Functions General Linear Equation Although the general linear form helps in the quick identification of lines, the slope-intercept form is the one to enter into a calculator for graphing. Ax + By = C By = – Ax + C y = – (A/B) x + C/B
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Analyzing and Graphing a General Linear Equation
U1B L2 Reviewing Linear Functions Analyzing and Graphing a General Linear Equation Example 7 Find the slope and y-intercept of the line 2𝑥−3𝑦=15 Rearrange for y −𝟑𝒚 = −𝟐𝒙 + 𝟏𝟓 −𝟑 −𝟑 𝒚 = −𝟐 −𝟑 𝒙+ 𝟏𝟓 −𝟑 𝟔 𝒚= 𝟐 𝟑 𝒙−𝟓 𝟑 𝟒 𝟐 y-intercept is (𝟎, −𝟓) Slope is 𝟐 𝟑
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U1B L2 Reviewing Linear Functions
Unit 1B Lesson 2 Page 1 EXAMPLES State the slopes and y-intercepts of the given linear functions. − 𝟏 𝟐 x + 2y = 3 slope = m = _______ y -intercept ( , ) 8. 0 , 3/2 𝟐𝒚 = −𝒙 +𝟑 𝒚 =− 𝟏 𝟐 𝒙 + 𝟑 𝟐 𝟓 𝟑 5𝑥−3𝑦 =−4 slope = m = _______ y -intercept ( , ) 9. 0 , 4/3 −𝟑𝒚 = −𝟓𝒙 −𝟒 𝒚 = 𝟓 𝟑 𝒙 + 𝟒 𝟑
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U1B L2 Reviewing Linear Functions
EXAMPLE 10 Find the equation in slope-intercept form for the line with slope 𝟐 𝟑 and passes through the point (−𝟑, 𝟓) 𝒎= 𝟐 𝟑 Step 1: Solve for b using the point (−𝟑, 𝟓) 𝒚=𝒎𝒙+𝒃 𝟓= 𝟐 𝟑 −𝟑 +𝒃 𝟓=−𝟐+𝒃 (𝟎, 𝟕) (−𝟑, 𝟓) b = 7 Step 2: Find the equation 𝒚= 𝟐 𝟑 𝒙+𝟕
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U1B L2 Reviewing Linear Functions
EXAMPLE 11 Find the equation in slope-intercept form for the line parallel to 𝒚 = 𝟐 𝟓 𝒙 + 𝟐 and through the point (10, -1) Step 1: The slope of a parallel line will be 𝟐 𝟓 Step 2: Solve for b using the point (𝟏𝟎, −𝟏) 𝒚=𝒎𝒙+𝒃 (𝟎, 𝟐) −𝟏= 𝟐 𝟓 𝟏𝟎 +𝒃 −𝟏=𝟒+𝒃 𝒃 = −𝟓 Step 3: Find the equation (𝟎, −𝟓) 𝒚 = 𝟐 𝟓 𝒙 – 𝟓
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U1B L2 Reviewing Linear Functions
EXAMPLE 12 Write the equation for the line through the point (– 1 , 2) that is parallel to the line L: y = 3x – 4 Step 1: Slope of L is 3 so slope of any parallel line is also 3. Step 2: Find b. Step 3: The equation of the line parallel to L: 𝒚 = 𝟑𝒙 – 𝟒 is 𝒚 = 𝟑𝒙 + 𝟓 𝟐 = 𝟑(−𝟏) + 𝒃 𝟐 =−𝟑+𝒃 𝒃 = 𝟓 Step 4: Graph on your calculator to check your work. Use a square window. Y1 = 3x – 4 Y2 = 3x + 5 (0, 5) (0, – 4)
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U1B L2 Reviewing Linear Functions
EXAMPLE 13 Write the equation for the line that is perpendicular to 𝒚 = 𝟐 𝟓 𝒙 + 𝟐 and passes through the point (10, – 1 ) Step 1: The slope of a perpendicular line will be – 𝟓 𝟐 negative reciprocal Step 2: Solve for b using the point (10, – 1) −𝟏 = – 𝟓 𝟐 (𝟏𝟎) + 𝒃 Step 3: The equation of the line ┴ to 𝒚 = 𝟐 𝟓 𝒙 + 𝟐 is 𝒚 = – 𝟓 𝟐 𝒙 + 𝟐𝟒 −𝟏=−𝟐𝟓+𝒃 𝒃 = 𝟐𝟒 Step 4: Graph on your calculator to check your work. Use a square window. Y1 = 𝟐 𝟓 𝒙 + 𝟐 Y2 = – 𝟓 𝟐 x + 24 𝟐 𝟐 −𝟓 𝟓
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U1B L2 Reviewing Linear Functions
EXAMPLE 14 Write the equation for the line through the point (– 1, 2) that is perpendicular to the line L: y = 3x – 4 Step 1: Slope of L is 3 so slope of any perpendicular line is − 𝟏 𝟑 . Step 2: Find b. 𝟐 =− 𝟏 𝟑 (−𝟏) + 𝒃 𝒃 = 𝟓 𝟑 𝟐 = 𝟏 𝟑 + 𝒃 𝟔 𝟑 = 𝟏 𝟑 + 𝒃 Step 3: Find the equation of the line perpendicular to L: y = 3x – 4 𝒚 =− 𝟏 𝟑 𝒙 + 𝟓 𝟑 Step 4: Graph on your calculator to check your work. Use a square window. Y1 = 3x – 4 Y2 =− 𝟏 𝟑 𝒙 + 𝟓 𝟑
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U1B L2 Reviewing Linear Functions
EXAMPLE 15 Find the equation in slope-intercept form for the line that passes through the points (7, −2) and (−5, 8). Step 1: Find the slope Step 2: Solve for b using either point 𝒎= −𝟐−𝟖 𝟕−(−𝟓) = −𝟏𝟎 𝟏𝟐 =− 𝟓 𝟔 −𝟐 =− 𝟓 𝟔 (𝟕) + 𝒃 𝟖 =− 𝟓 𝟔 (− 𝟓) + 𝒃 − 𝟏𝟐 𝟔 =− 𝟑𝟓 𝟔 + 𝒃 𝟒𝟖 𝟔 = 𝟐𝟓 𝟔 + 𝒃 𝒃 = 𝟐𝟑 𝟔 𝒃 = 𝟐𝟑 𝟔 Step 3: Find the equation (– 5, 8) 𝒚 =− 𝟓 𝟔 𝒙 + 𝟐𝟑 𝟔 (7, – 2)
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U1B L2 Reviewing Linear Functions
EXAMPLE 16 Write the slope-intercept equation for the line through (– 2, –1) and (5, 4). Slope = m = −𝟏−𝟒 −𝟐−𝟓 = −𝟓 −𝟕 = 𝟓 𝟕 –𝟏= 𝟓 𝟕 (–𝟐) + 𝒃 −𝟕 𝟕 = −𝟏𝟎 𝟕 + 𝒃 𝒃 = 𝟑 𝟕 (5, 4) (– 2, – 1) Equation for the line is 𝒚 = 𝟓 𝟕 𝒙 + 𝟑 𝟕
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U1B L2 Reviewing Linear Functions
Finish the 5 questions in Lesson #2
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