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ORGANOHALIDES + Nucleophilic Reactions (SN1/2, E1/E2/E1cB)
CH21 PS CLASS
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Preparation of Organohalides
From ALKENES C=C [just review old lessons] FOR TERTIARY ALCOHOLS, we can simply use H-X (gas) X=Cl,Br in ether, 0°C
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Preparation of Organohalides
FOR TERTIARY ALCOHOLS, we can simply use H-X (gas) X=Cl,Br in ether, 0°C Follows SN1 so a carbocation is formed, be careful with rearrangements!
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Preparation of Organohalides
FOR PRIMARY/SECONDARY ALCOHOLS: SOCl2 / PBr3
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Practice
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Alkyl Fluorides Also from ALCOHOLS + HF / Pryidine (CH3CH2)2NSF3
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Grignard Reagents Reaction of R-X with Mg over ether/THF to form R-Mg-X organometallic compound.
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Grignard Reagents: reduction of R-X
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More samples:
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Nucleophilic Reactions
R-X, alkyl halides are ELECTROPHILES (positive or electron-poor) They react with NUCLEOPHILES/BASES (negative or electron-rich) Either substitution C-C-X becomes C-C-blah + X- or elimination reactions C-C-X becomes C=C + X-
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SUBSTITUTION REACTIONS
S – substitution: R-X + Nu R-Nu + X- N – Nucleophilic 1 or 2 unimolecular or bimolecular rates INVERSION (change of stereochemistry) CAN HAPPEN!
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Try this first…
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SN2 BIMOLECULAR Bimolecular simply refers to the rate depending on BOTH reactants because of the nature of the mechanism Rate = k[RX][Nu] Rate depends on both because there is ONE SINGLE COLLISION BETWEEN RX and Nu to form a Nu-R-X transition state
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SN2 BIMOLECULAR 100% INVERSION OF STEREOCHEMISTRY OCCURS! SUBSTRATE
LEAVING GROUP
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Factors that affect SN2 RXNS:
STERIC EFFECTS TO INCOMING Nu: C=C-X (vinylic) and Ar-X (aryl) TOTALL UNREACTIVE
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Factors that affect SN2 RXNS:
THE NUCLEOPHILE
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Factors that affect SN2 RXNS:
THE LEAVING GROUP should be stable on its own as a free anion Comparing halides, we go down the column
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Factors that affect SN2 RXNS:
Alcohols and fluorides usually do not undergo SN2 because OH- and F- aren’t good leaving groups This is why we use SOCl2 and PBr3 … THEY CONVERT THE –OH INTO A BETTER LEAVING GROUP
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Factors that affect SN2 RXNS:
Reaction SOLVENT can also affect the reaction. We prefer POLAR APROTIC SOLVENTS POLAR but no –OH or –NH in the molecule (no H2O, NH3, etc…) Polar protic solvents form a CAGE around Nu
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Practice
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Practice
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Practice
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Practice
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SN1 UNIMOLECULAR Unimolecular: rate depends only on the substrate (mechanism), almost opposite of SN2 Rate = k[RX] Rate is only dependent on the slowest step which is the spontaneous dissociation of your leaving group. (molecules just don’t easily dissociate!)
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SN1 UNIMOLECULAR
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SN1 UNIMOLECULAR
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SN1 UNIMOLECULAR STEREOCHEM IS LOST, A RACEMATE FORM IS MADE, but usually not 50:50
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SN1 UNIMOLECULAR STEREOCHEM IS LOST, A RACEMATE FORM IS MADE, but usually not 50:50 An ION PAIR BLOCKS THE OTHER SIDE!
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Factors that affect SN1 RXNS:
SUBSTRATE:
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Factors that affect SN1 RXNS:
LEAVING GROUP: An –OH in acidic medium can become –OH2+ and leave as H2O which is very favorable
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Factors that affect SN1 RXNS:
NUCLEOPHILE: no effect, almost at all.
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Factors that affect SN1 RXNS:
SOLVENT: rates increase if you stabilize carbocation transition state. POLAR PROTIC!
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Factors that affect SN1 RXNS:
SOLVENT: rates increase if you stabilize carbocation transition state. POLAR PROTIC!
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PRACTICE
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PRACTICE
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PRACTICE
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PRACTICE
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PRACTICE
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PRACTICE
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PRACTICE
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Elimination Reactions
More compliated (different mechanisms) The loss of H-X can lead to a MIXTURE of alkene products (C-C-X C=C + HX) But we can predict the most stable/major poduct ZAITZEV’S RULE: base-induced eliminations will form more stable alkene
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E2 elimination Again, bimolecular so a single collision between your Base B: and the alkyl halide.
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E2 elimination Anti-periplanar is favored for transition state
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E2 elimination Anti-periplanar is favored for transition state
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Practice
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Practice
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Practice
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Practice
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E1 reaction Unimolecular, ALSO spontaneously forms carbocation, but then followed by loss of H+ (taken by a base B: and not an attack by Nu:) COMPETES WITH SN1 reactions!
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E1 reaction
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E1 reactions No need for anti periplanar geometry
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PRACTICE
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PRACTICE
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E1cB Unimolecular, but this time CARBANION formed because a proton H+ is first removed by a base. cB stands for “conjugate base” because you deprotonate your carbon C-H into a C- and H+ Usually favored for poor leaving groups (e.g. –OH) Carbanion can be stabilized with C=O groups nearby
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E1cB
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E1cB PRESENCE OF C=O NEARBY CAN GIVE RESONANCE STABILIZATION!
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PREDICTING WHAT PREDOMINATES:
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Slight Clarifications: BASE vs. NUCLEOPHILE
Affinity for a PROTON Strong base like R-O- or OH- Usually a LEWIS BASE In this context, how attracted to a CARBON
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PRACTICE
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