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 Read about Therac-25 at  [http://www.ddj.com/cpp/184401630]http://www.ddj.com/cpp/184401630  [http://sunnyday.mit.edu/papers/therac.pdf]http://sunnyday.mit.edu/papers/therac.pdf.

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Presentation on theme: " Read about Therac-25 at  [http://www.ddj.com/cpp/184401630]http://www.ddj.com/cpp/184401630  [http://sunnyday.mit.edu/papers/therac.pdf]http://sunnyday.mit.edu/papers/therac.pdf."— Presentation transcript:

1  Read about Therac-25 at  [http://www.ddj.com/cpp/184401630]http://www.ddj.com/cpp/184401630  [http://sunnyday.mit.edu/papers/therac.pdf]http://sunnyday.mit.edu/papers/therac.pdf

2  IPC (Interprocess Communication) mechanisms  [http://www.faqs.org/docs/kernel_2_4/lki-5.html]http://www.faqs.org/docs/kernel_2_4/lki-5.html  [http://www.comptechdoc.org/os/linux/programming /linux_pgcomm.html]http://www.comptechdoc.org/os/linux/programming /linux_pgcomm.html

3  Processes are concurrent if they exist at the same time.  Processes are asynchronous if NO timing assumptions can be made regarding events that each does. i.e. independent of each other.  Problems can occur if they access shared data.  Perhaps the most visible application of concurrency is in gaming.

4 Example:  Two processes one counts events one logs the count at regular intervals P1 (ex: count cars that pass, count lines of output) P2 report counts at regular intervals (timer based)

5  Suppose x is 99 and is shared by P1 and P2  Order of events:1-2-3 or 2-3-1  works as expected  Order of events 2-1-3  last event is unreported P1 (Observer)P2 (Reporter) loop wait for event (1)x=x+1 end loop loop sleep(time t) (2)print x (3)reset x to 0 end loop

6  Worse scenario  Could get the following reports: 93 – 95 – 91 – 93 – 181 – 92 – 95.  What happened?

7  x=x+1 could be translated into machine code as  (1a)move, Regx  (1b)add, Reg1  (1c)store, Regx Order of events is 1a-2-3-1b-1c  Resetting of x to 0 is lost!! P1 (Observer)P2 (Reporter) loop wait for event (1)x=x+1 end loop loop sleep(time t) (2)print x (3)reset x to 0 end loop

8 Solution:  if a process is modifying a shared variable, no other process should access it.  This is called Mutual Exclusion.  A portion of code that accesses the shared data is called a critical section.  No two processes should be executing their respective critical sections at the same time.

9  Solution to the critical section problem must satisfy: Mutual exclusion Progress: Don’t wait if not necessary Bounded waiting: to prevent starvation.

10  Need to implement entry and exit logic for concurrent programs as shown: While (1) { Entry section Critical section Exit section Non critical section }

11  Web site contains demos programs in Java that show attempts at Mutual Exclusion among two or more threads.  NOTE: Section 5.7 discusses a little about Java threads and thread scheduling.  Mutual Exclusion. Just establishes the framework and provides a chance to discuss Java Threads.

12 Algorithm_1  Enforces mutual exclusion  Does not satisfy the progress rule  forces threads to alternate entries into critical sections  Thus, a thread must wait if it is not its turn.

13 Algorithm_2  Enforces mutual exclusion  Processes not forced to alternate  can result in deadlock  though may need to use a small time value to show this.

14 Algorithm_3.  This is the book's Peterson's Solution implemented in Java.  Enforces mutual exclusion  Enforces the progress rule  Works for 2 processes  Does not scale to more than 2 processes.

15 n-process mutual exclusion algorithm. Developed by Edsgar Dijkstra in 1965.Edsgar Dijkstra shared data status: array [0..n-1] of (idle, entering, inside) turn : 0..n-1 enteringCriticalSection (for process i) Repeat status[i] = entering while turn  i do if (status[turn] == idle) turn = i status[i] = inside j = 0 while (j < n) and ( (j == i) or status[j]  inside) j = j+1 until j == n leavingCriticalSection(for process i) status[i] = idle

16  See Dekkers in the collection of java projects.  This solution is subject to starvation or indefinite postponement.  Other algorithms that improve on this have been written by Donald Knuth, DeBruijn, Eisenberg/McGuire and include Lamport’s Bakery algorithm.  Should be able to find examples on the Internet.

17 Hardware Solutions:  testandset(a, b): Implemented on early IBM machines. This command sets a to b and sets b to true. It’s atomic (uninterruptible) - a machine command.

18 enteringCriticalSection testandset(status, inside) do while (status) testandset(status, inside) leavingCriticalSection inside = false

19  Many modern systems provide some type of hardware or system level instructions to implement Mutual Exclusion.

20  Project getAndSet and book figures 6.4 and 6.5 (page 216-217) simulate a hardware instruction with a Java class.  The book example would lock up periodically because the testandset method is not an uninterruptible method. i.e. it is not a hardware instruction.  However, it can be simulated by putting a public synchronized qualifier on each Hardware Data method. This means

21  Every java object has a lock.  Locks are generally ignored.  thread must own a lock to call any of the synchronized methods.  If it does not then it waits in a queue until it can own the lock.  Works much like a Monitor (discussed later).

22 Semaphores:  developed by Dijkstra in 1965  aid to synchronize processes and enforce mutual exclusion.  name give to a device to control occupancy of sections of railroad tracks.  A semaphore is a variable, s that can be operated on only by two primitives (non-interruptible commands)

23  Classic primitive operations: P(s) (For the Dutch word Proberen meaning test) If (s > 0) then s = s – 1 else wait until s > 0  Sometimes instead of a wait, the definition uses a spinlock (busy wait loop). Book does this (p. 218)  Book uses acquire: that is, instead of writing P(s) the book write s.acquire()

24 V(s) (For the Dutch word Verhogen meaning increment) if a process is suspended, waiting on s, then wake it else s = s + 1  If P(s) is defined using a spinlock then V(s) need only increment the semaphore value (page 218)  Book uses release: That is, instead of writing V(s) the book writes s.release()

25  binary semaphore Value is 0 or 1  counting semaphore Value can be any positive integer value.

26  To enforce Mutual exclusion process code : : P(s) critical section V(s) : :  Works for any number of processes

27 Java semaphores  Folder java semaphore shows a java semaphore class from java.util.concurrent.Semaphore.  Similar to book figure 6.7.  Folder semaphore shows how a semaphore might be implemented

28 Synchronization: The Producer/consumer problem  Producer process creates or produces something  Consumer process uses or consumes something  Consumer cannot consume what has not been produced  Producer cannot produce until the previous thing has been consumed.  Their critical sections must alternate.

29 producer/consumer solution Initially, set s=1 and t=0 ProducerConsumer loop : P(s) store result V(t) : forever loop : P(t) get result V(s) : forever

30 Bounded Buffer problem  Producer stores things into a circular queue  Consumer consumes from the circular queue  Each thing is consumed once  Producer cannot store more than the queue can hold  Consumer cannot use what has not yet been stored there  Generalization of the producer/consumer problem

31  Solution is the same as that in the producer- consumer problem except initially set s=N (number of buffers).

32 variations on the producer consumer problem:  Two producers (any order), one consumer, etc.  Two producers (fixed order), one consumer, etc.  Either of two producers (not both), one consumer, etc.  Various combinations of one producer and two consumers.

33 Readers and Writers problem  If a reader wants access, deny iff a writer is active  if a writer wants access, deny only iff a reader or writer is active  The following solution is similar to book’s figures 6.15-6.19.

34 WriterReader loop : P(wrt) write result V(wrt) : forever loop : P(s) readcount++ if readcount == 1 P(wrt) V(s) read data P(s) readcount-- if readcount == 0 V(wrt) V(s) : Forever

35  Linux Semaphores: see the Linux demos.


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