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Balancing Equations.

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Presentation on theme: "Balancing Equations."— Presentation transcript:

1 Balancing Equations

2 Law of Conservation of Mass
The Law of Conservation of Mass states: that mass is neither created nor destroyed in any chemical reaction. Therefore balancing equations requires the same number of atoms on both sides of a chemical reaction. The number of atoms in the Reactants must equal the Number of atoms in the Products

3 Balance elements in the following order:
Nonmetals Metals Polyatomic ions Hydrogen Oxygen

4 Polyatomic Ions When balancing polyatomic ions treat them as one unit if they appear on both sides of the equation.

5 Balancing Equations N2 + H2 NH3 __N__ 2 1 __H__ 2 3
Complete an atom inventory. 2 1 2 3 __N__ __H__

6 Balancing Equations N2 + H2 2NH3 Nothing is balanced.
Balance the nitrogen first by placing a coefficient of 2 in front of the NH3. N2 + H NH3

7 Balancing Equations N2 + 3H2 2NH3 2 2 6 6 __N__ __H__
Hydrogen is not balanced. Place a 3 in front of H2. N H NH3 Complete a final atom inventory. 2 2 6 6 __N__ __H__

8 Balancing Equations C3H8 + O2→ CO2+ H2O __C__ 3 1 __H__ 8 2 __O__ 2 3
Complete an atom inventory. 3 1 8 2 2 3 __C__ __H__ __O__

9 Balancing Equations C3H8 + O2 → 3CO2+ H2O Nothing is balanced.
Balance the carbon first by placing a coefficient of 3 in front of the CO2. C3H O2 → 3CO2+ H2O

10 Balancing Equations C3H8 + O2 → 3CO2+ 4H2O
Now balance the hydrogen by placing a 4 in front of the water on the products side. C3H O2 → 3CO2+ 4H2O

11 Balancing Equations C3H8 + 5O2 → 3CO2+ 4H2O __C__ 3 3 __H__ 8 8 __O__
Balance the oxygen on the reactants side with a coefficient of 5. C3H8 + 5O2 → 3CO2+ 4H2O Complete a final atom inventory. 3 3 8 8 __C__ __H__ __O__

12 Balancing Equations BF3+ Li2SO3→ B2(SO3)3+ LiF 1 2 3 1 2 1 1 3 __B__
Complete an atom inventory. 1 2 3 1 2 1 1 3 __B__ __F__ __Li__ __SO3__

13 Balancing Equations BF3+ Li2SO3→ B2(SO3)3+ 3LiF Nothing is balanced.
Balance the fluorine first by placing a coefficient of 3 in front of the LiF. BF3+ Li2SO3→ B2(SO3)3+ 3LiF

14 Balancing Equations 2BF3+ Li2SO3→ B2(SO3)3+ 3LiF
Now balance the boron by placing a 2 in front of the BF3 on the reactants side. 2BF3+ Li2SO3→ B2(SO3)3+ 3LiF Notice we’ve unbalanced the fluorine, and now must adjust our coefficients.

15 Balancing Equations 2BF3+ Li2SO3→ B2(SO3)3+ 6LiF
Now balance the boron by placing a 2 in front of the BF3 on the reactants side. 2BF3+ Li2SO3→ B2(SO3)3+ 6LiF Notice we’ve unbalanced the fluorine, and now must adjust our coefficients.

16 Balancing Equations __B__ 2BF3+ 3Li2SO3→ B2(SO3)3+ 6LiF 2 2 __F__ 6 6
Balance the lithium sulfite on the reactants side with a coefficient of 3. 2BF3+ 3Li2SO3→ B2(SO3)3+ 6LiF Complete a final atom inventory. __B__ __F__ __Li__ __SO3__ 2 2 6 6

17 YOU ARE BALANCED!!


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