Presentation is loading. Please wait.

Presentation is loading. Please wait.

EXAMPLE 1 Standardized Test Practice SOLUTION Substitute several values of h into the equation C = 10 + 7h and solve for C.Then identify the table that.

Published bySkylar Vaughn Modified over 9 years ago

Similar presentations

Presentation on theme: "EXAMPLE 1 Standardized Test Practice SOLUTION Substitute several values of h into the equation C = 10 + 7h and solve for C.Then identify the table that."— Presentation transcript:

1 EXAMPLE 1 Standardized Test Practice SOLUTION Substitute several values of h into the equation C = 10 + 7h and solve for C.Then identify the table that contains the solutions.

2 EXAMPLE 1 Standardized Test Practice h -value Substitute for h. Evaluate. Solution (h, C) h = 1C = 10 + 7(1) h = 2 h = 3 h = 4 C = 10 + 7(2) C = 10 + 7(3) C = 10 + 7(4) C = 17 C = 24 C = 31 C = 38 (1, 17) (2, 24) (3, 31) (4, 38) ANSWER The correct answer is C.

3 GUIDED PRACTICE for Example 1 What If? In Example 1, suppose the store rounds your time up to the nearest half hour. How long can you skate if you have $35 ? 1.1. ANSWER You can skate for 3.5 hours or less.

Download ppt "EXAMPLE 1 Standardized Test Practice SOLUTION Substitute several values of h into the equation C = 10 + 7h and solve for C.Then identify the table that."

Similar presentations

Solving Equations. -132 = 4x – 5(6x – 10) -132 = 4x – 30x + 50 -132 = -26x + 50 -182 = -26x 7 = x.

Solving Equations = 4x – 5(6x – 10) -132 = 4x – 30x = -26x = -26x 7 = x.
Example 1 Solve the linear system. Solving a Linear System by Graphing y+x = 5 y = 2x2x 1 – SOLUTION STEP 1 Graph both equations as shown. STEP 2 Estimate.

Example 1 Solve the linear system. Solving a Linear System by Graphing y+x = 5 y = 2x2x 1 – SOLUTION STEP 1 Graph both equations as shown. STEP 2 Estimate.
EXAMPLE 3 Standardized Test Practice SOLUTION

EXAMPLE 3 Standardized Test Practice SOLUTION
EXAMPLE 1 Solve quadratic equations Solve the equation. a. 2x 2 = 8 SOLUTION a. 2x 2 = 8 Write original equation. x 2 = 4 Divide each side by 2. x = ±

EXAMPLE 1 Solve quadratic equations Solve the equation. a. 2x 2 = 8 SOLUTION a. 2x 2 = 8 Write original equation. x 2 = 4 Divide each side by 2. x = ±
Solve an equation with variables on both sides

Solve an equation with variables on both sides
EXAMPLE 1 Solve a quadratic equation having two solutions Solve x 2 – 2x = 3 by graphing. STEP 1 Write the equation in standard form. Write original equation.

EXAMPLE 1 Solve a quadratic equation having two solutions Solve x 2 – 2x = 3 by graphing. STEP 1 Write the equation in standard form. Write original equation.
Solve an absolute value equation EXAMPLE 2 SOLUTION Rewrite the absolute value equation as two equations. Then solve each equation separately. x – 3 =

Solve an absolute value equation EXAMPLE 2 SOLUTION Rewrite the absolute value equation as two equations. Then solve each equation separately. x – 3 =
EXAMPLE 3 Write an equation for a function

EXAMPLE 3 Write an equation for a function
EXAMPLE 3 Solve a multi-step problem Many businesses pay website hosting companies to store and maintain the computer files that make up their websites.

EXAMPLE 3 Solve a multi-step problem Many businesses pay website hosting companies to store and maintain the computer files that make up their websites.
Write decimal as percent. Divide each side by 136. Substitute 51 for a and 136 for b. Write percent equation. Find a percent using the percent equation.

Write decimal as percent. Divide each side by 136. Substitute 51 for a and 136 for b. Write percent equation. Find a percent using the percent equation.
Solve an equation using subtraction EXAMPLE 1 Solve x + 7 = 4. x + 7 = 4x + 7 = 4 Write original equation. x + 7 – 7 = 4 – 7 Use subtraction property of.

Solve an equation using subtraction EXAMPLE 1 Solve x + 7 = 4. x + 7 = 4x + 7 = 4 Write original equation. x + 7 – 7 = 4 – 7 Use subtraction property of.
Standardized Test Practice EXAMPLE 4 ANSWER The correct answer is B. DCBA Simplify the expression 4(n + 9) – 3(2 + n). 4(n + 9) – 3(2 + n) = Distributive.

Standardized Test Practice EXAMPLE 4 ANSWER The correct answer is B. DCBA Simplify the expression 4(n + 9) – 3(2 + n). 4(n + 9) – 3(2 + n) = Distributive.
Standardized Test Practice

Standardized Test Practice
EXAMPLE 5 Solve a multi-step problem Recording Studio

EXAMPLE 5 Solve a multi-step problem Recording Studio
Standardized Test Practice

Standardized Test Practice
EXAMPLE 1 Write an equation of a circle Write the equation of the circle shown. The radius is 3 and the center is at the origin. x 2 + y 2 = r 2 x 2 +

EXAMPLE 1 Write an equation of a circle Write the equation of the circle shown. The radius is 3 and the center is at the origin. x 2 + y 2 = r 2 x 2 +
EXAMPLE 2 Write a rule for the nth term Write a rule for the nth term of the sequence. Then find a 7. a. 4, 20, 100, 500,... b. 152, –76, 38, –19,... SOLUTION.

EXAMPLE 2 Write a rule for the nth term Write a rule for the nth term of the sequence. Then find a 7. a. 4, 20, 100, 500,... b. 152, –76, 38, –19,... SOLUTION.
Write an equation given two points

Write an equation given two points
Write and graph a direct variation equation

Write and graph a direct variation equation
EXAMPLE 2 Write a rule for the nth term a. 4, 9, 14, 19,... b. 60, 52, 44, 36,... SOLUTION The sequence is arithmetic with first term a 1 = 4 and common.

EXAMPLE 2 Write a rule for the nth term a. 4, 9, 14, 19,... b. 60, 52, 44, 36,... SOLUTION The sequence is arithmetic with first term a 1 = 4 and common.

Similar presentations

Ads by Google