1. Pressure in Fluid Systems

2. Unit 3 Pressure Pages 43-60  Fluid  Hydraulic System  Pneumatic System  Density  Specific gravity  Buoyant force  Hydrometer  Pressure  PSI  Atmospheric Pressure  Absolute pressure  Gage pressure  Manometer

3. Pressure in a Fluid System  Unit 3 Review  Page 53  #1-15

4. Fluid  Gas or liquid that conforms to the shape of the container  “Anything that flows”

5. Hydraulic system  Uses liquid as the fluid Pneumatic system  Uses air or gas as the fluid

6. Why does a hot air balloon float? Why does motor oil rise to the top of water? Density  Amount of matter in a given amount of substance  = Mass/Volume

7. Density  SI measured in:  Kg/m 3 or gm/cm 3  English measured in:  Lbm/ft 3 or lb/ft 3

8. Density  What is the density of gold if you have a 1.036cm 3 piece that had a mass of 20grams?  D=m/v  D=20g/1.036cm 3  D=19.3g/cm 3

9. Density  What is the density of gold if you have a 3.108cm 3 piece that had a mass of 60grams?  D=m/v  D=60g/3.108cm 3  D=19.3g/cm 3

11. Other Densities  Platinum  Diamond  Chromium  Tin (white)  Tin (gray)  21.45  3.5-3.53  7.15  7.265  5.769

12. Density  What is the mass in grams of mercury with a volume of 1cm 3 ?  D = m / v  13.6 g/cm 3 = x / 1cm 3  13.6 g = x

13. Density  What is the mass in kilograms of balsa wood with a volume of 1m 3 ? .3g / cm 3 = x / 1,000,000cm 3  300,000 g = x  300 kg =x  1m 3 = __cm 3  1m 3 = 100cm x 100cm x 100cm  = 1,000,000 cm 3  D = m / v .3g / cm 3 = x / 1m 3

14. Specific Gravity  Density of a substance divided by the density of water  Because specific gravity is density/density the units cancel out and is written as a whole number

15. Specific Gravity  Copper has a density of 8.9g/cm 3  What is its specific gravity?  Specific Gravity = density of substance  = density of water  S.G. = (8.9g/cm 3 ) / (1.0g/cm 3 )  S.G. = 8.9

17. Buoyant Force  The upward force on a substance from a fluid  Will lead sink or float in water?  Will it sink or float in mercury?

19. Hydrometer  Instrument that measures density or specific gravity of fluids  Can you drown in quick sand?

20. Pressure  Force per unit area exerted by a fluid

21. Force on Airplane Windows  An airplane window has a surface area of 136 square inches.  Air pressure inside the cabin is 12.3 lb/in 2  The force pushing on the window

22. Pressure  What happens to the pressure as we move away from the earth?  http://www.sciencedaily.com/videos/2006/1201- home_runs_amp_holeinone.htm http://www.sciencedaily.com/videos/2006/1201- home_runs_amp_holeinone.htm

23. Force on Airplane Windows  An airplane window has a surface area of 144 square inches.  Air pressure inside the cabin is 14.7 lb/in 2  Air pressure outside the window is 6.7 lb/in 2  The force pushing on the window  The force pushing out on the window  Net force on window

24. Inward force on window  F = P x A  F = (14.7lb/in 2 )(144in 2 )  F = 2116.8 lb  F = P x A  F = (6.7 lb/in 2 )(144in 2 )  F= 964.8lb Outward force on window

25. Net Force on window  The window is being pushed outward with a net force of 1152 lb.  Net Force = Force out – Force in  Net Force = 2116.8 lb – 964.8 lb  Net Force = 1152 lb

26. Net Force on window  If the plane rises to a higher altitude and the pressure outside the plane changes to 5.4 lb/in 2  How much stronger will the windows need to be in order to hold the pressure

27. Inward force on window  F = P x A  F = (14.7lb/in 2 )(144in 2 )  F = 2116.8 lb  F = P x A  F = (5.4 lb/in 2 )(144in 2 )  F= 777.6lb Outward force on window

28. Net Force on window  The window was originally pushing outward with a net force of 1152 lb.  Therefore it needs to hold 187.2 more pounds of pressure (1339.2 – 1152)  Net Force = Force out – Force in  Net Force = 2116.8 lb – 777.6 lb  Net Force = 1339.2 lb

29. Pressure  Pressure acts equally in all direction at any point in a fluid and therefore it is a scalar

30. Absolute vs. Gage Pressure  When we fill a tire to 30lb/in 2 is that the absolute or the gage pressure?  Atmospheric pressure = 14.7 lb/in 2

31. Absolute Pressure  Total pressure compared to a perfect vacuum Gage Pressure  Pressure measured above atmospheric pressure G.P = Total pressure – atmospheric pressure

32. Total Pressure  Gage pressure is generally measured “with a gage”

33. Pressure  Tire gage reads 30lb/in 2  What is the atmospheric pressure?  What is the gage pressure?  What is the total pressure?

34. Pressure  Tire gage reads 30lb/in 2  What is the atmospheric pressure?  What is the gage pressure?  What is the total pressure?

35. How does pressure change with depth?  Where is the pressure greater the shallow end or the deep end?  Why?

36. Pressure increases with depth  There is more water sitting on top of the deep end  There is twice as much weight  Twice as much force  Twice as much pressure

37. Relationship between pressure and depth

38. Water Pressure Calculation  Given:  The height of the water in a storage tank is 100 ft above the valve. The weight density of water is 62.4 lb/ft 3  Find:  The pressure at the valve in lb/ft 2

39. Water Pressure Calculation  P = pw x h  P = (62.4 lb/ft3)(100ft)  P = 6240 lb/ft 2  Given: 1 ft 2 = 144 in 2  Now find:  Pressure in PSI

40. Water Pressure Calculation  P = pw x h  P = (62.4 lb/ft3)(100ft)  P = 6240 lb/ft 2  Given: 1 ft 2 = 144 in 2  p = (6240 lb/ft 2 )(1ft2/144in 2 ) P = 43.3 lb/in 2 (psi)

41. Hydraulic lift  Liquids are incompressible  Air compressor increases the pressure to the fluid  Large pushing force is exerted on the lifting piston

42. Pressure acts like forces  Pressure is a prime mover Measuring Pressures  Manometer – instrument used to measure fluid pressure

43. Balanced pressure across the valve

44. Unbalanced pressure across the valve

45. Pressure on bottom does not depend on the size of the tank

46. Hydraulic jack?  Large cylinder to a small cylinder  Same pressure = more force in the smaller cylinder  Small to large = allowable force but small increments?