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Calculus 2.1 Introduction to Differentiation
Mrs. Kessler
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Rate of Change To begin our study of rates and changes we must realize that the rate of change is the change in y divided by the change in x. We are assuming two points With a straight line, this has been the slope, m. with However, with a curve, this is a little more complicated.
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Examples of tangents of curves
Since the curve is increasing and decreasing at different rates, we are looking for the instantaneous rate of change at a particular point. This means we need the slope of the tangent line at the point P.
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Approximating the slope of the tangent line with the secant line
x + x
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What happens as x gets smaller and sMALLER?
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Definition of the Slope of a Graph
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Definition of Derivative
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Example 1 Find the slope of f(x) = 7x - 4 using the limit process
But you already knew that.
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Ex 2. Find f ′(x) if using the limit process
Notice that the slope, or derivative, has a variable.
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Ex. 3 Find the equation of the line tangent to at (1, 2)
From before Let’s look graphically at this:
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Ex. 3 Find the equation of the line tangent to at (1, 2)
From before At x =1 m = ¼ point = (1, 2) y - y1= m (x – x1)
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Find f′(x) if using the limit process
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Find f′(x) if using the limit process
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Find equation of the line tangent to and parallel to y = 2x -7
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That’s what we are looking for! Find its equation.
Find equation of the line tangent to and parallel to y = 2x -7 Original function That’s what we are looking for! Find its equation. Original function plus line
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Find equation of the line tangent to and parallel to y = 2x -7
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is the slope of the tangent line at any point x.
Continued: is the slope of the tangent line at any point x. We want a tangent line parallel to y = 2x – 7 We can see m = 2 in y = 2x – 7 and from the calculus, m = . Now set the slopes equal and solve for x. Now sub back into the original function, and find y. y = 1/4
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Now find the equation y – y1 =m ( x – x1)
At the point (17/16, ¼), the tangent line is parallel to Now find the equation y – y1 =m ( x – x1)
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Day Questions?????????
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y = x2. The two tangent lines intersect at (1, -3).
Find their equations. (x1, y1) (1, -3) Let the red dot be the point (x1, ,y1). By the delta process the derivative is 2x. At the point (x1 ,y1), the derivative which is the slope = 2x1. Now use the slope formula setting the two =.
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The tangent points are ( 3, 9) and (-1, 1) If x =3, f(x) = y = 9
y = x2. The two tangent lines intersect at (1, -3). Find their equations. (x1, y1) Cross multiply and set equal to 0. Note: y1=(x1)2 (1, -3) The tangent points are ( 3, 9) and (-1, 1) If x =3, f(x) = y = 9 If x = -1, f(x) = y = 1
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Now find the equation of the line.
y = x2. The two tangent lines intersect at (1, -3). Find their equations. The tangent points are ( 3, 9) and (-1, 1) Now find the equation of the line. y - y1= m ( x – x1) (x1, y1) (1, -3) For first equation use ( 3, 9) and (1, -3) For second equation use ( -1, 1) and (1, -3) y = 6x – and y = - 2x -1 Graph and check.
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Weird Tangents - no derivative
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Alternative form of the derivative
provided the limit exists. exist and are equal.
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Alternative form of the derivative
at x = 4 Since the limit from left is not equal to the limit from the right, there is no limit, which means there is no derivative at x = 4 even though the function is continuous there.
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Continued
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Using the TI 83/84 to draw the tangent line
Enter the function into the y -editor. Graph the function: y = x sin(x) Suppose I want the tangent at x = π/3. Press 2nd Draw 5 Type π/3 Note: Decimal place was set a 3 fixed places.
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