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Published bySavanah Yarrow Modified over 9 years ago
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Упростить функцию и построить таблицу истинности
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F(x1,x2,x3) = x1 · x2 + x2 + x1 · x3 № 1. = (x1 · x2 + x2) + x1 · x3 = (x1 + x2) · (x2 + x2) + x1 · x3 = x1 + x2 + x1 · x3 = x1 + x1 · x3 + x2 = (x1 + x1) · (x1 + x3) + x2 = (x1 + x3) + x2 = x1 + x2 + x3
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F(x1,x2,x3) = x1 + x2 + x3 x1x2x3x2X1 + x2x1 + x2 + x3 000111 001111 010000 011001 100111 101111 110011 111011
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F(x1,x2,x3) = x3 · (x2 · x1 + x3) № 2.
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F(x1,x2,x3) = x1 · x2 · x3 + x1 + x2 + x3 № 3.
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№ 4. F(x1,x2,x3) = x1 + x3 + x1 · x2
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№ 5. F(x1,x2,x3) = x1 + x2 ·(x1 + x3 · x2)
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№ 6. F(x1,x2,x3) = x1 + x2 + x3 · ( x1 + x3)
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№ 7. F(x1,x2,x3) = x1 + x2 + x3 · ( x1 + x2)
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№ 8. F(x1,x2,x3) = x1 + x2 + x3 + x1 + x2 · x3
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№ 9. F(x1,x2,x3) = (x1 + x3) · x1 · x2 + x1
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№ 10. F(x1,x2,x3) = x1 + x2 + x1 · x3 + x1 · x2
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