Download presentation
Presentation is loading. Please wait.
Published byCarlo Gailes Modified over 10 years ago
1
Mechanics Lecture 2, Slide 1 Vectors and 2d-Kinematics Continued Relevant Equations How to use them Homework Hints
2
Hyperphysics-Trajectories Mechanics Lecture 1, Slide 2 http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html
3
Projectile Motion Quantities Mechanics Lecture 2, Slide 3 Initial velocity speed,angle Maximum Height of trajectory, h=y max Range of trajectory, D Height of trajectory at arbitrary x,t “Hang Time” Time of Flight, t f
4
Hyperphysics-Trajectories Mechanics Lecture 1, Slide 4
5
Maximum Height of Trajectory Mechanics Lecture 2, Slide 5 Height of trajectory,h=y max
6
Time of Flight Mechanics Lecture 1, Slide 6
7
Time of Flight, “Hang Time” Mechanics Lecture 2, Slide 7
8
Hyperphysics-Trajectories Mechanics Lecture 1, Slide 8
9
Range of trajectory Mechanics Lecture 2, Slide 9
10
Angle for Maximum Range Mechanics Lecture 2, Slide 10 MAXIMUM range OCCURS AT 45 0
11
Will it clear the fence Mechanics Lecture 1, Slide 11
12
Height of Trajectory at time t or position x Mechanics Lecture 2, Slide 12 Height of trajectory, y(x) Height of trajectory, y(t)
13
Projectile Trajectory Equations Mechanics Lecture 1, Slide 13 Height of trajectory as f(x), y(x) Height of trajectory as f(t), y(t) Range of trajectory Time of Flight (“Hang Time”) Maximum height
14
Where will it land? Mechanics Lecture 1, Slide 14
15
Launch Velocity-Given R and Mechanics Lecture 1, Slide 15
16
Launch Angle Mechanics Lecture 1, Slide 16
17
Launch Velocity –Given R and h Mechanics Lecture 1, Slide 17
18
Mechanics Lecture 2, Slide 18 Field Goal Example A field goal kicker can kick the ball 30 m/s at an angle of 30 degrees w.r.t. the ground. If the crossbar of the goal post is 3m off the ground, from how far away can he kick a field goal? y-direction v oy = v o sin(30 o ) = 15 m/s y = y o + v oy t + ½ at 2 3 m = 0 m + (15 m/s) t – ½ (9.8 m/s 2 ) t 2 t = 2.8 s or t = 0.22 s. x-direction v ox = v o cos(30 o ) = 26 m/s D = x o + v ox t + ½ at 2 = 0 m + (26 m/s)(2.8 s) + 0 m/s 2 (2.8 s ) 2 = 72.8 m D 3 m y x Illini Kicks 70 yard Field Goal
19
Homework Hints-Baseball Mechanics Lecture 1, Slide 19
20
Homework Hints- Baseball Stadium Wall Mechanics Lecture 1, Slide 20
21
Homework Hints – Stadium Wall Mechanics Lecture 1, Slide 21 Calculate time to reach wall using v x : Calculate y position at time to reach wall:
22
Homework Hints-Catch Mechanics Lecture 1, Slide 22
23
Homework Hints-Catch Mechanics Lecture 1, Slide 23
24
Homework Hints-Catch Mechanics Lecture 1, Slide 24
25
Homework Hints-Catch 2 Mechanics Lecture 1, Slide 25
26
Homework Hints-Catch 2 Mechanics Lecture 1, Slide 26 v V x is constant ! Kinetic energy should be same as when ball was thrown. Y- component of velocity would be downward.
27
Homework Hints-Catch 2 Mechanics Lecture 1, Slide 27 Same conditions as before
28
Homework Hints – Soccer Kick & Cannonball Mechanics Lecture 1, Slide 28
29
Homework Hints – Soccer Kick & Cannonball Mechanics Lecture 1, Slide 29
30
Homework Hints – Soccer Kick & Cannonball Mechanics Lecture 1, Slide 30
31
Trigonometric Identity for range equation Mechanics Lecture 2, Slide 31 http://mathworld.wolfram.com/Cosine.html http://mathworld.wolfram.com/Sine.html
32
Trigonometric Identities relating sum and products Mechanics Lecture 2, Slide 32 List of trigonometric identities
33
Question 2 Mechanics Lecture 2, Slide 33
34
Question 2 Mechanics Lecture 2, Slide 34
35
Hyperphysics-Trajectories Mechanics Lecture 1, Slide 35 http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.