Download presentation
1
Mrs. Rivas
2
Mrs. Rivas
3
Mrs. Rivas
4
Mrs. Rivas
5
Mrs. Rivas
6
Mrs. Rivas
7
Mrs. Rivas ππ + ππ + ππ β π = ππ + π ππ + ππ = ππ + π ππ = ππ β π
βππ = β π ππ + π ππ β π π = π Then substitute to answer the question.
8
Mrs. Rivas X = 3 mβ AOB = 4x β 1 = 4(3) β 1 = 11 mβ BOC = 2x + 15
= 4(3) β 1 = 11 mβ BOC = 2x + 15 = 2(3) + 15 = 21 2x + 15 mβ AOC = 8x + 8 = 8(3) + 8 = 32 8x + 8 4x β 1
9
Mrs. Rivas πππ β π ππ β ππ + ππ + ππ = πππ β π πππ + π = πππ β π
πππ = πππ β π 3x β 10 8x + 13 βπ = β π π = π Then substitute to answer the question.
10
Mrs. Rivas X = 9 12x β 6 mβ COD = 8x + 13 = 8(9) + 13 = 85
mβ BOC = 3x β 10 = 3(9) β 10 = 17 3x β 10 8x + 13 mβ BOD = 12x β 6 = 12(3) β 6 = 102
11
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 3x + 8 = 2x + 48 β 8 β 8 A B C E F 2x + 48 3x + 8 3x = 2x + 40 β 2x β 2x x = 40 3(40) + 8 = 128 2(40) + 48 = 128
12
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 2x β 3 + 5x + 2 = 90ΒΊ 2x β 3 + 5x + 2 = 90ΒΊ J K L 2x β 3 N P M 5x + 2 7x β 1 = 90ΒΊ + 1 + 1 7x = 91ΒΊ 5(13) + 2 = 67 7 7 2(13) β 3 = 23 x = 13ΒΊ
13
Mrs. Rivas
14
Mrs. Rivas
15
Mrs. Rivas
16
Mrs. Rivas
17
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. If β JKM = 86 then β MKL = 86, so β JKL has to be equal to = 172. J K M L 86
18
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. Since bisect means cut in half. Then, mβ RSV = 62 Γ· 2 = 31 R S V T 62
19
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 3x = 5x β 20 P Q S R 3x β 5x β 5x β 2x = β 20 5x β 20 2 2 x = 10 3(10) = 30 5(10) β 20 = 30 So, mβ PQR = = 60
20
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 2x + 1 = 4x β 15 β 1 P Q S R 2x + 1 β 1 2x = 4x β 16 4x β 15 β 4x β 4x β 2x = β 16 2(8) + 1 = 17 4(8) β 15 = 17 2 2 So, mβ PQR = = 34 x = 8
21
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. = 3x β 12 P Q S R 3x β 12 60 = 3x β 12 + 12 30 + 12 72 = 3x 3 3 3(24) β 12 = 60 x = 24
22
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. 2x + 10 = 5x β 17 P Q S R 2x + 10 β 10 β 10 2x = 5x β 27 5x β 17 β 5x β 5x β 3x = β 27 3 3 2(9) + 10 = 28 5(9) β 17 = 28 x = 9 So, mβ PQR = = 56
23
Always read the question and draw a picture.
Mrs. Rivas Always read the question and draw a picture. a). b). mβ MLN = 7(8) β 1 = 55 7x β 1 + 4x + 3 = 90ΒΊ 11x + 2 = 90ΒΊ mβ JKL = 4(8) + 3 = 35 β 2 β 2 11x = 88ΒΊ c). I can check the answer by adding 55 and 35, and it should be 90ΒΊ = 90ΒΊ 11 11 x = 8
24
Mrs. Rivas
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.