2. Energy Transfer of Two Liquids! By: Briana Brogan, Lindsey Tennis, Kristina Balla, Cheyenne Kressley, and Brit Rost

3. Purpose To determine how energy is transferred between two liquids, that are at two different temperatures.

4. Materials water, temperature sensor, beakers, graduated cylinder, anything in the lab drawers, and alcohol.

5. Hypothesis The temperature of the cold water will rise and the temperature of the warm water will drop. The temperature of the cold water will rise and the temperature of the warm water will drop.

6. IV (temperature C o ) Hot-50 Cold- 19.8 Hot-60 Cold- 19.8 Hot- 70 Cold- 19.8 Hot- 80 Cold- 10 Hot- 90 Cold- 0 Trial 1

7. DV The temperature mixed water (C o ) The temperature mixed water (C o )

8. Control and Constants Control- room temperature, 19.8 o Control- room temperature, 19.8 o Constants- same equipment and the same amount of water. Constants- same equipment and the same amount of water.

9. Procedures 1. Heat the water to the specified degrees C o (100mL of water). 1. Heat the water to the specified degrees C o (100mL of water). 2. When you are finished pick up the beaker with beaker tongs. 2. When you are finished pick up the beaker with beaker tongs. 3. Cool the other beaker of water to specified degrees C o (100mL of water) 3. Cool the other beaker of water to specified degrees C o (100mL of water) 4. Mix and check the temperature. 4. Mix and check the temperature. 5. Repeat steps 1-4 until you have finished all the degrees C o. 5. Repeat steps 1-4 until you have finished all the degrees C o.

10. Results Hot Water Celsius Cold Water Celsius Water Mixed Celsius 5019.835.7 6019.838.6 7019.842.0 801037.7 90040.7

11. Conclusion We heated water to 50, 60, 70,80, and 90 o C. Then we cooled water to 19.8, 10, and 0 o C. The control was 19.8 C (room temperature). Next, we mixed the hot and cold water and checked the temperature. Our hypothesis was that the temperature of the colder liquid will rise and the temperature of the warmer liquid water will drop. Our hypothesis was supported. We thought about what the average temperatures for our experiment would be and they were, 50 o C and 19.8 o C = about 34.9 o C, 60 o C and 19.8 o C=39.9 o C, 70 o C and 19.8 o C= 44.9 o C, 80 o C and 10 o C= 45 o C, and 90 o C and 0 o C= 45oC. When the hot water was at 50 o C which was then was mixed with cold water at room temperature, it was 35.7 o C. At 70 o C and at room temperature, the mixed water was 42 o C. When the water was 80 o C and 10 o C the mixed water was 37.7 o C. Finally at 90 o C and 0 o C the mixed temperature was 40.7 o C.

12. The End