1. Chapter 12 Stoichiometry Quantity

2. 12.1 Stoichiometry Chemical reactions represent the heart of chemistry: they describe the endless ways that substances can combine with each other to form new substances. In essence, they describe what chemistry really is -- the study of matter and its transformations through Chemical Reactions.

3. Ch 12 Stoichiometry is the area of chemistry which deals with quantitative relationships in chemical reactions. It is the area which allows chemists to know how much starting material is needed to produce a million pounds of sulfuric acid or how many molecules are in a microgram of a particular hormone.

4. When I worked in a semi trailer factory, guess who was highest paid
When I worked in a semi trailer factory, guess who was highest paid? Not the factory worker (Minimum wage) Not the welders (4 times minimum wage) Not the foreman (5 times minimum wage) It was the warehouse manager (6 times minimum wage) Why??? He had to know how to do Stoichiometry to produce the correct amount of chemicals needed for production.

5. Stoichiometry Predicting the quantities of products when given the quantities of reagents.

6. Stoichiometry Predicting the quantities of products when given the quantities of reagents.
Stoichiometry: Quantities are usually given in grams, kilograms, or pounds.
Are chemical equations in grams?

7. Stoichiometry Predicting the quantities of products when given the quantities of reagents.
Quantities are usually given in grams, kilograms, or pounds.
Are chemical equations in grams? No, in representative particles or moles.
Usually we have to:
1. Convert from grams to moles.
2. Work equations with moles.
3. Convert moles back to grams.

8. What is the mass of 2 moles of F2?
How much is in 2 moles of F2?
(written as 2 F2 )
Moles = 2 moles of F2
Molecules = 2 molecules of F (or 2 x 6.02 x 1023 molecules)
Atoms = 4 atoms F (or 4 x 6.02 x 1023 atoms)
Grams = 76g (F has atomic mass of 19)
(total grams in 2 moles of F2)
Liters = 44.8L (C.F. = 22.4 L per Mole at STP)

9. Stoichiometry (“stoy-key-AHM-uh-tree”)
The relationship between the quantities of reactants and products in a chemical reaction (Eqn next page.)

10. From the balanced equation the following information can be obtained.
P4(s) Cl2(g)  PCl3(s)

11. U try it!
2Na Cl2  2NaCl
Moles?
Grams?
Liters?

12. U try it!
2Na Cl2  2NaCl
Moles?
Grams?
Liters?

13. Mole ratios The ratio of moles given by the balanced equation.
N F2  2NF3
For every 1 mole of N2 there are 2 moles of NF3 formed (assuming that there is at least 3 F2)
Mole Ratios: N2:NF3 is 1 to 2
F2:NF3 is 3 to 2

14. Mole to Mole calculations How many moles of ozone O3 will be formed from 6 moles of oxygen O2?

15. O2  O3
Step 1 balance the equation.

16. How many moles of ozone O3 will be formed from 6 moles of oxygen O2?
Step 2 Identify what the question is asking… Goal?
List Known’s and Unknown’s

17. How many moles of ozone O3 will be formed from 6 moles of oxygen O2?
Step 3 Use dimensional analysis to answer solve the problem

18. How many moles of ozone O3 will be formed from 6 moles of oxygen O2?
Check your answer to see if it is logical.

19. Can you make the six mole ratios? 4Al + 3O2  2Al2O3

20. How many moles of aluminum and oxygen are needed to form 3
How many moles of aluminum and oxygen are needed to form moles of aluminum oxide? 4Al O2  2Al2O3

21. How many moles of chlorine are needed to make 15 moles of NaCl?

24. C + O2  CO2 1 C atom reacts with 1 O2 molecule to form 1 CO2 molecule
12 C atoms reacts with 12 O2 molecules to form 12 CO2 molecules
1 mol C atoms reacts with 1 mol O2 molecules to form 1 mol CO2 molecules
What do you need to make 12 mol CO2?

25. 12.2 Chemical calculations
Start here!

26. 12.2 Chemical calculations

27. 12.2 Chemical calculations
1 mole =
6.02 x representative particles =
molar mass (grams) =
22.4L (gases only)

28. Mole ratios
2 moles of O3 form 3 moles of O2
2 O3  3 O2

29. (Gram, molecules, particles, atoms)
Remember ALWAYS convert to moles!
Then use mole ratio.

30. How many grams of water can be formed from 15g of hydrogen
How many grams of water can be formed from 15g of hydrogen? (assume there is unlimited oxygen)
2H2 + O2  2H2O
g mol hydrogen
Then, mole ratio to find water
then convert moles of water  grams

31. 2H2 + O2  2H2O

32. How many H2 molecules are needed to make 50g of water
How many H2 molecules are needed to make 50g of water? (assume there is unlimited oxygen)
2H2 + O2  2H2O

33. 50g of water 2H2 + O2  2H2O g H2O  moles H2O Moles H2O  moles H2
Moles H2  molecules of H2

34. Greenhouse gases
North America, consists of the United States and Canada. North America is the highest fossil-fuel, CO2 emitting region of the world with 1.73 billion tons of carbon in This 2002 total is an all-time high for North America and represents a 1.4% increase from Because ~92% of current fossil-fuel CO2 emissions from the region are from the United States, the North America data closely resembles that for the United States.

35. How many L of CO2(g) will be formed from 16 gallons of gasoline (64,000g)? (assume gas is 100% octane)
2C8H O2  16CO H2O

36. 197,614g = 2.0 x 105
100,000L of CO2 made for each 16 gal of gas burned.

37. 12.5 g Li  g product O2
Li + O2  Li2O S
Li + S  Li2S

38. 12.5 g Li  Predict g product O2
Li + O2  Li2O S
Li + S  Li2S

39. 12.5 g Li  Predict g product Step 1, Balance
Li + O2  Li2O
4Li + 2O2  2Li2O S
Li + S  Li2S
2Li + S  Li2S

40. Use last problem to intro 12.3

41. 12.5 g Li  g product What is your a.)Theoretical Yield
b.) Actual Yield c.) Percent Yield
Li + O2  Li2O
Previous Ans: You calculate 26.9 g Li2O
You measure the product and there is 25 grams of Li2O
Li + S  Li2S
Previous Ans: You calculate 41.4 g Li2S
You measure the product and there is 37.0 grams of Li2S

42. 12.5 g Li  g product Li + O2  Li2O a.)Theoretical Yield 27.0 g Li2O
b.) Actual Yield 25 g Li2O
c.) Percent Yield 25/26.9 x100=92.9%
Li + S  Li2S
a.)Theoretical Yield 41.4 g Li2S
b.) Actual Yield 37.0 g Li2S
c.) Percent Yield 37.0/41.4 x100=89.4%

43. Actual Yield = MEASURED amount (recorded by experiment)
Theoretical Yield = CALCULATED amount
(What balance equation says we should have produced)
Percent Yield is ratio of GRAMS!

44. 12.3 limiting reagents
limiting reagent – reactant that will be used up first and cause the reaction to stop producing products

45. Identify the limiting reagent
Example Problem (solved on next slide)
2Na Cl2  2NaCl
Givens are starting amounts of each reagent
Which is the limiting reactant?
STEPS to find limiting reagent (Balance equation.)
1.) Calculate amount of product produced by each reagent.
2.) Limiting reagent is the one that produces the least amount of product.
3.) Excess reagent is the leftover amounts of the other reagent

46. Identify the limiting reagent
2Na Cl2  NaCl
1 mol Na reacts with 1 mol Cl2?
Which is the limiting reactant?

47. Identify the excess reagent
2Na Cl2  NaCl
1 mol Na reacts with 1 mol Cl2?
How much of excess reagent is there?

48. What is the actual equation?
1 Na + 1 Cl2  1 NaCl + ½ Cl2
Limiting Excess
Reagent Reagent

49. Identify the limiting reagent
N O2  NO3
1.7 mol N2 or 1.3 mol O2

50. Identify the excess reagent.
N O2  NO3
1.7 mol N2 or 1.3 mol O2

51. 58g of Na are reacted with 110g of S how much product will be formed
58g of Na are reacted with 110g of S how much product will be formed? 2Na S  Na2S Discuss steps

52. What is the percent yield if 170g of sodium sulfide was produced
What is the percent yield if 170g of sodium sulfide was produced? (see previous problem)
Because of human error, measurement error, contaminated reactants, experimental error, ect… there will usually be less than 100% yield, meaning that less products will be produced then you calculated for.

53. 15. 5g of H2 is reacted with 155g of O2
15.5g of H2 is reacted with 155g of O2. What is the percent yield if 136g of H2O has been collected? 2H2 + O2  2H2O

54. ANSWER: 15. 5g of H2 is reacted with 155g of O2
ANSWER: 15.5g of H2 is reacted with 155g of O2. What is the percent yield if 136g of H2O has been collected? 2H2 + O2  2H2O 97.1%

55. SUMMARY
Write the balanced equation.
Convert variables to moles.
Find the moles of each reactant needed based on the amount of the other reactant given (use Na to find S).
Identify the limiting reagent.
Solve for the amounts of reactants needed and products formed.