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Published byEllis Dunham Modified over 9 years ago
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講者: 許永昌 老師 1
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Contents Conformal Mapping Mappings Translation Rotation Inversion Branch Points and Multivalent Functions 2
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Conformal mapping ( 請預讀 P368~P370) 3
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Conformal mapping (continue) Based on Cauchy-Riemann conditions, we get 2 u=0= 2 v, u v=0. They are orthogonal to each other The curves u=constant and v=constant are orthogonal to each other. Example: w=z 2 =(x 2 -y 2 )+2ixy Code: z2_uv.mz2_uv.m y=sqrt(x 2 -u), y=v/(2x) Contour u= x 2 -y 2, v=2xy. 4 Proper rotation
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Conformal Mapping (final) The mapping of w=z 2. From these figures, you will find that the contour lines of y=C and y=-C are the same in w-plane. Reason: z=re i and z’=re i i . z 2 =r 2 e i2 =z’ 2. Therefore, it has a two-to-one correspondence. 5
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Mappings ( 請預讀 P360~P363) Linear Transformation: Translation: w=z+z 0. Rotation: w=cz=(r r c )e i( c ). Nonlinear Transformation: Inversion: w=1/z=1/r e i . … Code: mappings.mmappings.m 想像 w=z‘ 與 z 畫在同一個座標系 6
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Exercise Prove that w=1/z will map a straight line in z-plane into a circle cross w=0. Try to add “z=z*(1+1i);x=real(z);y=imag(z);” into the code mappings.m to see the result. 7
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Multivalent functions and Branch Points ( 請預讀 P363~P367) 8 Hint: Restrict the allowed range of ’.
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Multivalent functions and Branch Points (continue) 9 * 莊 ( 土斤 ) 泰,張南岳,復變函數
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Multivalent functions and Branch Points (final) 10
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Homework 6.6.2 6.6.3 6.6.5 6.6.6 6.6.7 6.7.1 6.7.4 11
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Nouns 12
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