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Newton’s Universal Law of Gravitation
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Factors Affecting the Gravitational Force mass distance
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force varies directly with masses
decrease mass decreased force force varies directly with masses Fg α m1 m2
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Distance r increase r force decreased
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Force varies inversely with distance squared Fg α 1/r2
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Fg α m1m2 Fg α 1/r2 m1 m2 Fg α r2 Fg slope = G m1 m2/r2
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G = 6.67 x 10-11 N m2/kg2
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A 1000 kg car and a 2000 kg truck are 0.50 m apart. Gravitational force: 5.3 x 10-4 N
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Computing mass of Earth
radius of Earth: x 106 m 1.00 kg mass has a weight of 9.81 N mass of Earth: 5.97 x 1024 kg
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2F 4F
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¼ F 4F
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F
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“g” gravitational field – weight per mass wtg Fg g = = mass m G M = r2 M = planet mass
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Effect of changing variables GM g = ----- r2
if M doubles: if r doubles: if M & r doubles: if r becomes ½: 2g ¼ g ½ g 4g
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radius: 53% radius of Earth gravitational field for Mars?
mass: 11% mass of Earth radius: 53% radius of Earth gravitational field for Mars? 0.39 gE = N/kg
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Net gravitational force on bottom mass?
√3 GM2/s2
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G m1 m2 Fg = ---------- = weight r2
What would happen to your weight if: Earth had twice mass but the same radius: Twice weight Earth had twice radius but same mass: ¼ weight
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What is “g” at top of Mt. Everest
(8848 m elevation)? 9.77 N/kg = 9.77 m/s2
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