1. MOLARITY – Ch 13, p. 412 Quantifies the concentration of a solution.
Molarity (M) = mol solute = n = mol
volume solution V L
Read as “moles solute per liter of solution”
Variables
Units

2. MOLARITY – Ch 13 Example 1: A bottle labeled “0.2 M NaCl” reads as
“0.2 molar sodium chloride solution.”

3. MOLARITY – Ch 13 Example 1: A bottle labeled “0.2 M NaCl” reads as
“0.2 molar sodium chloride solution.”
This means 1 L of the solution contains
0.2 moles NaCl.

4. MOLARITY – Ch 13
Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.

5. Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.
Given:

6. Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.
Given: mass = g

7. Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.
Given: mass = g
V = mL

8. Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.
Given: mass = g
V = mL
Unknown:

9. Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.
Given: mass = g
V = mL
Unknown: M

10. Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.
Given: mass = g
V = mL
Unknown: M
Need:

11. MOLARITY – Ch 13
Example 2: Calculate the molarity of a solution prepared by dissolving g NaCl in enough water to make a mL solution.
Given: mass = g
V = mL
Unknown: M
Need: molar mass NaCl

12. MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L
Unknown: M
Need: molar mass NaCl g/mol
M = n = g V

13. MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L
Unknown: M
Need: molar mass NaCl
M = n = g mol
V g

14. MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L
Unknown: M
Need: molar mass NaCl
M = n = g mol
V g

15. MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L
Unknown: M
Need: molar mass NaCl
M = n = g mol
V L g

16. MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L
Unknown: M
Need: molar mass NaCl
M = n = g mol M
V L g

17. MOLARITY – Ch 13 Example 2: Given: mass = 5.844 g
V = mL = L
Unknown: M
Need: molar mass NaCl
M = n = g mol M
V L g

18. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.

19. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.
Given:

20. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.
Given: V = mL

21. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.
Given: V = mL
molarity = M

22. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.
Given: V = mL
molarity = M
Unknown: n, mol NaOH

23. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.
Given: V = mL
molarity = M
Unknown: n, mol NaOH
Need:

24. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.
Given: V = mL
molarity = M
Unknown: n, mol NaOH
Need: M = n V

25. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.
Given: V = mL
molarity = M
Unknown: n, mol NaOH
Need: M = n  V

26. MOLARITY – Ch 13
Example 3: Calculate the moles of NaOH present in mL of M NaOH.
Given: V = mL
molarity = M
Unknown: n, mol NaOH
Need: M = n  n = M•V V

27. MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL molarity = 0.250 M
Unknown: n, mol NaOH
Need: M = n  n = M•V V
0.250 M

28. MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL molarity = 0.250 M
Unknown: n, mol NaOH
Need: M = n  n = M•V V
0.250 mol L

29. MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L
molarity = M
Unknown: n, mol NaOH
Need: M = n  n = M•V V
0.250 mol L

30. MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L
molarity = M
Unknown: n, mol NaOH
Need: M = n  n = M•V V
0.250 mol L L

31. MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L
molarity = M
Unknown: n, mol NaOH
Need: M = n  n = M•V V
0.250 mol L L

32. MOLARITY – Ch 13 Example 3: Given: V = 5000.0 mL = 5.0000 L
molarity = M
Unknown: n, mol NaOH
Need: M = n  n = M•V V
0.250 mol L mol L

33. MOLARITY – Ch 13
Example 4: Calculate the volume of 0.50 M HCl that would contain 2.0 mol HCl.
YOU TRY IT!

34. MOLARITY – Ch 13 Example 4: Given: n = 2.0 mol HCl molarity = 0.50 M
Unknown: V
Need: M = n  V = n
V M
2.0 mol L L
0.50 mol

35. MOLARITY – Ch 13
Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated
12 M HCl?
YOU TRY IT!

36. MOLARITY – Ch 13
Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated
12 M HCl?
Use C1V1 = C2V2

37. MOLARITY – Ch 13
Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated
12 M HCl?
Use C1V1 = C2V2
Given: C1 = 0.50 M V1 = 100mL
C2 = 12 M

38. MOLARITY – Ch 13
Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated
12 M HCl?
Use C1V1 = C2V2
Given: C1 = 0.50 M V1 = 100mL
C2 = 12
Unknown:

39. MOLARITY – Ch 13
Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated
12 M HCl?
Use C1V1 = C2V2
Given: C1 = 0.50 M V1 = 100mL
C2 = 12
Unknown: V2 =

40. MOLARITY – Ch 13
Example 5: How would you prepare 100 mL of 0.50 M HCl from concentrated
12 M HCl?
Use C1V1 = C2V2  C1V1 = V2 C2
Given: C1 = 0.50 M V1 = 100mL
C2 = 12
Unknown: V2 =