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Solution 2nd Exam.

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Presentation on theme: "Solution 2nd Exam."— Presentation transcript:

1 Solution 2nd Exam

2 f=f+A[2]; B[8] = A[i] + A[j]; LW $t0, 8($s6) ADD $s0, $s0, $t0
SLL $t0, $s3, 2 ADD $t0, $s6, $t0 LW $t0, 0($t0) SLL $t1, $s4, 2 ADD $t1, $s6, $t1 LW $t1, 0($t1) ADD $t2, $t0, $t1 SW $t2, 32($s7)

3 for (i = 0; i < 10; i++) a = a + b + 1; add $t0, $zero, $zero LOOP: slti $t1, $t0, 10 beq $t1, $zero, EXIT add $s0, $s0, $s1 addi $s0, $s0, 1 addi $t0, $t0, 1 j LOOP EXIT: 7 instructions total number is *6 +2 = 63

4 int compare(int a, int b) { if (a < b) return 1; else return 0; }
slt $t0, $a0, $a1 addi $v0, $zero, 1 bne $t0, $zero, EXIT addi $v0, $zero, 0 EXIT: jr $ra

5 int compare(int a, int b) { if (subit (a, b) <0) return 1; else return 0; } int subit (int a, int b) return a-b;

6 COMPARE: EXIT: SUBIT: addi $sp, $sp, -4 sw $ra, 0($sp) jal SUBIT
addi $t1, $zero, 1 slti $t0, $v0, 0 #subit(a,b)<0 -> $t0=1 bne $t0, $zero, EXIT addi $t1, $zero, 0 EXIT: add $v0, $t1, $zero lw $ra, 0($sp) addi $sp, $sp, 4 jr $ra SUBIT: sub $v0, $a0, $a1


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