1. Bridging Theory in Practice Transferring Technical Knowledge to Practical Applications

2. Advanced Power Dissipation and AC Thermal Analysis

3. Intended Audience: Engineers interested in advanced thermal design under AC (variable duty cycle and transient) conditions A basic knowledge of DC thermal analysis is required Topics Covered: Modeling thermal performance with electrical parameters Explanation of thermal RC networks Introduction of the Z th Diagram AC thermal calculations Complex waveform (superposition principle) thermal calculations Expected Time: Approximately 60 minutes

4. Advanced Power Dissipation and AC Thermal Analysis Electrical Parameters vs. Thermal Parameters Thermal Resistance and Capacitance Networks Understanding the Z th Diagram Example AC Thermal Calculations Complex Waveforms and Superposition

5. Electrical vs. Thermal DC Parameters Electrical ParametersThermal Parameters I R VV + - V = I R R = Electrical Resistance (  ) V = Potential Difference (V) I = Current (A)  T = P D R th R th = Thermal Resistance (C/W)  T = Temperature Difference (C) P D = Power Dissipated (W) PDPD R th TT + -

6. Electrical Resistance vs. Thermal Resistance Electrical ResistanceThermal Resistance I = Current A = Area d = Thickness  = Electrical Conductivity R = Electrical Resistance (  ) I A } d  R P D = Power Dissipated A = Area d = Thickness th = Thermal Conductivity R th = Thermal Resistance (C/W) V + - PDPD A } d th R th TT + -

7. Electrical Circuits vs. Thermal Circuits Electrical CircuitsThermal Circuits I R VV + - PDPD R th TT + - I = 10A R = 1   V = IR  V = (10A)(1  ) = 10V 10V Potential Difference P D = 10W R th = 1C/W  T = P D R th  T = (10W)(1C/W) = 10C 10C Temperature Difference

8. Electrical vs. Thermal Parameters Electrical ParametersThermal Parameters + C th E - TT + C Q - V C = Capacitance (Farads = A-sec / V) C th = Thermal Capacitance (Joules / C = Watts-sec / C)

9. Advanced Power Dissipation and AC Thermal Analysis Electrical Parameters vs. Thermal Parameters Thermal Resistance and Capacitance Networks Understanding the Z th Diagram Example AC Thermal Calculations Complex Waveforms and Superposition

10. Die Attach C th3 – R th3 Leadframe Silicon C th2 – R th2 Thermal Resistance & Capacitance Example Silicon Wafer Cross Section p + Well C th1 - R th1 Leadframe Metal

11. Thermal RC Network - Internal Chip  T T junction C th1 C th2 C th3 T ambient R th1 R th2 R th3 PDPD Temperature ~ Voltage Power ~ Current

12. Thermal RC Network – Total Temperature ~ Voltage Power ~ Current Chip  T T junction C th1 C th2 C th3 T ambient R th1 R th2 R th3 PDPD Heatsink T case R inteface R heatsink C interface C heatsink

13. Junction Temperature Calculations With temperature analogous to voltage,  T Is determined by the P D and the RC network Chip  T T junction C th1 C th2 C th3 T ambient R th1 R th2 R th3 PDPD Heatsink T case

14. Junction Temperature Calculations The maximum junction temperature is specified in the absolute maximum section of the data sheet (T j,max ) Chip  T T junction C th1 C th2 C th3 T ambient R th1 R th2 R th3 PDPD Heatsink T case

15. Junction Temperature Calculations The device junction-to-case thermal resistance (R thjc ) is specified in the datasheet and determines  T jc. R thjc is usually valid for DC only  T jc Chip  T T junction C th1 C th2 C th3 T ambient R th1 R th2 R th3 PDPD Heatsink T case

16. Chip  T T junction C th1 C th2 C th3 T ambient R th1 R th2 R th3 PDPD Heatsink T case Junction Temperature Calculations The external case-to-ambient thermal resistance, (R thca ) is determined by the heatsink. This determines the temperature change from the case to the ambient.  T ca

17. DC Junction Temperature Calculations Under DC conditions, power and temperature reach steady state conditions and the thermal capacitors are removed from the circuit model Chip  T T junction T ambient R th1 R th2 R th3 PDPD Heatsink T case

18. DC Junction Temperature Calculation Power Dissipation P D = I ds 2 R dson = (5A) 2 (24m  ) = 0.6W Thermal Resistance R thja = 55 C/W Junction Temperature T junction = T ambient + P D R thja T junction = 85C + (0.6W)(55C/W) T junction = 85C + 33C = 118C DC Calculations are relatively simple

19. Z th (j  ) = ? Z th (t) = ? AC Junction Temperature Calculation of Transfer Function Chip  T T junction C th1 C th2 C th3 T ambient R th1 R th2 R th3 PDPD Heatsink T case

20. AC Junction Temperature Calculation of Transfer Function

21. Simplified AC Thermal RC Network Chip  T T junction T ambient R’ th1 R’ th2 R’ th3 PDPD Heatsink T case C’ th1 C’ th2 C’ th3 Thermal capacitance now in parallel with thermal resistance

22. The new RC component values of the simplified network are obtained by mathematical transformations. They do NOT refer to any physical layer. Together, they describe the overall thermal behavior and performance of the device and heatsink. Chip  T T junction T ambient R’ th1 R’ th2 R’ th3 PDPD Heatsink T case C’ th1 C’ th2 C’ th3 Simplified AC Thermal RC Network

23. Chip  T T junction T ambient R’ th1 R’ th2 R’ th3 PDPD Heatsink T case C’ th1 C’ th2 C’ th3 Frequency Domain Time Domain

24. AC Temperature Calculation Simplified Transfer Function  T( t ) = P D (t) Z th ( t) Tj(t)P(t) Z th

25. Advanced Power Dissipation and AC Thermal Analysis Electrical Parameters vs. Thermal Parameters Thermal Resistance and Capacitance Networks Understanding the Z th Diagram Example AC Thermal Calculations Complex Waveforms and Superposition

26. Development of the Z th Diagram Create test set-up for integrated circuit package types Power is generated in the integrated circuit for defined lengths of time The resulting temperature rise is measured A thermal impedance (Zth) diagram is generated Tj(t)P(t) Z th

27. Z thja (C / W) 0.01 0.1 1.0 10.0 100.0 t pulse (sec) 1E-51E+3 Duty Cycle 50% 20% 10% 5% 2% 1% Single Pulse 1E-31E-11E+1 Z th Diagram for the TO-263 Package

28. Z thja (C / W) 0.01 0.1 1.0 10.0 100.0 t pulse (sec) 1E-51E+3 Duty Cycle 50% 20% 10% 5% 2% 1% Single Pulse 1E-31E-11E+1 Single Pulse P(t) PDPD t pulse

29. Z thja (C / W) 0.01 0.1 1.0 10.0 100.0 t pulse (sec) 1E-51E-31E-11E+11E+3 Duty Cycle 50% 20% 10% 5% 2% 1% Single Pulse Periodic event: P(t) PDPD t pulse T Duty Cycle: Z th Diagram for the TO-263 Package

30. Z th Diagrams for Different Packages TO-263-5-1 t p = 1s Z thja  2C/W TO-252-3-1 t p = 1s Z thja  4C/W SOT-223 t p = 1s Z thja  30C/W SO-8 t p = 1s Z thja  65C/W

31. Advanced Power Dissipation and AC Thermal Analysis Electrical Parameters vs. Thermal Parameters Thermal Resistance and Capacitance Networks Understanding the Z th Diagram Example AC Thermal Calculations Complex Waveforms and Superposition

32. PDPD 400W t pulse t pulse = 200µs T iunction (t) T peak T peak = ? Single Pulse in a TO-263 Package 25C

33. Duty Cycle 50% 20% 10% 5% 2% 1% Single Pulse Single Pulse in a TO-263 Package Z thja (C / W) 0.01 0.1 1.0 10.0 100.0 t pulse (sec) 1E-51E-31E-11E+11E+3 Duty Cycle 50% 20% 10% 5% 2% 1% Single Pulse t pulse = 2E-4 s Z thja  0.083 C/W

34. Power Dissipation P D = 400W Thermal Resistance Z thja = 0.083 C/W Junction Temperature T junction,peak = T ambient + P D Z thja T junction,peak = 25C + (400W)(0.083C/W) T junction,peak = 25C + 33C = 58C Single Pulse in a TO-263 Package

35. Single Pulse – TO-263 Package Saber Simulation 0100200300400500600700 Time (  s) P D,max = 400W 400W 350W 300W 250W 200W 150W 0W 100W 50W 55C 50C 45C 40C 35C 30C 25C T junction,peak = 55C

36. 50% Duty Cycle in a TO-263 Package PDPD 1.44W t pulse = 200µs t period = 400µs T iunction (t) T peak T peak = ? 25C

37. Duty Cycle 50% 20% 10% 5% 2% 1% Single Pulse 50% Duty Cycle in a TO-263 Package Z thja (C / W) 0.01 0.1 1.0 10.0 100.0 t pulse (sec) 1E-51E-31E-11E+11E+3 t pulse = 2E-4 s Z thja  23 C/W

38. Power Dissipation P D = 1.44W Thermal Resistance Z thja = 23 C/W Junction Temperature T junction = T ambient + P D Z thja T junction = 25C + (1.44W)(23C/W) T junction = 25C + 33C = 58C 50% Duty Cycle in a TO-263 Package

39. Advanced Power Dissipation and AC Thermal Analysis Electrical Parameters vs. Thermal Parameters Thermal Resistance and Capacitance Networks Understanding the Z th Diagram Example AC Thermal Calculations Complex Waveforms and Superposition

40. Complex Pulse-Superposition MOSFET Turn On I DS 1.V IN goes HI 2.I DS increases 3.V DS decreases 4.P LOSS spikes 1. V IN 2. I DS 4. P LOSS 3. V DS

41. I DS Complex Pulse-Superposition MOSFET Turn On 2. I DS 4. P LOSS 3. V DS Pulse 1: t START 20µS t STOP 50µS Pulse 2: t START 25µS t STOP 50µS Pulse 3(neg): t START 40µS t STOP 50µS Pulse 4(neg): t START 45µS t STOP 50µS 1. V IN

42. Complex Pulse-Superposition MOSFET Turn On Power Time t=5µs At t = 5µs: t PULSE,1 = 5µsec t PULSE,2 = t PULSE,3 = t PULSE,4 = 0  T J1 (5µs) = Z TH (5µs)*P PULSE,1

43. Complex Pulse-Superposition MOSFET Turn On Power Time t=20µs At t = 20µs: t PULSE,1 = 20µsec t PULSE,2 = 15µsec t PULSE,3 = t PULSE,4 = 0  T J2 (20µs) = Z TH (20µs)*P PULSE,1 + Z TH (15µs)*P PULSE,2

44. Complex Pulse-Superpositon MOSFET Turn On Power Time t=25µs At t = 25µs: t PULSE,1 = 25µsec t PULSE,2 = 20µsec t PULSE,3 = 5µsec t PULSE,4 = 0  T J3 (25µs) = Z TH (25µs)*P PULSE,1 + Z TH (20µs)*P PULSE,2 - Z TH (5µs)*P PULSE,3

45. Complex Pulse-Superpositon MOSFET Turn On Power Time t=30µs At t = 30µs: t PULSE,1 = 30µsec t PULSE,2 = 25µsec t PULSE,3 = 10µsec t PULSE,4 = 5µsec  T J4 (30µs) = Z TH (30µs)*P PULSE,1 + Z TH (25µs)*P PULSE,2 - Z TH (10µs)*P PULSE,3 - Z TH (5µs)*P PULSE,4

46. Complex Pulse-Superpositon MOSFET Turn On I DS 4. P LOSS Pulse 1: t START 20µS t STOP 50µS Pulse 2: t START 25µS t STOP 50µS Pulse 3(neg): t START 40µS t STOP 50µS Pulse 4(neg): t START 45µS t STOP 50µS T J1 T J2 T J3 T J4

47. Advanced Power Dissipation and AC Thermal Analysis Electrical Parameters vs. Thermal Parameters Thermal Resistance and Capacitance Networks Understanding the Z th Diagram Example AC Thermal Calculations Complex Waveforms and Superposition

48. Advanced Power Dissipation and AC Thermal Analysis

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