1. Surface Area of Pyramids
Return to table
of contents

2. Surface Area of Pyramids
What is a pyramid?
Polyhedron with one base and triangular faces that meet at a vertex
How do you find Surface Area?
Sum of the areas of all the surfaces of a 3-D Figure
click to reveal
click to reveal

3. Find the Surface Area.
17.5 cm
go on to see steps
7 cm
8 cm

4. Find the Surface Area. Bottom Front/Back Left/Right Rectangle
8 cm
7 cm
17.5 cm
8 cm
Bottom
Rectangle 8
x 7 56
Front/Back
Triangles
Left/Right
Triangles
Surface Area 56
140
318.5 cm2

5. Find the surface area of a square pyramid with base edge of 4 inches and triangle height of 3 inches.
4 in
3 in
Base 4
x 4 16
4 Triangles
Surface Area 16
+ 24
40 in2
click to reveal
click to reveal
click to reveal

6. Find the surface area.
Be sure to look at the base to see if it is an equilateral or isosceles triangle (making all or two of the side triangles equivalent!).
Triangles
(all equal)
Base
click to reveal
click to reveal
6 in
4 in
3.5 in
Surface Area 7
+ 36
43 in2
4 in
4 in
click to reveal

7. 42
Which has a greater Surface Area, a square pyramid with a base edge of 8 in and a height of 4 in or a cube with an edge of 5 in? A
Square Pyramid B
Cube
Answer: B
Square Pyramid Cube
Bases Triangles faces
A = s A = (1/2)bh x A = s 2 x 6
A = A = (1/2)(8)(4) x A = 52 x 6
A = 64 in A = 64 in A = 150 in2
SA= 128 in2

8. 43
Find the Surface Area of a triangular pyramid with base edges of 8 in, base height of 4 in and a slant height of 10 in.
8 in
10 in
6.9 in
Answer: 147.6
Bases Triangles
A = (1/2)bh A = (1/2)bh x 3
A = (1/2)(8)(6.9) A = (1/2)(8)(10) x 3
A = A = 120
SA= = in2

9. 44 Find the Surface Area. 11 m 12 m 6.7 m 9 m 9 m Answer: 205.2
Bases Triangles
A = (1/2)bh A = (1/2)bh x 2 + (1/2) bh
A = (1/2)(12)(6.7) A = (1/2)(9)(11) x 2 + (1/2)(12)(11)
A = A =
A = 165
SA= = in2
9 m
9 m