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Chapter 4 Modelling and Analysis for Process Control
Laplace Transform Definition
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Input signals
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(c) A unit impulse function (Dirac delta function)
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* Properties of the Laplace transform
Linearity Differentiation theorem
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Zero initial values Proof:
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Integration theorem
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Translation theorem Proof:
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Final value theorem Initial value theorem
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Complex translation theorem
Complex differentiation theorem
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Example 4.1 Solution:
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Example 4.2 (S1)
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(S2)
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* Laplace transform procedure for differential equations
Steps:
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Exercises: a second-order differential equation
(1) Laplace transform
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Algebraic rearrangement
Zero initials (2) Transfer function
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(3) Laplace Inversion Where
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Inversion method: Partial fractions expansion (pp.931)
(i) Fraction of denominator and
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(ii) Partial fractions
where
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* Repeated roots (iii) Inversion
If r1=r2, the expansion is carried out as
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where Inversion
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* Repeated roots for m times
If the expansion is carried out as
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and
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and A3=2 as (a) case.
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The step response: Example 4.3
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(S1)
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(S3) Find coefficients s=0 Inversion
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Example 4.4 (S1) Laplace transformation
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(S2) Find coefficients s=0 s=1-j s=-1+j
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(S3) Inversion and using the identity
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Time delays: Consider Y(s)=Y1(s)e-st0 and
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Example:
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Input function f(t)
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* Input-Output model and Transfer Function
Ex.4.5 Adiabatic thermal process example
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S1. Energy balance
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S2. Under steady-state initial conditions
and define deviation variable
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S3. Standard form where
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S4. Transfer function (Laplace form)
@ Step change ( )
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* Non-adiabatic thermal process example
S1. model S2. Under deviation variables, the standard form
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where
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S3. Laplace form @ Transfer functions
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Ex. 4.6 Thermal process with transportation delay
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@ Dead time
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@ Transfer functions
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※ Transfer function (G(s))
Note: The transfer function defines the steady-state and dynamic characteristic, or total response, of a system described by a linear differential equation.
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*Important properties of G(s)
Physical systems, Transforms of the derivation of input and output variables Steady state responses
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* Steady-state gain ( ) Ex. Consider two isothermal CSTRs in series
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Ans.: Steady-state gain: Final value of the reactant concentration in the second reactor:
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※ Block diagrams
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@ Block diagram for
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Example 4.7 Block diagram for
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* Rules for block diagram
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Example 4.8 Determine the transfer functions
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Solution: ◎
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Example 3-4.3 Determine the transfer functions
=?
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@ Reduced block
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Example 4.9 =?
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◎ Answer
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◎ Design steps for transfer function
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@ Review of complex number
c=a+ib
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Polar notations
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※ Frequency response
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◎ Experimental determination of frequency response
S1. Process (valve, model, sensor/transmitter)
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S2. Input signal S3. Output response where
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P1. Amplitude of output signal
P2. Output signal ‘lags’ the input signal by θ. P3. Amplitude ratio (AR): AR=Y0/X0 P4. Magnitude ratio (MR): MR=AR/K P5. Phase angle (θ): if θ is negative, it is a lag angle.
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Ex.4.7 A first-order transfer function G(s)=K/(τs+1)
* Consider a form of If the input is set as Then the output
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*Through inverse Laplace transformation, the output response is reduced as
P2. (p.69)
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Ex.4.8 Consider a first-order system
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S2. Amplitude ratio and phase angle
Ex.4.9 Consider a second-order system
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S1. s=iω to decide amplitude ratio
#
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G(s)=K(1+τs) S2. Phase angle #
Ex.4.10 Consider a first-order lead transfer function G(s)=K(1+τs)
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Ex.4 Consider a pure dead time transfer function
G(s) =e-t0s
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Ex.5 Consider an integrator
G(s)=1/s G(i)=-(1/ )i
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* Expression of AR and θ for general OLTF
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※ Bode plot A common graphical representation of AR (MR) and θ functions. Bode plot consists: (1) log AR or (log MR) vs. log ω (2) θ vs. log ω * (3) 20 log AR (db) vs. log ω
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Ex. 5 Consider a first-order lag by Ex. 1
To show Bode plot. S1. MR1 as ω 0 S2. As ω
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# * Types of Bode plots Gain element First-order lag Dead time Second-order lag First-order lead Integrator
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* Process control for a chemical reactor
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Homework 2# Q4.6 Q4.10 Q4.16 Q4.18 (※Difficulty)
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