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Modern Physics By Neil Bronks
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Atoms C 12 6 Mass Number Mass Number - Number of protons + Neutrons. Atomic Number Atomic Number - Number of protons In a neutral atom the number of electrons and protons are the same. In Carbon it is……… 6
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4 Forces of Nature Gravitational - Only Positive - Very long range Weak Nuclear- Associated with beta decay Strong Nuclear – Holds nucleus together - Very Short Range Electromagnetic – Positive and negative
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Radiation Decay of nucleus by the emission of a particle or a ray. Discovered by Henri Becquerel Units 1 Bq is one decay per second Natural happens without outside bombardment Artificial happens due to bombardment J’ai fais ça ! Dodgy Beard
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Alpha Particles Helium Nuclei Positive Charge Heavy so not very penetrating Very Ionizing Very Ionizing 14 7 N + 4 2 He 17 8 O + 1 1 H
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Beta Particle ß Fast electron from the nucleus Negative charge Moderately Penetrating Moderately ionizing 14 7 N 14 8 O + 0 -1 ß
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Gamma Ray High energy e-m wave (A Photon) No charge - not deflected by field Very penetrating – Need lead to stop most of them Not very ionizing Release energy after reaction
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Penetrating Power Paper Al foil Concrete
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Particles in Fields Charged particles move in a circular path as the force is always at right angles to the direction of motion- Fleming's Left Hand Rule
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Solid State Detector PN This a P-N junction in reverse bias. This creates a huge depletion layer. + - A piece of radiation passes through the depletion layer and creates enough carriers to carry one pulse of current.
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Experiments All experiments the same stick a DETECTOR in front of a source and count the decays. Move it away for distance and plot Time for half life and plot Put things in front for penetration
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Half-Life Atoms Not Decayed Time 1234
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Calculations =0.693/T ½ =0.693/3s =0.231s -1
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Activity Calculations Rate of Decay = x number you started with dN/dt = - x N Start with 4000 particles and =0.231 Activity = 4000 x 0.231=924 Bq
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Isotopes Same atomic number different mass number
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Rutherford Scattering – alpha particles fired at gold foil. Nucleus Deflected A small number of high energy alphas are Deflected very small More pass unaffected - So the nucleus is very small totally positive. Some reflected completely back - Nucleus totally positive.
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Cockcroft and Walton Alpha pha Lithium Target Alpha Hydrogen discharge tube Accelerated by An electric field Proton Alpha strikes the screen Producing a flash that Is seen with the microscope 4000kv 0kv
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Nobel Prize for Physics Proton + Lithium 2xAlpha + Energy Proves Einstein ’ s Law E=mc 2 First Transmutation by artificial Bombardment of an element Ernest Walton
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Use Famous Formula E=mc 2 E=mc 2 E= x 2 E= 3.96x10 -30 Kg x (3x10 8 m/s) 2 E = E = 3.56x10 -13 Joules
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Fusion Fusion is the joining together of 2 light nuclei to make one nucleus with release of energy. Fusion is the joining together of 2 light nuclei to make one nucleus with release of energy. Caused by a super fast collision at high temperature in a magnetic bottle. Caused by a super fast collision at high temperature in a magnetic bottle. 21H21H 21H21H
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1.Subtract mass in a.m.u. 2.Convert to kg 3.Use E=mc 2 Also produced 3 fast neutrons that can cause another fission and so a chain reaction Uranium-235 Fission-The breaking apart of a heavy nucleus to form smaller products with release of energy.
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Fuel rods contain the Uranium-235 (Enriched to ensure chain reaction) Moderators slow down the neutrons to the right speed Control Rods stop the reaction and prevent meltdown Hot water to turbine
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Leptons Fundamental particles 1/1846 of an a.m.u. Does not feel the strong nuclear force Matter – Electron, Muon, Tau, …… Anti-matter – Positron, Anti-Tau Anti-matter first suggested by Paul Dirac
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Annihilation e+e+ e-e- An electron and a positron collide to make energy. All the mass of the electrons gets turned into gamma waves So Energy E=mc 2 To find frequency of wave E = 2h.f Matter turns Into energy Matter combining with anti-matter to form energy in the form of e-m radiation
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Use Planks Equation E=hf h= planks constant f= frequency 3.01x10 -10 Joules = (6.6x10 -34 js)x(f) f= 3.01x10 -10 Joules / 6.6x10 -34 js = 4.56x10 23 Hz
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Pair Creation e+e+ e-e- An electron and a positron are created from a gamma ray. (We can also get a proton and an anti-proton) We do the calculation in reverse To find energy of wave E = h.f As we get 2 electrons E = 2mc 2 A matter and anti-matter pair being created by energy from an e-m wave
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Annihilation and Production p+p+ p-p- New particles are produced from the KE of the colliding protons They must conserve charge If we carry in 4Gev (1.6x10 -19. 4x10 9 = 4x10 -10 J) As Energy to make 3 Pions is E=mc 2 =(3x 2.4842x10 -28 xcxc) =6.7x10 -11 J Subtracting we find the KE after collision. p+p+ p-p- +0-+0-
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Quarks - Inside the Hadrons 6 Quarks 6 Anti-Quarks – Opposite Signs UP +2/3 STRANGE -1/3 TOP +2/3 DOWN -1/3 CHARMED +2/3 BOTTOM -1/3
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Baryon Meson
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Beta decay In β− decay, the weak force converts a neutron into a proton while emitting an electron and an antineutrino n 0 → p + + e - + ν e This explains loss in energy and momentum. Pauli proposed it’s existence in 1930 but was not discovered until 1956 as it is so weakly interacting with other particles.
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Subject to all forces Particle Zoo Hadrons Leptons Fundamental particles Do not feel Strong Nuclear Force Baryons 3 Quarks Proton uud Mesons Quark + Anti-quark Pion ud
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