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Mrs. Rivas.

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Presentation on theme: "Mrs. Rivas."β€” Presentation transcript:

1 Mrs. Rivas

2 Mrs. Rivas

3 Mrs. Rivas

4 Mrs. Rivas

5 Mrs. Rivas

6 Mrs. Rivas

7 Mrs. Rivas πŸπ’™ + πŸπŸ“ + πŸ’π’™ – 𝟏 = πŸ–π’™ + πŸ– πŸ”π’™ + πŸπŸ’ = πŸ–π’™ + πŸ– πŸ”π’™ = πŸ–π’™ – πŸ”
βˆ’πŸπ’™ = – πŸ” πŸ–π’™ + πŸ– πŸ’π’™ – 𝟏 𝒙 = πŸ‘ Then substitute to answer the question.

8 Mrs. Rivas X = 3 m∠AOB = 4x – 1 = 4(3) – 1 = 11 m∠BOC = 2x + 15
= 4(3) – 1 = 11 m∠BOC = 2x + 15 = 2(3) + 15 = 21 2x + 15 m∠AOC = 8x + 8 = 8(3) + 8 = 32 8x + 8 4x – 1

9 Mrs. Rivas πŸπŸπ’™ – πŸ” πŸ‘π’™ – 𝟏𝟎 + πŸ–π’™ + πŸπŸ‘ = πŸπŸπ’™ – πŸ” πŸπŸπ’™ + πŸ‘ = πŸπŸπ’™ – πŸ”
πŸπŸπ’™ = πŸπŸπ’™ – πŸ— 3x – 10 8x + 13 βˆ’π’™ = – πŸ— 𝒙 = πŸ— Then substitute to answer the question.

10 Mrs. Rivas X = 9 12x – 6 m∠COD = 8x + 13 = 8(9) + 13 = 85
m∠BOC = 3x – 10 = 3(9) – 10 = 17 3x – 10 8x + 13 m∠BOD = 12x – 6 = 12(3) – 6 = 102

11 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 3x + 8 = 2x + 48 – 8 – 8 A B C E F 2x + 48 3x + 8 3x = 2x + 40 – 2x – 2x x = 40 3(40) + 8 = 128 2(40) + 48 = 128

12 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 2x – 3 + 5x + 2 = 90ΒΊ 2x – 3 + 5x + 2 = 90ΒΊ J K L 2x – 3 N P M 5x + 2 7x – 1 = 90ΒΊ + 1 + 1 7x = 91ΒΊ 5(13) + 2 = 67 7 7 2(13) – 3 = 23 x = 13ΒΊ

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17 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. If ∠JKM = 86 then ∠MKL = 86, so ∠JKL has to be equal to = 172. J K M L 86

18 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. Since bisect means cut in half. Then, m∠RSV = 62 ÷ 2 = 31 R S V T 62

19 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 3x = 5x – 20 P Q S R 3x – 5x – 5x – 2x = – 20 5x – 20 2 2 x = 10 3(10) = 30 5(10) – 20 = 30 So, m∠PQR = = 60

20 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 2x + 1 = 4x – 15 – 1 P Q S R 2x + 1 – 1 2x = 4x – 16 4x – 15 – 4x – 4x – 2x = – 16 2(8) + 1 = 17 4(8) – 15 = 17 2 2 So, m∠PQR = = 34 x = 8

21 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. = 3x – 12 P Q S R 3x – 12 60 = 3x – 12 + 12 30 + 12 72 = 3x 3 3 3(24) – 12 = 60 x = 24

22 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 2x + 10 = 5x – 17 P Q S R 2x + 10 – 10 – 10 2x = 5x – 27 5x – 17 – 5x – 5x – 3x = – 27 3 3 2(9) + 10 = 28 5(9) – 17 = 28 x = 9 So, m∠PQR = = 56

23 Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. a). b). m∠MLN = 7(8) – 1 = 55 7x – 1 + 4x + 3 = 90ΒΊ 11x + 2 = 90ΒΊ m∠JKL = 4(8) + 3 = 35 – 2 – 2 11x = 88ΒΊ c). I can check the answer by adding 55 and 35, and it should be 90ΒΊ = 90ΒΊ 11 11 x = 8

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