1. Quadratic Word Problems WS 2 Solutions#1
10 inches #2
15 cm by 7 cm #3
a ft b sec c & 5.70 sec #4
72 units #5
96 cm #6
Height is 5.25 m or 5 m and 25 cm
Distance is 3.79 meters or 3 m and 79 cm

2. #1
2x + 15
2x + 20
ft x 12 in/ft
About 10 inches

3. The dimensions of the rectangle are 15 cm by 7 cm#2
Perimeter = 44 cm
Area = 105 sq. cm
Width = W
2L + 2W = 44
L + W = 22
Length = L
L = 22 - W
The dimensions of the rectangle are 15 cm by 7 cm
(L)(W) = 105
(22 - W)(W) = 105
22W – W2 = 105
W2 – 22W = 0
(W - 15)(W - 7) = 105

4. #3a
h = -16t t
First find Axis of Symmetry
Plug it in to get the vertex
Solving for h will give the maximum point (or highest point)

5. #3b
h = -16t t
Two ways to solve …
Why does this work?
Alternate solution
0 = -16t t
0 = -4t(4t – 25)
t = 0 or 6.25

6. #3c
h = -16t t
50 = -16t t
16t t + 50 = 0
8t2 - 50t + 25 = 0

7. #4 x x
x + 6
x + 9

8. Width = w Length = 3w Volume = L x W x H 512 = (3w - 4)(w - 4)(2)
Perimeter = 96 cm
256 = 3w2 – 16w + 16
0 = 3w2 – 16w - 240
0 = (w – 12)(3w + 20)
Width = 12 cm

9. #6 Mr. Lomas (at least the way I remember me) ….
Maximum height (at vertex)
height when I hit the water?
3 meters
Distance from board when entering water?

10. Maximum height of 525 cm

11. #7
Equation: y = x2 - 10x + 15
Direct: Up
Width: Standard
L of S: x = 5
Vertex: (5, -10)
y-int: (0, 15)
Roots:

12. #8
Equation: y = -2x2 + 8
Direct: Down
Width: Narrow
L of S: x = 0
Vertex: (0, 8)
y-int: (0, 8)
Roots: 2 or -2

13. #9
Equation: y = (1/4)x2 - 2x - 5
Direct: Up
Width: Wide
L of S: x = 4
Vertex: (4, -9)
y-int: (0, -5)
Roots: 10 or -2